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Theorem nan 514
Description: Theorem to move a conjunct in and out of a negation.
Assertion
Ref Expression
nan |- ((ph -> -. (ps /\ ch)) <-> ((ph /\ ps) -> -. ch))

Proof of Theorem nan
StepHypRef Expression
1 impexp 276 . 2 |- (((ph /\ ps) -> -. ch) <-> (ph -> (ps -> -. ch)))
2 imnan 207 . . 3 |- ((ps -> -. ch) <-> -. (ps /\ ch))
32imbi2i 160 . 2 |- ((ph -> (ps -> -. ch)) <-> (ph -> -. (ps /\ ch)))
41, 3bitr2 152 1 |- ((ph -> -. (ps /\ ch)) <-> ((ph /\ ps) -> -. ch))
Colors of variables: wff set class
Syntax hints:  -. wn 1   -> wi 2   <-> wb 127   /\ wa 196
This theorem is referenced by:  cfsuc 3709
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6
This theorem depends on definitions:  df-bi 128  df-an 198
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