| Metamath Proof Explorer |
< Previous
Next >
Related theorems GIF version |
| Description: Axiom of Choice using abbreviations. This cute and very short version does not make use of any defined objects such as the empty set or a function value. However, it is hard to explain intuitively. If you want to figure it out, the rewritten equivalent ac3 3568 is easier to understand. Note: aceq0 3553 shows the logical equivalence to ax-ac 1080. |
| Ref | Expression |
|---|---|
| ac2 | ⊢ ∃y∀z ∈ x ∀w ∈ z ∃!v ∈ z ∃u ∈ y (z ∈ u ∧ v ∈ u) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ax-ac 1080 | . 2 ⊢ ∃y∀z∀w((z ∈ w ∧ w ∈ x) → ∃v∀u(∃t((u ∈ w ∧ w ∈ t) ∧ (u ∈ t ∧ t ∈ y)) ↔ u = v)) | |
| 2 | aceq0 3553 | . 2 ⊢ (∃y∀z ∈ x ∀w ∈ z ∃!v ∈ z ∃u ∈ y (z ∈ u ∧ v ∈ u) ↔ ∃y∀z∀w((z ∈ w ∧ w ∈ x) → ∃v∀u(∃t((u ∈ w ∧ w ∈ t) ∧ (u ∈ t ∧ t ∈ y)) ↔ u = v))) | |
| 3 | 1, 2 | mpbir 165 | 1 ⊢ ∃y∀z ∈ x ∀w ∈ z ∃!v ∈ z ∃u ∈ y (z ∈ u ∧ v ∈ u) |
| Colors of variables: wff set class |
| Syntax hints: → wi 2 ↔ wb 127 ∧ wa 196 ∀wal 672 ∃wex 678 = weq 797 ∈ wel 803 ∀wral 1201 ∃wrex 1202 ∃!wreu 1203 |
| This theorem is referenced by: ac3 3568 ac7 3569 |
| This theorem was proved from axioms: ax-1 3 ax-2 4 ax-3 5 ax-mp 6 ax-4 673 ax-5 674 ax-6 675 ax-7 676 ax-gen 677 ax-8 798 ax-9 799 ax-10 800 ax-11 801 ax-12 802 ax-13 804 ax-14 805 ax-17 925 ax-ext 1074 ax-ac 1080 |
| This theorem depends on definitions: df-bi 128 df-or 197 df-an 198 df-ex 679 df-sb 853 df-eu 1009 df-cleq 1097 df-clel 1099 df-ral 1205 df-rex 1206 df-reu 1207 |