Theorem funfn 2689

Description: An equivalence for the function predicate.

Assertion

Ref	Expression
funfn	|- (Fun A <-> A Fn dom A)

Proof of Theorem funfn

Step	Hyp	Ref	Expression
1		cleqid 1102	. . 3 |- dom A = dom A
2	1	biantru 543	. 2 |- (Fun A <-> (Fun A /\ dom A = dom A))
3		df-fn 2433	. 2 |- (A Fn dom A <-> (Fun A /\ dom A = dom A))
4	2, 3	bitr4 154	1 |- (Fun A <-> A Fn dom A)

Syntax hints:   <-> wb 127   /\ wa 196   = wceq 1091  dom cdm 2410  Fun wfun 2416   Fn wfn 2417

This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-gen 677  ax-ext 1074

This theorem depends on definitions:  df-bi 128  df-an 198  df-cleq 1097  df-fn 2433

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