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Theorem elreldm 2554
Description: The first member of an ordered pair in a relation belongs to the domain of the relation.
Assertion
Ref Expression
elreldm ((Rel ABA) → B ∈ dom A)

Proof of Theorem elreldm
StepHypRef Expression
1 df-rel 2425 . . . . 5 (Rel AA ⊆ (V × V))
2 ssel 1502 . . . . 5 (A ⊆ (V × V) → (BAB ∈ (V × V)))
31, 2sylbi 174 . . . 4 (Rel A → (BAB ∈ (V × V)))
4 elvv 2464 . . . 4 (B ∈ (V × V) ↔ ∃xy B = ⟨x, y⟩)
53, 4syl6ib 185 . . 3 (Rel A → (BA → ∃xy B = ⟨x, y⟩))
6 eleq1 1149 . . . . . 6 (B = ⟨x, y⟩ → (BA ↔ ⟨x, y⟩ ∈ A))
7 visset 1350 . . . . . . 7 xV
87opeldm 2534 . . . . . 6 (⟨x, y⟩ ∈ Ax ∈ dom A)
96, 8syl6bi 187 . . . . 5 (B = ⟨x, y⟩ → (BAx ∈ dom A))
10 inteq 1968 . . . . . . . 8 (B = ⟨x, y⟩ → B = x, y⟩)
1110inteqd 1970 . . . . . . 7 (B = ⟨x, y⟩ → B = x, y⟩)
127op1stb 1992 . . . . . . 7 x, y⟩ = x
1311, 12syl6eq 1140 . . . . . 6 (B = ⟨x, y⟩ → B = x)
1413eleq1d 1155 . . . . 5 (B = ⟨x, y⟩ → (B ∈ dom Ax ∈ dom A))
159, 14sylibrd 179 . . . 4 (B = ⟨x, y⟩ → (BAB ∈ dom A))
161519.23aivv 953 . . 3 (∃xy B = ⟨x, y⟩ → (BAB ∈ dom A))
175, 16syli 52 . 2 (Rel A → (BAB ∈ dom A))
1817imp 277 1 ((Rel ABA) → B ∈ dom A)
Colors of variables: wff set class
Syntax hints:   → wi 2   ∧ wa 196  ∃wex 678   = wceq 1091   ∈ wcel 1092  Vcvv 1348   ⊆ wss 1487  ⟨cop 1810  cint 1965   × cxp 2408  dom cdm 2410  Rel wrel 2415
This theorem is referenced by:  fundmen 3333
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-13 804  ax-14 805  ax-16 922  ax-17 925  ax-ext 1074  ax-rep 1075  ax-pow 1077
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-ral 1205  df-v 1349  df-dif 1489  df-un 1490  df-in 1491  df-ss 1492  df-nul 1708  df-pw 1799  df-sn 1811  df-pr 1812  df-op 1815  df-int 1966  df-br 2063  df-opab 2098  df-xp 2424  df-rel 2425  df-dm 2428
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