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Theorem ac2 3567
Description: Axiom of Choice using abbreviations. This cute and very short version does not make use of any defined objects such as the empty set or a function value. However, it is hard to explain intuitively. If you want to figure it out, the rewritten equivalent ac3 3568 is easier to understand. Note: aceq0 3553 shows the logical equivalence to ax-ac 1080.
Assertion
Ref Expression
ac2 yzxwz ∃!vzuy (zuvu)
Distinct variable group(s):   x,y,z,w,v,u

Proof of Theorem ac2
StepHypRef Expression
1 ax-ac 1080 . 2 yzw((zwwx) → ∃vu(∃t((uwwt) ∧ (utty)) ↔ u = v))
2 aceq0 3553 . 2 (∃yzxwz ∃!vzuy (zuvu) ↔ ∃yzw((zwwx) → ∃vu(∃t((uwwt) ∧ (utty)) ↔ u = v)))
31, 2mpbir 165 1 yzxwz ∃!vzuy (zuvu)
Colors of variables: wff set class
Syntax hints:   → wi 2   ↔ wb 127   ∧ wa 196  ∀wal 672  ∃wex 678   = weq 797   ∈ wel 803  ∀wral 1201  ∃wrex 1202  ∃!wreu 1203
This theorem is referenced by:  ac3 3568  ac7 3569
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-13 804  ax-14 805  ax-17 925  ax-ext 1074  ax-ac 1080
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-eu 1009  df-cleq 1097  df-clel 1099  df-ral 1205  df-rex 1206  df-reu 1207
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