Proof of Theorem divmuldivt
| Step | Hyp | Ref
| Expression |
| 1 | | divcan3t 4251 |
. . 3
⊢ ((((B
· D) ∈ ℂ ∧ ((A / B) ·
(C / D)) ∈ ℂ) ∧ (B · D)
≠ 0) → (((B · D) · ((A
/ B) · (C / D))) /
(B · D)) = ((A /
B) · (C / D))) |
| 2 | | axmulcl 4068 |
. . . . . . 7
⊢ ((B
∈ ℂ ∧ D ∈ ℂ)
→ (B · D) ∈ ℂ) |
| 3 | 2 | adantrl 311 |
. . . . . 6
⊢ ((B
∈ ℂ ∧ (C ∈ ℂ
∧ D ∈ ℂ)) → (B · D)
∈ ℂ) |
| 4 | 3 | adantll 309 |
. . . . 5
⊢ (((A
∈ ℂ ∧ B ∈ ℂ)
∧ (C ∈ ℂ ∧ D ∈ ℂ)) → (B · D)
∈ ℂ) |
| 5 | 4 | adantr 306 |
. . . 4
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ (C ∈ ℂ ∧ D ∈ ℂ)) ∧ (B ≠ 0 ∧ D
≠ 0)) → (B · D) ∈ ℂ) |
| 6 | | axmulcl 4068 |
. . . . . 6
⊢ (((A /
B) ∈ ℂ ∧ (C / D) ∈
ℂ) → ((A / B) · (C /
D)) ∈ ℂ) |
| 7 | | divclt 4223 |
. . . . . 6
⊢ (((A
∈ ℂ ∧ B ∈ ℂ)
∧ B ≠ 0) → (A / B) ∈
ℂ) |
| 8 | | divclt 4223 |
. . . . . 6
⊢ (((C
∈ ℂ ∧ D ∈ ℂ)
∧ D ≠ 0) → (C / D) ∈
ℂ) |
| 9 | 6, 7, 8 | syl2an 349 |
. . . . 5
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ B ≠ 0) ∧ ((C ∈ ℂ ∧ D ∈ ℂ) ∧ D ≠ 0)) → ((A / B) ·
(C / D)) ∈ ℂ) |
| 10 | 9 | an4s 390 |
. . . 4
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ (C ∈ ℂ ∧ D ∈ ℂ)) ∧ (B ≠ 0 ∧ D
≠ 0)) → ((A / B) · (C /
D)) ∈ ℂ) |
| 11 | 5, 10 | jca 236 |
. . 3
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ (C ∈ ℂ ∧ D ∈ ℂ)) ∧ (B ≠ 0 ∧ D
≠ 0)) → ((B · D) ∈ ℂ ∧ ((A / B) ·
(C / D)) ∈ ℂ)) |
| 12 | | muln0bt 4213 |
. . . . . . 7
⊢ ((B
∈ ℂ ∧ D ∈ ℂ)
→ ((B ≠ 0 ∧ D ≠ 0) ↔ (B · D)
≠ 0)) |
| 13 | 12 | biimpd 135 |
. . . . . 6
⊢ ((B
∈ ℂ ∧ D ∈ ℂ)
→ ((B ≠ 0 ∧ D ≠ 0) → (B · D)
≠ 0)) |
| 14 | 13 | adantrl 311 |
. . . . 5
⊢ ((B
∈ ℂ ∧ (C ∈ ℂ
∧ D ∈ ℂ)) → ((B ≠ 0 ∧ D
≠ 0) → (B · D) ≠ 0)) |
| 15 | 14 | adantll 309 |
. . . 4
⊢ (((A
∈ ℂ ∧ B ∈ ℂ)
∧ (C ∈ ℂ ∧ D ∈ ℂ)) → ((B ≠ 0 ∧ D
≠ 0) → (B · D) ≠ 0)) |
| 16 | 15 | imp 277 |
. . 3
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ (C ∈ ℂ ∧ D ∈ ℂ)) ∧ (B ≠ 0 ∧ D
≠ 0)) → (B · D) ≠ 0) |
| 17 | 1, 11, 16 | sylanc 361 |
. 2
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ (C ∈ ℂ ∧ D ∈ ℂ)) ∧ (B ≠ 0 ∧ D
≠ 0)) → (((B · D) · ((A
/ B) · (C / D))) /
(B · D)) = ((A /
B) · (C / D))) |
| 18 | | mul4t 4177 |
. . . . . 6
⊢ (((B
∈ ℂ ∧ (A / B) ∈ ℂ) ∧ (D ∈ ℂ ∧ (C / D) ∈
ℂ)) → ((B · (A / B)) ·
(D · (C / D))) =
((B · D) · ((A
/ B) · (C / D)))) |
| 19 | | pm3.27 260 |
. . . . . . . 8
⊢ ((A
∈ ℂ ∧ B ∈ ℂ)
→ B ∈ ℂ) |
| 20 | 19 | adantr 306 |
. . . . . . 7
⊢ (((A
∈ ℂ ∧ B ∈ ℂ)
∧ B ≠ 0) → B ∈ ℂ) |
| 21 | 20, 7 | jca 236 |
. . . . . 6
⊢ (((A
∈ ℂ ∧ B ∈ ℂ)
∧ B ≠ 0) → (B ∈ ℂ ∧ (A / B) ∈
ℂ)) |
| 22 | | pm3.27 260 |
. . . . . . . 8
⊢ ((C
∈ ℂ ∧ D ∈ ℂ)
→ D ∈ ℂ) |
| 23 | 22 | adantr 306 |
. . . . . . 7
⊢ (((C
∈ ℂ ∧ D ∈ ℂ)
∧ D ≠ 0) → D ∈ ℂ) |
| 24 | 23, 8 | jca 236 |
. . . . . 6
⊢ (((C
∈ ℂ ∧ D ∈ ℂ)
∧ D ≠ 0) → (D ∈ ℂ ∧ (C / D) ∈
ℂ)) |
| 25 | 18, 21, 24 | syl2an 349 |
. . . . 5
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ B ≠ 0) ∧ ((C ∈ ℂ ∧ D ∈ ℂ) ∧ D ≠ 0)) → ((B · (A /
B)) · (D · (C /
D))) = ((B · D)
· ((A / B) · (C /
D)))) |
| 26 | | divcan2t 4229 |
. . . . . . . . 9
⊢ (((B
∈ ℂ ∧ A ∈ ℂ)
∧ B ≠ 0) → (B · (A /
B)) = A) |
| 27 | 26 | exp 291 |
. . . . . . . 8
⊢ ((B
∈ ℂ ∧ A ∈ ℂ)
→ (B ≠ 0 → (B · (A /
B)) = A)) |
| 28 | 27 | ancoms 334 |
. . . . . . 7
⊢ ((A
∈ ℂ ∧ B ∈ ℂ)
→ (B ≠ 0 → (B · (A /
B)) = A)) |
| 29 | 28 | imp 277 |
. . . . . 6
⊢ (((A
∈ ℂ ∧ B ∈ ℂ)
∧ B ≠ 0) → (B · (A /
B)) = A) |
| 30 | | divcan2t 4229 |
. . . . . . . . 9
⊢ (((D
∈ ℂ ∧ C ∈ ℂ)
∧ D ≠ 0) → (D · (C /
D)) = C) |
| 31 | 30 | exp 291 |
. . . . . . . 8
⊢ ((D
∈ ℂ ∧ C ∈ ℂ)
→ (D ≠ 0 → (D · (C /
D)) = C)) |
| 32 | 31 | ancoms 334 |
. . . . . . 7
⊢ ((C
∈ ℂ ∧ D ∈ ℂ)
→ (D ≠ 0 → (D · (C /
D)) = C)) |
| 33 | 32 | imp 277 |
. . . . . 6
⊢ (((C
∈ ℂ ∧ D ∈ ℂ)
∧ D ≠ 0) → (D · (C /
D)) = C) |
| 34 | 29, 33 | opreqan12d 3015 |
. . . . 5
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ B ≠ 0) ∧ ((C ∈ ℂ ∧ D ∈ ℂ) ∧ D ≠ 0)) → ((B · (A /
B)) · (D · (C /
D))) = (A · C)) |
| 35 | 25, 34 | eqtr3d 1130 |
. . . 4
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ B ≠ 0) ∧ ((C ∈ ℂ ∧ D ∈ ℂ) ∧ D ≠ 0)) → ((B · D)
· ((A / B) · (C /
D))) = (A · C)) |
| 36 | 35 | an4s 390 |
. . 3
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ (C ∈ ℂ ∧ D ∈ ℂ)) ∧ (B ≠ 0 ∧ D
≠ 0)) → ((B · D) · ((A
/ B) · (C / D))) =
(A · C)) |
| 37 | 36 | opreq1d 3012 |
. 2
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ (C ∈ ℂ ∧ D ∈ ℂ)) ∧ (B ≠ 0 ∧ D
≠ 0)) → (((B · D) · ((A
/ B) · (C / D))) /
(B · D)) = ((A
· C) / (B · D))) |
| 38 | 17, 37 | eqtr3d 1130 |
1
⊢ ((((A
∈ ℂ ∧ B ∈ ℂ)
∧ (C ∈ ℂ ∧ D ∈ ℂ)) ∧ (B ≠ 0 ∧ D
≠ 0)) → ((A / B) · (C /
D)) = ((A · C) /
(B · D))) |