| Metamath Proof Explorer |
< Previous
Next >
Related theorems GIF version |
| Description: Composition with the empty set. |
| Ref | Expression |
|---|---|
| co01 | ⊢ (∅ ∘ A) = ∅ |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cnv0 2633 | . . . . . 6 ⊢ ◡∅ = ∅ | |
| 2 | 1 | coeq2i 2505 | . . . . 5 ⊢ (◡A ∘ ◡∅) = (◡A ∘ ∅) |
| 3 | co02 2663 | . . . . 5 ⊢ (◡A ∘ ∅) = ∅ | |
| 4 | 2, 3 | eqtr2 1120 | . . . 4 ⊢ ∅ = (◡A ∘ ◡∅) |
| 5 | cnvco 2520 | . . . 4 ⊢ ◡(∅ ∘ A) = (◡A ∘ ◡∅) | |
| 6 | 4, 1, 5 | 3eqtr4 1126 | . . 3 ⊢ ◡∅ = ◡(∅ ∘ A) |
| 7 | cnveq 2513 | . . 3 ⊢ (◡∅ = ◡(∅ ∘ A) → ◡◡∅ = ◡◡(∅ ∘ A)) | |
| 8 | 6, 7 | ax-mp 6 | . 2 ⊢ ◡◡∅ = ◡◡(∅ ∘ A) |
| 9 | rel0 2499 | . . 3 ⊢ Rel ∅ | |
| 10 | dfrel2 2660 | . . 3 ⊢ (Rel ∅ ↔ ◡◡∅ = ∅) | |
| 11 | 9, 10 | mpbi 164 | . 2 ⊢ ◡◡∅ = ∅ |
| 12 | relco 2658 | . . 3 ⊢ Rel (∅ ∘ A) | |
| 13 | dfrel2 2660 | . . 3 ⊢ (Rel (∅ ∘ A) ↔ ◡◡(∅ ∘ A) = (∅ ∘ A)) | |
| 14 | 12, 13 | mpbi 164 | . 2 ⊢ ◡◡(∅ ∘ A) = (∅ ∘ A) |
| 15 | 8, 11, 14 | 3eqtr3r 1125 | 1 ⊢ (∅ ∘ A) = ∅ |
| Colors of variables: wff set class |
| Syntax hints: = wceq 1091 ∅c0 1707 ◡ccnv 2409 ∘ ccom 2414 Rel wrel 2415 |
| This theorem was proved from axioms: ax-1 3 ax-2 4 ax-3 5 ax-mp 6 ax-4 673 ax-5 674 ax-6 675 ax-7 676 ax-gen 677 ax-8 798 ax-9 799 ax-10 800 ax-11 801 ax-12 802 ax-13 804 ax-14 805 ax-16 922 ax-17 925 ax-ext 1074 ax-rep 1075 ax-pow 1077 |
| This theorem depends on definitions: df-bi 128 df-or 197 df-an 198 df-ex 679 df-sb 853 df-clab 1093 df-cleq 1097 df-clel 1099 df-v 1349 df-dif 1489 df-un 1490 df-in 1491 df-ss 1492 df-nul 1708 df-pw 1799 df-sn 1811 df-pr 1812 df-op 1815 df-br 2063 df-opab 2098 df-xp 2424 df-rel 2425 df-cnv 2426 df-co 2427 |