Proof of Theorem brinxp
| Step | Hyp | Ref
| Expression |
| 1 | | ibar 487 |
. 2
⊢ ((A
∈ C ∧ B ∈ D)
→ (ARB ↔
((A ∈ C ∧ B ∈
D) ∧ ARB))) |
| 2 | | opelxpi 2455 |
. . . . 5
⊢ ((A
∈ C ∧ B ∈ D)
→ 〈A, B〉 ∈ (C × D)) |
| 3 | | ibib 448 |
. . . . 5
⊢ (((A
∈ C ∧ B ∈ D)
→ 〈A, B〉 ∈ (C × D))
↔ ((A ∈ C ∧ B ∈
D) → ((A ∈ C ∧
B ∈ D) ↔ 〈A, B〉
∈ (C × D)))) |
| 4 | 2, 3 | mpbi 164 |
. . . 4
⊢ ((A
∈ C ∧ B ∈ D)
→ ((A ∈ C ∧ B ∈
D) ↔ 〈A, B〉
∈ (C × D))) |
| 5 | | df-br 2063 |
. . . . 5
⊢ (ARB ↔ 〈A, B〉
∈ R) |
| 6 | 5 | a1i 7 |
. . . 4
⊢ ((A
∈ C ∧ B ∈ D)
→ (ARB ↔
〈A, B〉 ∈ R)) |
| 7 | 4, 6 | anbi12d 476 |
. . 3
⊢ ((A
∈ C ∧ B ∈ D)
→ (((A ∈ C ∧ B ∈
D) ∧ ARB) ↔ (〈A, B〉
∈ (C × D) ∧ 〈A, B〉
∈ R))) |
| 8 | | df-br 2063 |
. . . 4
⊢ (A(R ∩
(C × D))B ↔
〈A, B〉 ∈ (R ∩ (C
× D))) |
| 9 | | elin 1635 |
. . . 4
⊢ (〈A, B〉
∈ (R ∩ (C × D))
↔ (〈A, B〉 ∈ R
∧ 〈A, B〉 ∈ (C × D))) |
| 10 | | ancom 333 |
. . . 4
⊢ ((〈A, B〉
∈ R ∧ 〈A, B〉
∈ (C × D)) ↔ (〈A, B〉
∈ (C × D) ∧ 〈A, B〉
∈ R)) |
| 11 | 8, 9, 10 | 3bitr 155 |
. . 3
⊢ (A(R ∩
(C × D))B ↔
(〈A, B〉 ∈ (C × D)
∧ 〈A, B〉 ∈ R)) |
| 12 | 7, 11 | syl6bbr 416 |
. 2
⊢ ((A
∈ C ∧ B ∈ D)
→ (((A ∈ C ∧ B ∈
D) ∧ ARB) ↔ A(R ∩
(C × D))B)) |
| 13 | 1, 12 | bitrd 406 |
1
⊢ ((A
∈ C ∧ B ∈ D)
→ (ARB ↔
A(R
∩ (C × D))B)) |