Proof of Theorem a16g
| Step | Hyp | Ref
| Expression |
| 1 | | eq5 824 |
. . 3
⊢ (∀x x = y → ∀z∀x
x = y) |
| 2 | | ax9a 808 |
. . . . 5
⊢ ¬ ∀x ¬ x =
z |
| 3 | | ax-16 922 |
. . . . 5
⊢ (∀x x = y → (¬ x = z →
∀x ¬ x = z)) |
| 4 | 2, 3 | mt3i 100 |
. . . 4
⊢ (∀x x = y → x =
z) |
| 5 | | eqcom 811 |
. . . 4
⊢ (x =
z → z = x) |
| 6 | 4, 5 | syl 12 |
. . 3
⊢ (∀x x = y → z =
x) |
| 7 | 1, 6 | 19.21ai 740 |
. 2
⊢ (∀x x = y → ∀z z = x) |
| 8 | | ax-16 922 |
. . 3
⊢ (∀x x = y → (φ
→ ∀xφ)) |
| 9 | | idd 11 |
. . . 4
⊢ (∀z z = x → (φ
→ φ)) |
| 10 | 9 | del35 836 |
. . 3
⊢ (∀z z = x → (∀xφ →
∀zφ)) |
| 11 | 8, 10 | syl9r 56 |
. 2
⊢ (∀z z = x → (∀x x = y → (φ
→ ∀zφ))) |
| 12 | 7, 11 | mpcom 49 |
1
⊢ (∀x x = y → (φ
→ ∀zφ)) |