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Theorem 19.29 752
Description: Theorem 19.29 of [Margaris] p. 90.
Assertion
Ref Expression
19.29 ((∀xφ ∧ ∃xψ) → ∃x(φψ))

Proof of Theorem 19.29
StepHypRef Expression
1 19.20 690 . . . . 5 (∀x(φ → ¬ ψ) → (∀xφ → ∀x ¬ ψ))
2 alnex 716 . . . . 5 (∀x ¬ ψ ↔ ¬ ∃xψ)
31, 2syl6ib 185 . . . 4 (∀x(φ → ¬ ψ) → (∀xφ → ¬ ∃xψ))
43con3i 90 . . 3 (¬ (∀xφ → ¬ ∃xψ) → ¬ ∀x(φ → ¬ ψ))
5 df-an 198 . . 3 ((∀xφ ∧ ∃xψ) ↔ ¬ (∀xφ → ¬ ∃xψ))
6 exnal 721 . . 3 (∃x ¬ (φ → ¬ ψ) ↔ ¬ ∀x(φ → ¬ ψ))
74, 5, 63imtr4 192 . 2 ((∀xφ ∧ ∃xψ) → ∃x ¬ (φ → ¬ ψ))
8 df-an 198 . . 3 ((φψ) ↔ ¬ (φ → ¬ ψ))
98biex 733 . 2 (∃x(φψ) ↔ ∃x ¬ (φ → ¬ ψ))
107, 9sylibr 175 1 ((∀xφ ∧ ∃xψ) → ∃x(φψ))
Colors of variables: wff set class
Syntax hints:  ¬ wn 1   → wi 2   ∧ wa 196  ∀wal 672  ∃wex 678
This theorem is referenced by:  19.29r 753  exan 784  r19.29 1295
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-gen 677
This theorem depends on definitions:  df-bi 128  df-an 198  df-ex 679
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