Proof of Theorem divdiv23t
| Step | Hyp | Ref
| Expression |
| 1 | | div23t 4240 |
. . 3
⊢ (((A
∈ ℂ ∧ (1 / B) ∈ ℂ
∧ C ∈ ℂ) ∧ C ≠ 0) → ((A · (1 / B)) / C) =
((A / C) · (1 / B))) |
| 2 | | 3simp1 594 |
. . . . 5
⊢ ((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) → A ∈ ℂ) |
| 3 | 2 | adantr 306 |
. . . 4
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → A ∈ ℂ) |
| 4 | | 1cn 4101 |
. . . . . . 7
⊢ 1 ∈ ℂ |
| 5 | | divclt 4223 |
. . . . . . 7
⊢ (((1 ∈ ℂ ∧ B ∈ ℂ) ∧ B ≠ 0) → (1 / B) ∈ ℂ) |
| 6 | 4, 5 | mpan11 529 |
. . . . . 6
⊢ ((B
∈ ℂ ∧ B ≠ 0) → (1 /
B) ∈ ℂ) |
| 7 | | 3simp2 595 |
. . . . . 6
⊢ ((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) → B ∈ ℂ) |
| 8 | 6, 7 | sylan 343 |
. . . . 5
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ B ≠ 0) → (1 / B) ∈ ℂ) |
| 9 | 8 | adantrr 312 |
. . . 4
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → (1 / B) ∈
ℂ) |
| 10 | | 3simp3 596 |
. . . . 5
⊢ ((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) → C ∈ ℂ) |
| 11 | 10 | adantr 306 |
. . . 4
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → C ∈ ℂ) |
| 12 | 3, 9, 11 | 3jca 604 |
. . 3
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → (A ∈ ℂ ∧ (1
/ B) ∈ ℂ ∧ C ∈ ℂ)) |
| 13 | | pm3.27 260 |
. . . 4
⊢ ((B
≠ 0 ∧ C ≠ 0) → C ≠ 0) |
| 14 | 13 | adantl 305 |
. . 3
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → C ≠ 0) |
| 15 | 1, 12, 14 | sylanc 361 |
. 2
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → ((A · (1 / B)) / C) =
((A / C) · (1 / B))) |
| 16 | | divrect 4238 |
. . . 4
⊢ (((A
∈ ℂ ∧ B ∈ ℂ)
∧ B ≠ 0) → (A / B) =
(A · (1 / B))) |
| 17 | | 3simpa 591 |
. . . 4
⊢ ((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) → (A ∈ ℂ ∧ B ∈ ℂ)) |
| 18 | | pm3.26 256 |
. . . 4
⊢ ((B
≠ 0 ∧ C ≠ 0) → B ≠ 0) |
| 19 | 16, 17, 18 | syl2an 349 |
. . 3
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → (A / B) = (A ·
(1 / B))) |
| 20 | 19 | opreq1d 3012 |
. 2
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → ((A / B) / C) =
((A · (1 / B)) / C)) |
| 21 | | divrect 4238 |
. . 3
⊢ ((((A
/ C) ∈ ℂ ∧ B ∈ ℂ) ∧ B ≠ 0) → ((A / C) /
B) = ((A / C) ·
(1 / B))) |
| 22 | | divclt 4223 |
. . . . . . . 8
⊢ (((A
∈ ℂ ∧ C ∈ ℂ)
∧ C ≠ 0) → (A / C) ∈
ℂ) |
| 23 | 22 | exp 291 |
. . . . . . 7
⊢ ((A
∈ ℂ ∧ C ∈ ℂ)
→ (C ≠ 0 → (A / C) ∈
ℂ)) |
| 24 | 23 | 3adant2 598 |
. . . . . 6
⊢ ((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) → (C ≠ 0 → (A / C) ∈
ℂ)) |
| 25 | 24 | imp 277 |
. . . . 5
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ C ≠ 0) → (A / C) ∈
ℂ) |
| 26 | 25 | adantrl 311 |
. . . 4
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → (A / C) ∈ ℂ) |
| 27 | 7 | adantr 306 |
. . . 4
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → B ∈ ℂ) |
| 28 | 26, 27 | jca 236 |
. . 3
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → ((A / C) ∈ ℂ ∧ B ∈ ℂ)) |
| 29 | 18 | adantl 305 |
. . 3
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → B ≠ 0) |
| 30 | 21, 28, 29 | sylanc 361 |
. 2
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → ((A / C) / B) =
((A / C) · (1 / B))) |
| 31 | 15, 20, 30 | 3eqtr4d 1134 |
1
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ (B ≠ 0 ∧ C
≠ 0)) → ((A / B) / C) =
((A / C) / B)) |