Proof of Theorem caoprdistr
| Step | Hyp | Ref
| Expression |
| 1 | | caoprdistr.1 |
. 2
⊢ A
∈ V |
| 2 | | caoprdistr.2 |
. 2
⊢ B
∈ V |
| 3 | | caoprdistr.3 |
. 2
⊢ C
∈ V |
| 4 | | opreq1 3006 |
. . . 4
⊢ (x =
A → (xG(yFz)) = (AG(yFz))) |
| 5 | | opreq1 3006 |
. . . . 5
⊢ (x =
A → (xGy) = (AGy)) |
| 6 | | opreq1 3006 |
. . . . 5
⊢ (x =
A → (xGz) = (AGz)) |
| 7 | 5, 6 | opreq12d 3014 |
. . . 4
⊢ (x =
A → ((xGy)F(xGz)) = ((AGy)F(AGz))) |
| 8 | 4, 7 | cleq12d 1115 |
. . 3
⊢ (x =
A → ((xG(yFz)) = ((xGy)F(xGz)) ↔ (AG(yFz)) = ((AGy)F(AGz)))) |
| 9 | | opreq1 3006 |
. . . . 5
⊢ (y =
B → (yFz) = (BFz)) |
| 10 | 9 | opreq2d 3013 |
. . . 4
⊢ (y =
B → (AG(yFz)) = (AG(BFz))) |
| 11 | | opreq2 3007 |
. . . . 5
⊢ (y =
B → (AGy) = (AGB)) |
| 12 | 11 | opreq1d 3012 |
. . . 4
⊢ (y =
B → ((AGy)F(AGz)) = ((AGB)F(AGz))) |
| 13 | 10, 12 | cleq12d 1115 |
. . 3
⊢ (y =
B → ((AG(yFz)) = ((AGy)F(AGz)) ↔ (AG(BFz)) = ((AGB)F(AGz)))) |
| 14 | | opreq2 3007 |
. . . . 5
⊢ (z =
C → (BFz) = (BFC)) |
| 15 | 14 | opreq2d 3013 |
. . . 4
⊢ (z =
C → (AG(BFz)) = (AG(BFC))) |
| 16 | | opreq2 3007 |
. . . . 5
⊢ (z =
C → (AGz) = (AGC)) |
| 17 | 16 | opreq2d 3013 |
. . . 4
⊢ (z =
C → ((AGB)F(AGz)) = ((AGB)F(AGC))) |
| 18 | 15, 17 | cleq12d 1115 |
. . 3
⊢ (z =
C → ((AG(BFz)) = ((AGB)F(AGz)) ↔ (AG(BFC)) = ((AGB)F(AGC)))) |
| 19 | 8, 13, 18 | syl3an9b 634 |
. 2
⊢ ((x =
A ∧ y = B ∧
z = C)
→ ((xG(yFz)) =
((xGy)F(xGz)) ↔
(AG(BFC)) =
((AGB)F(AGC)))) |
| 20 | | caoprdistr.4 |
. 2
⊢ (xG(yFz)) = ((xGy)F(xGz)) |
| 21 | 1, 2, 3, 19, 20 | vtocl3 1380 |
1
⊢ (AG(BFC)) = ((AGB)F(AGC)) |