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Theorem disjsn 1836
Description: Intersection with singleton of non-member is disjoint.
Assertion
Ref Expression
disjsn ((A ∩ {B}) = ∅ ↔ ¬ BA)

Proof of Theorem disjsn
StepHypRef Expression
1 noel 1711 . . . 4 ¬ B ∈ ∅
2 eleq2 1150 . . . 4 ((A ∩ {B}) = ∅ → (B ∈ (A ∩ {B}) ↔ B ∈ ∅))
31, 2mtbiri 539 . . 3 ((A ∩ {B}) = ∅ → ¬ B ∈ (A ∩ {B}))
4 snidg 1828 . . . . 5 (BAB ∈ {B})
54ancli 244 . . . 4 (BA → (BAB ∈ {B}))
6 elin 1635 . . . 4 (B ∈ (A ∩ {B}) ↔ (BAB ∈ {B}))
75, 6sylibr 175 . . 3 (BAB ∈ (A ∩ {B}))
83, 7nsyl 102 . 2 ((A ∩ {B}) = ∅ → ¬ BA)
9 eleq1 1149 . . . . . . . 8 (x = B → (xABA))
109biimpcd 137 . . . . . . 7 (xA → (x = BBA))
11 elsn 1820 . . . . . . 7 (x ∈ {B} ↔ x = B)
1210, 11syl5ib 181 . . . . . 6 (xA → (x ∈ {B} → BA))
1312con3d 87 . . . . 5 (xA → (¬ BA → ¬ x ∈ {B}))
1413com12 13 . . . 4 BA → (xA → ¬ x ∈ {B}))
151419.21aiv 943 . . 3 BA → ∀x(xA → ¬ x ∈ {B}))
16 disj1 1734 . . 3 ((A ∩ {B}) = ∅ ↔ ∀x(xA → ¬ x ∈ {B}))
1715, 16sylibr 175 . 2 BA → (A ∩ {B}) = ∅)
188, 17impbi 139 1 ((A ∩ {B}) = ∅ ↔ ¬ BA)
Colors of variables: wff set class
Syntax hints:  ¬ wn 1   → wi 2   ↔ wb 127   ∧ wa 196  ∀wal 672   = wceq 1091   ∈ wcel 1092   ∩ cin 1486  ∅c0 1707  {csn 1808
This theorem is referenced by:  disjsn2 1837  orddisj 2236  ndmima 2623  limensuci 3401  php 3409  infensuc 3484  kmlem2 3581  facnnt 4870  fac0 4871
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-ral 1205  df-v 1349  df-dif 1489  df-un 1490  df-in 1491  df-nul 1708  df-sn 1811  df-pr 1812
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