Proof of Theorem disjsn
| Step | Hyp | Ref
| Expression |
| 1 | | noel 1711 |
. . . 4
⊢ ¬ B ∈ ∅ |
| 2 | | eleq2 1150 |
. . . 4
⊢ ((A
∩ {B}) = ∅ → (B ∈ (A
∩ {B}) ↔ B ∈ ∅)) |
| 3 | 1, 2 | mtbiri 539 |
. . 3
⊢ ((A
∩ {B}) = ∅ → ¬ B ∈ (A
∩ {B})) |
| 4 | | snidg 1828 |
. . . . 5
⊢ (B
∈ A → B ∈ {B}) |
| 5 | 4 | ancli 244 |
. . . 4
⊢ (B
∈ A → (B ∈ A ∧
B ∈ {B})) |
| 6 | | elin 1635 |
. . . 4
⊢ (B
∈ (A ∩ {B}) ↔ (B
∈ A ∧ B ∈ {B})) |
| 7 | 5, 6 | sylibr 175 |
. . 3
⊢ (B
∈ A → B ∈ (A
∩ {B})) |
| 8 | 3, 7 | nsyl 102 |
. 2
⊢ ((A
∩ {B}) = ∅ → ¬ B ∈ A) |
| 9 | | eleq1 1149 |
. . . . . . . 8
⊢ (x =
B → (x ∈ A
↔ B ∈ A)) |
| 10 | 9 | biimpcd 137 |
. . . . . . 7
⊢ (x
∈ A → (x = B →
B ∈ A)) |
| 11 | | elsn 1820 |
. . . . . . 7
⊢ (x
∈ {B} ↔ x = B) |
| 12 | 10, 11 | syl5ib 181 |
. . . . . 6
⊢ (x
∈ A → (x ∈ {B}
→ B ∈ A)) |
| 13 | 12 | con3d 87 |
. . . . 5
⊢ (x
∈ A → (¬ B ∈ A
→ ¬ x ∈ {B})) |
| 14 | 13 | com12 13 |
. . . 4
⊢ (¬ B ∈ A
→ (x ∈ A → ¬ x
∈ {B})) |
| 15 | 14 | 19.21aiv 943 |
. . 3
⊢ (¬ B ∈ A
→ ∀x(x ∈ A
→ ¬ x ∈ {B})) |
| 16 | | disj1 1734 |
. . 3
⊢ ((A
∩ {B}) = ∅ ↔
∀x(x ∈ A
→ ¬ x ∈ {B})) |
| 17 | 15, 16 | sylibr 175 |
. 2
⊢ (¬ B ∈ A
→ (A ∩ {B}) = ∅) |
| 18 | 8, 17 | impbi 139 |
1
⊢ ((A
∩ {B}) = ∅ ↔ ¬ B ∈ A) |