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Theorem dmco 2570
Description: Domain of a composition. Theorem 21 of [Suppes] p. 63.
Assertion
Ref Expression
dmco dom (AB) ⊆ dom B

Proof of Theorem dmco
StepHypRef Expression
1 df-br 2063 . . . . . . 7 (x(AB)y ↔ ⟨x, y⟩ ∈ (AB))
2 visset 1350 . . . . . . . 8 xV
3 visset 1350 . . . . . . . 8 yV
42, 3opelco 2509 . . . . . . 7 (⟨x, y⟩ ∈ (AB) ↔ ∃z(xBzzAy))
51, 4bitr 151 . . . . . 6 (x(AB)y ↔ ∃z(xBzzAy))
65biex 733 . . . . 5 (∃y x(AB)y ↔ ∃yz(xBzzAy))
7 excom 728 . . . . 5 (∃yz(xBzzAy) ↔ ∃zy(xBzzAy))
86, 7bitr 151 . . . 4 (∃y x(AB)y ↔ ∃zy(xBzzAy))
9 19.42v 966 . . . . . 6 (∃y(xBzzAy) ↔ (xBz ∧ ∃y zAy))
109pm3.26bd 259 . . . . 5 (∃y(xBzzAy) → xBz)
111019.22i 723 . . . 4 (∃zy(xBzzAy) → ∃z xBz)
128, 11sylbi 174 . . 3 (∃y x(AB)y → ∃z xBz)
1312ss2abi 1552 . 2 {x∣∃y x(AB)y} ⊆ {x∣∃z xBz}
14 df-dm 2428 . 2 dom (AB) = {x∣∃y x(AB)y}
15 df-dm 2428 . 2 dom B = {x∣∃z xBz}
1613, 14, 153sstr4 1539 1 dom (AB) ⊆ dom B
Colors of variables: wff set class
Syntax hints:   ∧ wa 196  ∃wex 678  {cab 1090   ∈ wcel 1092   ⊆ wss 1487  ⟨cop 1810   class class class wbr 2054  dom cdm 2410   ∘ ccom 2414
This theorem is referenced by:  rnco 2571  coexg 2671
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-13 804  ax-14 805  ax-16 922  ax-17 925  ax-ext 1074  ax-rep 1075  ax-pow 1077
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-dif 1489  df-un 1490  df-in 1491  df-ss 1492  df-nul 1708  df-pw 1799  df-sn 1811  df-pr 1812  df-op 1815  df-br 2063  df-opab 2098  df-co 2427  df-dm 2428
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