Proof of Theorem dm0rn0
| Step | Hyp | Ref
| Expression |
| 1 | | excom 728 |
. . . . . 6
⊢ (∃x∃y
xAy ↔
∃y∃x xAy) |
| 2 | 1 | negbii 162 |
. . . . 5
⊢ (¬ ∃x∃y
xAy ↔ ¬
∃y∃x xAy) |
| 3 | | alnex 716 |
. . . . 5
⊢ (∀x ¬ ∃y
xAy ↔ ¬
∃x∃y xAy) |
| 4 | | alnex 716 |
. . . . 5
⊢ (∀y ¬ ∃x
xAy ↔ ¬
∃y∃x xAy) |
| 5 | 2, 3, 4 | 3bitr4 158 |
. . . 4
⊢ (∀x ¬ ∃y
xAy ↔
∀y ¬ ∃x xAy) |
| 6 | | noel 1711 |
. . . . . 6
⊢ ¬ x ∈ ∅ |
| 7 | 6 | nbn 542 |
. . . . 5
⊢ (¬ ∃y xAy ↔
(∃y xAy ↔ x
∈ ∅)) |
| 8 | 7 | bial 695 |
. . . 4
⊢ (∀x ¬ ∃y
xAy ↔
∀x(∃y xAy ↔
x ∈ ∅)) |
| 9 | | noel 1711 |
. . . . . 6
⊢ ¬ y ∈ ∅ |
| 10 | 9 | nbn 542 |
. . . . 5
⊢ (¬ ∃x xAy ↔
(∃x xAy ↔ y
∈ ∅)) |
| 11 | 10 | bial 695 |
. . . 4
⊢ (∀y ¬ ∃x
xAy ↔
∀y(∃x xAy ↔
y ∈ ∅)) |
| 12 | 5, 8, 11 | 3bitr3 156 |
. . 3
⊢ (∀x(∃y
xAy ↔
x ∈ ∅) ↔ ∀y(∃x
xAy ↔
y ∈ ∅)) |
| 13 | | cleqabr 1175 |
. . 3
⊢ ({x∣∃y
xAy} = ∅
↔ ∀x(∃y xAy ↔
x ∈ ∅)) |
| 14 | | cleqabr 1175 |
. . 3
⊢ ({y∣∃x
xAy} = ∅
↔ ∀y(∃x xAy ↔
y ∈ ∅)) |
| 15 | 12, 13, 14 | 3bitr4 158 |
. 2
⊢ ({x∣∃y
xAy} = ∅
↔ {y∣∃x xAy} =
∅) |
| 16 | | df-dm 2428 |
. . 3
⊢ dom A
= {x∣∃y xAy} |
| 17 | 16 | cleq1i 1108 |
. 2
⊢ (dom A
= ∅ ↔ {x∣∃y xAy} =
∅) |
| 18 | | dfrn2 2523 |
. . 3
⊢ ran A
= {y∣∃x xAy} |
| 19 | 18 | cleq1i 1108 |
. 2
⊢ (ran A
= ∅ ↔ {y∣∃x xAy} =
∅) |
| 20 | 15, 17, 19 | 3bitr4 158 |
1
⊢ (dom A
= ∅ ↔ ran A = ∅) |