Theorem eqt 814

Description: A transitive law for equality.

Assertion

Ref	Expression
eqt	|- (x = y -> (y = z -> x = z))

Proof of Theorem eqt

Step	Hyp	Ref	Expression
1		ax-8 798	. 2 |- (y = x -> (y = z -> x = z))
2	1	eqcoms 813	1 |- (x = y -> (y = z -> x = z))

Syntax hints:   -> wi 2   = weq 797

This theorem is referenced by:  eqt2 815  eqan 816  a8b 817  eqvin.l2 931  zfaus 1480

This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-gen 677  ax-8 798  ax-9 799  ax-12 802

This theorem depends on definitions:  df-bi 128  df-an 198  df-ex 679

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