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Theorem dfpr2 1821
Description: Alternate definition of unordered pair. Definition 5.1 of [TakeutiZaring] p. 15.
Assertion
Ref Expression
dfpr2 {A, B} = {x∣(x = Ax = B)}
Distinct variable group(s):   x,A   x,B

Proof of Theorem dfpr2
StepHypRef Expression
1 df-pr 1812 . 2 {A, B} = ({A} ∪ {B})
2 elun 1601 . . . 4 (x ∈ ({A} ∪ {B}) ↔ (x ∈ {A} ∨ x ∈ {B}))
3 elsn 1820 . . . . 5 (x ∈ {A} ↔ x = A)
4 elsn 1820 . . . . 5 (x ∈ {B} ↔ x = B)
53, 4orbi12i 216 . . . 4 ((x ∈ {A} ∨ x ∈ {B}) ↔ (x = Ax = B))
62, 5bitr 151 . . 3 (x ∈ ({A} ∪ {B}) ↔ (x = Ax = B))
76biabri 1180 . 2 ({A} ∪ {B}) = {x∣(x = Ax = B)}
81, 7eqtr 1119 1 {A, B} = {x∣(x = Ax = B)}
Colors of variables: wff set class
Syntax hints:   ∨ wo 195  {cab 1090   = wceq 1091   ∈ wcel 1092   ∪ cun 1485  {csn 1808  {cpr 1809
This theorem is referenced by:  elprg 1822  pwpw0 1883  zfpair 1891
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-un 1490  df-sn 1811  df-pr 1812
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