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Theorem preq12b 1874
Description: Equality relationship for two unordered pairs.
Hypotheses
Ref Expression
preq12b.1 |- A e. V
preq12b.2 |- B e. V
preq12b.3 |- C e. V
preq12b.4 |- D e. V
Assertion
Ref Expression
preq12b |- ({A, B} = {C, D} <-> ((A = C /\ B = D) \/ (A = D /\ B = C)))

Proof of Theorem preq12b
StepHypRef Expression
1 preq12b.1 . . . . . 6 |- A e. V
21pri1 1841 . . . . 5 |- A e. {A, B}
3 eleq2 1150 . . . . 5 |- ({A, B} = {C, D} -> (A e. {A, B} <-> A e. {C, D}))
42, 3mpbii 168 . . . 4 |- ({A, B} = {C, D} -> A e. {C, D})
51elpr 1823 . . . 4 |- (A e. {C, D} <-> (A = C \/ A = D))
64, 5sylib 173 . . 3 |- ({A, B} = {C, D} -> (A = C \/ A = D))
7 preq1 1870 . . . . . . . 8 |- (A = C -> {A, B} = {C, B})
87cleq1d 1109 . . . . . . 7 |- (A = C -> ({A, B} = {C, D} <-> {C, B} = {C, D}))
9 preq12b.2 . . . . . . . 8 |- B e. V
10 preq12b.4 . . . . . . . 8 |- D e. V
119, 10prer2 1873 . . . . . . 7 |- ({C, B} = {C, D} -> B = D)
128, 11syl6bi 187 . . . . . 6 |- (A = C -> ({A, B} = {C, D} -> B = D))
1312com12 13 . . . . 5 |- ({A, B} = {C, D} -> (A = C -> B = D))
1413ancld 246 . . . 4 |- ({A, B} = {C, D} -> (A = C -> (A = C /\ B = D)))
15 prcom 1840 . . . . . . 7 |- {C, D} = {D, C}
1615cleq2i 1111 . . . . . 6 |- ({A, B} = {C, D} <-> {A, B} = {D, C})
17 preq1 1870 . . . . . . . . 9 |- (A = D -> {A, B} = {D, B})
1817cleq1d 1109 . . . . . . . 8 |- (A = D -> ({A, B} = {D, C} <-> {D, B} = {D, C}))
19 preq12b.3 . . . . . . . . 9 |- C e. V
209, 19prer2 1873 . . . . . . . 8 |- ({D, B} = {D, C} -> B = C)
2118, 20syl6bi 187 . . . . . . 7 |- (A = D -> ({A, B} = {D, C} -> B = C))
2221com12 13 . . . . . 6 |- ({A, B} = {D, C} -> (A = D -> B = C))
2316, 22sylbi 174 . . . . 5 |- ({A, B} = {C, D} -> (A = D -> B = C))
2423ancld 246 . . . 4 |- ({A, B} = {C, D} -> (A = D -> (A = D /\ B = C)))
2514, 24orim12d 436 . . 3 |- ({A, B} = {C, D} -> ((A = C \/ A = D) -> ((A = C /\ B = D) \/ (A = D /\ B = C))))
266, 25mpd 46 . 2 |- ({A, B} = {C, D} -> ((A = C /\ B = D) \/ (A = D /\ B = C)))
27 preq2 1871 . . . 4 |- (B = D -> {C, B} = {C, D})
287, 27sylan9eq 1144 . . 3 |- ((A = C /\ B = D) -> {A, B} = {C, D})
29 prcom 1840 . . . . 5 |- {D, B} = {B, D}
3017, 29syl6eq 1140 . . . 4 |- (A = D -> {A, B} = {B, D})
31 preq1 1870 . . . 4 |- (B = C -> {B, D} = {C, D})
3230, 31sylan9eq 1144 . . 3 |- ((A = D /\ B = C) -> {A, B} = {C, D})
3328, 32jaoi 275 . 2 |- (((A = C /\ B = D) \/ (A = D /\ B = C)) -> {A, B} = {C, D})
3426, 33impbi 139 1 |- ({A, B} = {C, D} <-> ((A = C /\ B = D) \/ (A = D /\ B = C)))
Colors of variables: wff set class
Syntax hints:   -> wi 2   <-> wb 127   \/ wo 195   /\ wa 196   = wceq 1091   e. wcel 1092  Vcvv 1348  {cpr 1809
This theorem is referenced by:  prel12 1875  preleq 3454
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-un 1490  df-sn 1811  df-pr 1812
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