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Theorem elabs2 1457
Description: Membership in a class abstraction, expressed in terms of class substitution. Theorem 6.13 of [Quine] p. 44.
Assertion
Ref Expression
elabs2 (A ∈ {xφ} ↔ (AV ∧ [A / x]φ))

Proof of Theorem elabs2
StepHypRef Expression
1 df-rab 1208 . . . 4 {xVφ} = {x∣(xVφ)}
2 visset 1350 . . . . . 6 xV
32biantrur 544 . . . . 5 (φ ↔ (xVφ))
43biabi 1181 . . . 4 {xφ} = {x∣(xVφ)}
51, 4eqtr4 1122 . . 3 {xVφ} = {xφ}
65eleq2i 1153 . 2 (A ∈ {xVφ} ↔ A ∈ {xφ})
7 ax-17 925 . . 3 (yV → ∀x yV)
87elrabsf 1456 . 2 (A ∈ {xVφ} ↔ (AV ∧ [A / x]φ))
96, 8bitr3 153 1 (A ∈ {xφ} ↔ (AV ∧ [A / x]φ))
Colors of variables: wff set class
Syntax hints:   ↔ wb 127   ∧ wa 196  {cab 1090   ∈ wcel 1092  {crab 1204  Vcvv 1348  [wsbc 1440
This theorem is referenced by:  elabs 1458
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-rab 1208  df-v 1349  df-sbc 1441
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