Theorem opreqan12rd 3016

Description: Equality deduction for operations.

Hypotheses

Ref	Expression
opreq1d.1	|- (ph -> A = B)
opreqan12i.2	|- (ps -> C = D)

Assertion

Ref	Expression
opreqan12rd	|- ((ps /\ ph) -> (AFC) = (BFD))

Proof of Theorem opreqan12rd

Step	Hyp	Ref	Expression
1		opreq1d.1	. . 3 |- (ph -> A = B)
2		opreqan12i.2	. . 3 |- (ps -> C = D)
3	1, 2	opreqan12d 3015	. 2 |- ((ph /\ ps) -> (AFC) = (BFD))
4	3	ancoms 334	1 |- ((ps /\ ph) -> (AFC) = (BFD))

Syntax hints:   -> wi 2   /\ wa 196   = wceq 1091  (class class class)co 3001

This theorem is referenced by:  mulgt0sr 4008  mulcnsr 4048  mulresr 4051  recdivt 4270

This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-13 804  ax-14 805  ax-16 922  ax-17 925  ax-ext 1074  ax-rep 1075  ax-pow 1077

This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-dif 1489  df-un 1490  df-in 1491  df-ss 1492  df-nul 1708  df-pw 1799  df-sn 1811  df-pr 1812  df-op 1815  df-uni 1920  df-br 2063  df-opab 2098  df-xp 2424  df-cnv 2426  df-dm 2428  df-rn 2429  df-res 2430  df-ima 2431  df-fv 2438  df-opr 3003

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