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Theorem difeq2 1583
Description: Equality theorem for class difference.
Assertion
Ref Expression
difeq2 (A = B → (CA) = (CB))

Proof of Theorem difeq2
StepHypRef Expression
1 eleq2 1150 . . . . 5 (A = B → (xAxB))
21negbid 463 . . . 4 (A = B → (¬ xA ↔ ¬ xB))
32anbi2d 468 . . 3 (A = B → ((xC ∧ ¬ xA) ↔ (xC ∧ ¬ xB)))
43biabdv 1183 . 2 (A = B → {x∣(xC ∧ ¬ xA)} = {x∣(xC ∧ ¬ xB)})
5 df-dif 1489 . 2 (CA) = {x∣(xC ∧ ¬ xA)}
6 df-dif 1489 . 2 (CB) = {x∣(xC ∧ ¬ xB)}
74, 5, 63eqtr4g 1147 1 (A = B → (CA) = (CB))
Colors of variables: wff set class
Syntax hints:  ¬ wn 1   → wi 2   ∧ wa 196  {cab 1090   = wceq>/A> 1091   ∈ wcel 1092   ∖ cdif 1484
This theorem is referenced by:  difeq2i 1585  difeq2d 1588  oev 3122  sbthlem2 3350  sbth 3359  phplem5 3407  unfilem3 3440  numthlem 3598  numth 3599
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-dif 1489
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