Proof of Theorem divmult
| Step | Hyp | Ref
| Expression |
| 1 | | opreq1 3006 |
. . . . . 6
⊢ (A =
if(A ∈ ℂ, A, 0) → (A
/ B) = (if(A ∈ ℂ, A, 0) / B)) |
| 2 | 1 | cleq1d 1109 |
. . . . 5
⊢ (A =
if(A ∈ ℂ, A, 0) → ((A
/ B) = C ↔ (if(A
∈ ℂ, A, 0) / B) = C)) |
| 3 | | cleq2 1110 |
. . . . 5
⊢ (A =
if(A ∈ ℂ, A, 0) → ((B
· C) = A ↔ (B
· C) = if(A ∈ ℂ, A, 0))) |
| 4 | 2, 3 | bibi12d 477 |
. . . 4
⊢ (A =
if(A ∈ ℂ, A, 0) → (((A / B) =
C ↔ (B · C) =
A) ↔ ((if(A ∈ ℂ, A, 0) / B) =
C ↔ (B · C) =
if(A ∈ ℂ, A, 0)))) |
| 5 | 4 | imbi2d 464 |
. . 3
⊢ (A =
if(A ∈ ℂ, A, 0) → ((B
≠ 0 → ((A / B) = C ↔
(B · C) = A)) ↔
(B ≠ 0 → ((if(A ∈ ℂ, A, 0) / B) =
C ↔ (B · C) =
if(A ∈ ℂ, A, 0))))) |
| 6 | | neeq1 1194 |
. . . 4
⊢ (B =
if(B ∈ ℂ, B, 0) → (B
≠ 0 ↔ if(B ∈ ℂ, B, 0) ≠ 0)) |
| 7 | | opreq2 3007 |
. . . . . 6
⊢ (B =
if(B ∈ ℂ, B, 0) → (if(A ∈ ℂ, A, 0) / B) =
(if(A ∈ ℂ, A, 0) / if(B
∈ ℂ, B, 0))) |
| 8 | 7 | cleq1d 1109 |
. . . . 5
⊢ (B =
if(B ∈ ℂ, B, 0) → ((if(A ∈ ℂ, A, 0) / B) =
C ↔ (if(A ∈ ℂ, A, 0) / if(B
∈ ℂ, B, 0)) = C)) |
| 9 | | opreq1 3006 |
. . . . . 6
⊢ (B =
if(B ∈ ℂ, B, 0) → (B
· C) = (if(B ∈ ℂ, B, 0) · C)) |
| 10 | 9 | cleq1d 1109 |
. . . . 5
⊢ (B =
if(B ∈ ℂ, B, 0) → ((B
· C) = if(A ∈ ℂ, A, 0) ↔ (if(B ∈ ℂ, B, 0) · C) = if(A ∈
ℂ, A, 0))) |
| 11 | 8, 10 | bibi12d 477 |
. . . 4
⊢ (B =
if(B ∈ ℂ, B, 0) → (((if(A ∈ ℂ, A, 0) / B) =
C ↔ (B · C) =
if(A ∈ ℂ, A, 0)) ↔ ((if(A ∈ ℂ, A, 0) / if(B
∈ ℂ, B, 0)) = C ↔ (if(B
∈ ℂ, B, 0) · C) = if(A ∈
ℂ, A, 0)))) |
| 12 | 6, 11 | imbi12d 474 |
. . 3
⊢ (B =
if(B ∈ ℂ, B, 0) → ((B
≠ 0 → ((if(A ∈ ℂ,
A, 0) / B) = C ↔
(B · C) = if(A ∈
ℂ, A, 0))) ↔ (if(B ∈ ℂ, B, 0) ≠ 0 → ((if(A ∈ ℂ, A, 0) / if(B
∈ ℂ, B, 0)) = C ↔ (if(B
∈ ℂ, B, 0) · C) = if(A ∈
ℂ, A, 0))))) |
| 13 | | cleq2 1110 |
. . . . 5
⊢ (C =
if(C ∈ ℂ, C, 0) → ((if(A ∈ ℂ, A, 0) / if(B
∈ ℂ, B, 0)) = C ↔ (if(A
∈ ℂ, A, 0) / if(B ∈ ℂ, B, 0)) = if(C
∈ ℂ, C, 0))) |
| 14 | | opreq2 3007 |
. . . . . 6
⊢ (C =
if(C ∈ ℂ, C, 0) → (if(B ∈ ℂ, B, 0) · C) = (if(B
∈ ℂ, B, 0) · if(C ∈ ℂ, C, 0))) |
| 15 | 14 | cleq1d 1109 |
. . . . 5
⊢ (C =
if(C ∈ ℂ, C, 0) → ((if(B ∈ ℂ, B, 0) · C) = if(A ∈
ℂ, A, 0) ↔ (if(B ∈ ℂ, B, 0) · if(C ∈ ℂ, C, 0)) = if(A
∈ ℂ, A, 0))) |
| 16 | 13, 15 | bibi12d 477 |
. . . 4
⊢ (C =
if(C ∈ ℂ, C, 0) → (((if(A ∈ ℂ, A, 0) / if(B
∈ ℂ, B, 0)) = C ↔ (if(B
∈ ℂ, B, 0) · C) = if(A ∈
ℂ, A, 0)) ↔ ((if(A ∈ ℂ, A, 0) / if(B
∈ ℂ, B, 0)) = if(C ∈ ℂ, C, 0) ↔ (if(B ∈ ℂ, B, 0) · if(C ∈ ℂ, C, 0)) = if(A
∈ ℂ, A, 0)))) |
| 17 | 16 | imbi2d 464 |
. . 3
⊢ (C =
if(C ∈ ℂ, C, 0) → ((if(B ∈ ℂ, B, 0) ≠ 0 → ((if(A ∈ ℂ, A, 0) / if(B
∈ ℂ, B, 0)) = C ↔ (if(B
∈ ℂ, B, 0) · C) = if(A ∈
ℂ, A, 0))) ↔ (if(B ∈ ℂ, B, 0) ≠ 0 → ((if(A ∈ ℂ, A, 0) / if(B
∈ ℂ, B, 0)) = if(C ∈ ℂ, C, 0) ↔ (if(B ∈ ℂ, B, 0) · if(C ∈ ℂ, C, 0)) = if(A
∈ ℂ, A, 0))))) |
| 18 | | 0cn 4100 |
. . . . 5
⊢ 0 ∈ ℂ |
| 19 | 18 | elimel 1793 |
. . . 4
⊢ if(A
∈ ℂ, A, 0) ∈
ℂ |
| 20 | 18 | elimel 1793 |
. . . 4
⊢ if(B
∈ ℂ, B, 0) ∈
ℂ |
| 21 | 18 | elimel 1793 |
. . . 4
⊢ if(C
∈ ℂ, C, 0) ∈
ℂ |
| 22 | 19, 20, 21 | divmulz 4219 |
. . 3
⊢ (if(B
∈ ℂ, B, 0) ≠ 0 →
((if(A ∈ ℂ, A, 0) / if(B
∈ ℂ, B, 0)) = if(C ∈ ℂ, C, 0) ↔ (if(B ∈ ℂ, B, 0) · if(C ∈ ℂ, C, 0)) = if(A
∈ ℂ, A, 0))) |
| 23 | 5, 12, 17, 22 | dedth3h 1788 |
. 2
⊢ ((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) → (B ≠ 0 → ((A / B) =
C ↔ (B · C) =
A))) |
| 24 | 23 | imp 277 |
1
⊢ (((A
∈ ℂ ∧ B ∈ ℂ ∧
C ∈ ℂ) ∧ B ≠ 0) → ((A / B) =
C ↔ (B · C) =
A)) |