Proof of Theorem cdaen
| Step | Hyp | Ref
| Expression |
| 1 | | 0ne1oOLD 3113 |
. . . . . 6
⊢ ¬ ∅ =
1o |
| 2 | | xpsndisj 2655 |
. . . . . 6
⊢ (¬ ∅ = 1o
→ ((A × {∅}) ∩
(C × {1o})) =
∅) |
| 3 | 1, 2 | ax-mp 6 |
. . . . 5
⊢ ((A
× {∅}) ∩ (C ×
{1o})) = ∅ |
| 4 | | xpsndisj 2655 |
. . . . . 6
⊢ (¬ ∅ = 1o
→ ((B × {∅}) ∩
(D × {1o})) =
∅) |
| 5 | 1, 4 | ax-mp 6 |
. . . . 5
⊢ ((B
× {∅}) ∩ (D ×
{1o})) = ∅ |
| 6 | 3, 5 | pm3.2i 234 |
. . . 4
⊢ (((A
× {∅}) ∩ (C ×
{1o})) = ∅ ∧ ((B × {∅}) ∩ (D × {1o})) =
∅) |
| 7 | | unen 3338 |
. . . 4
⊢ ((((A
× {∅}) ≈ (B ×
{∅}) ∧ (C ×
{1o}) ≈ (D ×
{1o})) ∧ (((A ×
{∅}) ∩ (C ×
{1o})) = ∅ ∧ ((B × {∅}) ∩ (D × {1o})) = ∅))
→ ((A × {∅}) ∪
(C × {1o})) ≈
((B × {∅}) ∪ (D × {1o}))) |
| 8 | 6, 7 | mpan2 519 |
. . 3
⊢ (((A
× {∅}) ≈ (B ×
{∅}) ∧ (C ×
{1o}) ≈ (D ×
{1o})) → ((A ×
{∅}) ∪ (C ×
{1o})) ≈ ((B
× {∅}) ∪ (D ×
{1o}))) |
| 9 | | cdaen.1 |
. . . . 5
⊢ A
∈ V |
| 10 | | 0ex 1745 |
. . . . . 6
⊢ ∅ ∈ V |
| 11 | 9, 10 | xpsnen 3339 |
. . . . 5
⊢ (A
× {∅}) ≈ A |
| 12 | | enen1 3375 |
. . . . 5
⊢ ((A
∈ V ∧ (A × {∅})
≈ A) → ((A × {∅}) ≈ (B × {∅}) ↔ A ≈ (B
× {∅}))) |
| 13 | 9, 11, 12 | mp2an 520 |
. . . 4
⊢ ((A
× {∅}) ≈ (B ×
{∅}) ↔ A ≈ (B × {∅})) |
| 14 | | cdaen.2 |
. . . . 5
⊢ B
∈ V |
| 15 | 14, 10 | xpsnen 3339 |
. . . . 5
⊢ (B
× {∅}) ≈ B |
| 16 | | enen2 3376 |
. . . . 5
⊢ ((B
∈ V ∧ (B × {∅})
≈ B) → (A ≈ (B
× {∅}) ↔ A ≈
B)) |
| 17 | 14, 15, 16 | mp2an 520 |
. . . 4
⊢ (A
≈ (B × {∅}) ↔
A ≈ B) |
| 18 | 13, 17 | bitr 151 |
. . 3
⊢ ((A
× {∅}) ≈ (B ×
{∅}) ↔ A ≈ B) |
| 19 | | cdaen.3 |
. . . . 5
⊢ C
∈ V |
| 20 | | 1o 3109 |
. . . . . . 7
⊢ 1o ∈ On |
| 21 | 20 | elisseti 1355 |
. . . . . 6
⊢ 1o ∈
V |
| 22 | 19, 21 | xpsnen 3339 |
. . . . 5
⊢ (C
× {1o}) ≈ C |
| 23 | | enen1 3375 |
. . . . 5
⊢ ((C
∈ V ∧ (C ×
{1o}) ≈ C) →
((C × {1o}) ≈
(D × {1o}) ↔
C ≈ (D × {1o}))) |
| 24 | 19, 22, 23 | mp2an 520 |
. . . 4
⊢ ((C
× {1o}) ≈ (D
× {1o}) ↔ C
≈ (D ×
{1o})) |
| 25 | | cdaen.4 |
. . . . 5
⊢ D
∈ V |
| 26 | 25, 21 | xpsnen 3339 |
. . . . 5
⊢ (D
× {1o}) ≈ D |
| 27 | | enen2 3376 |
. . . . 5
⊢ ((D
∈ V ∧ (D ×
{1o}) ≈ D) →
(C ≈ (D × {1o}) ↔ C ≈ D)) |
| 28 | 25, 26, 27 | mp2an 520 |
. . . 4
⊢ (C
≈ (D × {1o})
↔ C ≈ D) |
| 29 | 24, 28 | bitr 151 |
. . 3
⊢ ((C
× {1o}) ≈ (D
× {1o}) ↔ C
≈ D) |
| 30 | 8, 18, 29 | syl2anbr 351 |
. 2
⊢ ((A
≈ B ∧ C ≈ D)
→ ((A × {∅}) ∪
(C × {1o})) ≈
((B × {∅}) ∪ (D × {1o}))) |
| 31 | 9, 19 | cdaval 3717 |
. 2
⊢ (A
+c C) = ((A × {∅}) ∪ (C × {1o})) |
| 32 | 14, 25 | cdaval 3717 |
. 2
⊢ (B
+c D) = ((B × {∅}) ∪ (D × {1o})) |
| 33 | 30, 31, 32 | 3brtr4g 2088 |
1
⊢ ((A
≈ B ∧ C ≈ D)
→ (A +c C) ≈ (B
+c D)) |