Proof of Theorem dffr2
| Step | Hyp | Ref
| Expression |
| 1 | | df-fr 2169 |
. 2
⊢ (R Fr
A ↔ ∀x((x ⊆
A ∧ ¬ x = ∅) → ∃v ∈ x
∀w ∈ x ¬ wRv)) |
| 2 | | disj 1733 |
. . . . . . 7
⊢ ((x
∩ {z∣zRy}) = ∅ ↔ ∀w ∈ x ¬
w ∈ {z∣zRy}) |
| 3 | | visset 1350 |
. . . . . . . . . 10
⊢ w
∈ V |
| 4 | | breq1 2065 |
. . . . . . . . . 10
⊢ (z =
w → (zRy ↔ wRy)) |
| 5 | 3, 4 | elab 1415 |
. . . . . . . . 9
⊢ (w
∈ {z∣zRy} ↔ wRy) |
| 6 | 5 | negbii 162 |
. . . . . . . 8
⊢ (¬ w ∈ {z∣zRy} ↔ ¬ wRy) |
| 7 | 6 | biral 1223 |
. . . . . . 7
⊢ (∀w ∈ x ¬
w ∈ {z∣zRy} ↔ ∀w ∈ x ¬
wRy) |
| 8 | 2, 7 | bitr 151 |
. . . . . 6
⊢ ((x
∩ {z∣zRy}) = ∅ ↔ ∀w ∈ x ¬
wRy) |
| 9 | 8 | birex 1224 |
. . . . 5
⊢ (∃y ∈ x
(x ∩ {z∣zRy}) = ∅ ↔ ∃y ∈ x
∀w ∈ x ¬ wRy) |
| 10 | | breq2 2066 |
. . . . . . . 8
⊢ (y =
v → (wRy ↔ wRv)) |
| 11 | 10 | negbid 463 |
. . . . . . 7
⊢ (y =
v → (¬ wRy ↔ ¬ wRv)) |
| 12 | 11 | biraldv 1219 |
. . . . . 6
⊢ (y =
v → (∀w ∈ x ¬
wRy ↔
∀w ∈ x ¬ wRv)) |
| 13 | 12 | cbvrexv 1334 |
. . . . 5
⊢ (∃y ∈ x
∀w ∈ x ¬ wRy ↔ ∃v ∈ x
∀w ∈ x ¬ wRv) |
| 14 | 9, 13 | bitr 151 |
. . . 4
⊢ (∃y ∈ x
(x ∩ {z∣zRy}) = ∅ ↔ ∃v ∈ x
∀w ∈ x ¬ wRv) |
| 15 | 14 | imbi2i 160 |
. . 3
⊢ (((x
⊆ A ∧ ¬ x = ∅) → ∃y ∈ x
(x ∩ {z∣zRy}) = ∅) ↔ ((x ⊆ A
∧ ¬ x = ∅) →
∃v ∈ x ∀w
∈ x ¬ wRv)) |
| 16 | 15 | bial 695 |
. 2
⊢ (∀x((x ⊆
A ∧ ¬ x = ∅) → ∃y ∈ x
(x ∩ {z∣zRy}) = ∅) ↔ ∀x((x ⊆
A ∧ ¬ x = ∅) → ∃v ∈ x
∀w ∈ x ¬ wRv)) |
| 17 | 1, 16 | bitr4 154 |
1
⊢ (R Fr
A ↔ ∀x((x ⊆
A ∧ ¬ x = ∅) → ∃y ∈ x
(x ∩ {z∣zRy}) = ∅)) |