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Theorem 3mix1 600
Description: Introduction in triple disjunction.
Assertion
Ref Expression
3mix1 |- (ph -> (ph \/ ps \/ ch))

Proof of Theorem 3mix1
StepHypRef Expression
1 orc 225 . 2 |- (ph -> (ph \/ (ps \/ ch)))
2 3orass 584 . 2 |- ((ph \/ ps \/ ch) <-> (ph \/ (ps \/ ch)))
31, 2sylibr 175 1 |- (ph -> (ph \/ ps \/ ch))
Colors of variables: wff set class
Syntax hints:   -> wi 2   \/ wo 195   \/ w3o 580
This theorem is referenced by:  3mix2 601  3mix3 602  tz7.44-1 2966
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6
This theorem depends on definitions:  df-bi 128  df-or 197  df-3or 582
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