Theorem annim 206

Description: Express conjunction in terms of implication.

Assertion

Ref	Expression
annim	|- ((ph /\ -. ps) <-> -. (ph -> ps))

Proof of Theorem annim

Step	Hyp	Ref	Expression
1		iman 205	. 2 |- ((ph -> ps) <-> -. (ph /\ -. ps))
2	1	bicon2i 194	1 |- ((ph /\ -. ps) <-> -. (ph -> ps))

Syntax hints:  -. wn 1   -> wi 2   <-> wb 127   /\ wa 196

This theorem is referenced by:  pm5.18 497  19.35 754  r19.35 1298  nss 1550  difin0ss 1753  nssss 1866  findsg 2398  tfindsg 2402  strlem6 5697

This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6

This theorem depends on definitions:  df-bi 128  df-an 198

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