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Theorem cdaen 3719
Description: Cardinal addition of equinumerous sets. Exercise 4.56(b) of [Mendelson] p. 258.
Hypotheses
Ref Expression
cdaen.1 AV
cdaen.2 BV
cdaen.3 CV
cdaen.4 DV
Assertion
Ref Expression
cdaen ((ABCD) → (A +c C) ≈ (B +c D))

Proof of Theorem cdaen
StepHypRef Expression
1 0ne1oOLD 3113 . . . . . 6 ¬ ∅ = 1o
2 xpsndisj 2655 . . . . . 6 (¬ ∅ = 1o → ((A × {∅}) ∩ (C × {1o})) = ∅)
31, 2ax-mp 6 . . . . 5 ((A × {∅}) ∩ (C × {1o})) = ∅
4 xpsndisj 2655 . . . . . 6 (¬ ∅ = 1o → ((B × {∅}) ∩ (D × {1o})) = ∅)
51, 4ax-mp 6 . . . . 5 ((B × {∅}) ∩ (D × {1o})) = ∅
63, 5pm3.2i 234 . . . 4 (((A × {∅}) ∩ (C × {1o})) = ∅ ∧ ((B × {∅}) ∩ (D × {1o})) = ∅)
7 unen 3338 . . . 4 ((((A × {∅}) ≈ (B × {∅}) ∧ (C × {1o}) ≈ (D × {1o})) ∧ (((A × {∅}) ∩ (C × {1o})) = ∅ ∧ ((B × {∅}) ∩ (D × {1o})) = ∅)) → ((A × {∅}) ∪ (C × {1o})) ≈ ((B × {∅}) ∪ (D × {1o})))
86, 7mpan2 519 . . 3 (((A × {∅}) ≈ (B × {∅}) ∧ (C × {1o}) ≈ (D × {1o})) → ((A × {∅}) ∪ (C × {1o})) ≈ ((B × {∅}) ∪ (D × {1o})))
9 cdaen.1 . . . . 5 AV
10 0ex 1745 . . . . . 6 ∅ ∈ V
119, 10xpsnen 3339 . . . . 5 (A × {∅}) ≈ A
12 enen1 3375 . . . . 5 ((AV ∧ (A × {∅}) ≈ A) → ((A × {∅}) ≈ (B × {∅}) ↔ A ≈ (B × {∅})))
139, 11, 12mp2an 520 . . . 4 ((A × {∅}) ≈ (B × {∅}) ↔ A ≈ (B × {∅}))
14 cdaen.2 . . . . 5 BV
1514, 10xpsnen 3339 . . . . 5 (B × {∅}) ≈ B
16 enen2 3376 . . . . 5 ((BV ∧ (B × {∅}) ≈ B) → (A ≈ (B × {∅}) ↔ AB))
1714, 15, 16mp2an 520 . . . 4 (A ≈ (B × {∅}) ↔ AB)
1813, 17bitr 151 . . 3 ((A × {∅}) ≈ (B × {∅}) ↔ AB)
19 cdaen.3 . . . . 5 CV
20 1o 3109 . . . . . . 7 1o ∈ On
2120elisseti 1355 . . . . . 6 1oV
2219, 21xpsnen 3339 . . . . 5 (C × {1o}) ≈ C
23 enen1 3375 . . . . 5 ((CV ∧ (C × {1o}) ≈ C) → ((C × {1o}) ≈ (D × {1o}) ↔ C ≈ (D × {1o})))
2419, 22, 23mp2an 520 . . . 4 ((C × {1o}) ≈ (D × {1o}) ↔ C ≈ (D × {1o}))
25 cdaen.4 . . . . 5 DV
2625, 21xpsnen 3339 . . . . 5 (D × {1o}) ≈ D
27 enen2 3376 . . . . 5 ((DV ∧ (D × {1o}) ≈ D) → (C ≈ (D × {1o}) ↔ CD))
2825, 26, 27mp2an 520 . . . 4 (C ≈ (D × {1o}) ↔ CD)
2924, 28bitr 151 . . 3 ((C × {1o}) ≈ (D × {1o}) ↔ CD)
308, 18, 29syl2anbr 351 . 2 ((ABCD) → ((A × {∅}) ∪ (C × {1o})) ≈ ((B × {∅}) ∪ (D × {1o})))
319, 19cdaval 3717 . 2 (A +c C) = ((A × {∅}) ∪ (C × {1o}))
3214, 25cdaval 3717 . 2 (B +c D) = ((B × {∅}) ∪ (D × {1o}))
3330, 31, 323brtr4g 2088 1 ((ABCD) → (A +c C) ≈ (B +c D))
Colors of variables: wff set class
Syntax hints:  ¬ wn 1   → wi 2   ↔ wb 127   ∧ wa 196   = wceq 1091   ∈ wcel 1092  Vcvv 1348   ∪ cun 1485   ∩ cin 1486  ∅c0 1707  {csn 1808   class class class wbr 2054  Oncon0 2199   × cxp 2408  (class class class)co 3001  1oc1o 3099   ≈ cen 3271   +c ccda 3714
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-13 804  ax-14 805  ax-16 922  ax-17 925  ax-ext 1074  ax-rep 1075  ax-un 1076  ax-pow 1077
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-3or 582  df-3an 583  df-ex 679  df-sb 853  df-eu 1009  df-mo 1010  df-clab 1093  df-cleq 1097  df-clel 1099  df-ral 1205  df-rex 1206  df-v 1349  df-dif 1489  df-un 1490  df-in 1491  df-ss 1492  df-nul 1708  df-pw 1799  df-sn 1811  df-pr 1812  df-tp 1814  df-op 1815  df-uni 1920  df-int 1966  df-tr 2042  df-br 2063  df-opab 2098  df-eprel 2122  df-id 2125  df-po 2128  df-so 2138  df-fr 2169  df-we 2186  df-ord 2202  df-on 2203  df-suc 2205  df-xp 2424  df-rel 2425  df-cnv 2426  df-co 2427  df-dm 2428  df-rn 2429  df-res 2430  df-ima 2431  df-fun 2432  df-fn 2433  df-f 2434  df-f1 2435  df-fo 2436  df-f1o 2437  df-fv 2438  df-opr 3003  df-oprab 3004  df-1o 3104  df-er 3200  df-en 3274  df-cda 3715
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