Proof of Theorem cmbr2
| Step | Hyp | Ref
| Expression |
| 1 | | pjoml2.1 |
. . 3
⊢ A
∈ Cℋ |
| 2 | | pjoml2.2 |
. . 3
⊢ B
∈ Cℋ |
| 3 | 1, 2 | cmcm4 5504 |
. 2
⊢ (A Com
B ↔ (⊥ ‘A) Com (⊥ ‘B)) |
| 4 | 1 | chocl 5192 |
. . 3
⊢ (⊥ ‘A) ∈ Cℋ |
| 5 | 2 | chocl 5192 |
. . 3
⊢ (⊥ ‘B) ∈ Cℋ |
| 6 | 4, 5 | cmbr 5499 |
. 2
⊢ ((⊥ ‘A) Com (⊥ ‘B) ↔ (⊥ ‘A) = (((⊥ ‘A) ∩ (⊥ ‘B)) ∨ℋ ((⊥ ‘A) ∩ (⊥ ‘(⊥ ‘B))))) |
| 7 | | cleqcom 1103 |
. . . 4
⊢ (A =
((A ∨ℋ B) ∩ (A
∨ℋ (⊥ ‘B)))
↔ ((A ∨ℋ B) ∩ (A
∨ℋ (⊥ ‘B)))
= A) |
| 8 | 1, 2 | chjcl 5379 |
. . . . . 6
⊢ (A
∨ℋ B) ∈
Cℋ |
| 9 | 1, 5 | chjcl 5379 |
. . . . . 6
⊢ (A
∨ℋ (⊥ ‘B))
∈ Cℋ |
| 10 | 8, 9 | chincl 5382 |
. . . . 5
⊢ ((A
∨ℋ B) ∩ (A &>r;ℋ (⊥ ‘B))) ∈ Cℋ |
| 11 | 10, 1 | chcon3 5387 |