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Related theorems GIF version |
| Description: A member of an unordered triple of classes is one of them. Special case of Exercise 1 of [TakeutiZaring] p. 17. |
| Ref | Expression |
|---|---|
| eltp.1 | ⊢ A ∈ V |
| Ref | Expression |
|---|---|
| eltp | ⊢ (A ∈ {B, C, D} ↔ (A = B ∨ A = C ∨ A = D)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | df-tp 1814 | . . . 4 ⊢ {B, C, D} = ({B, C} ∪ {D}) | |
| 2 | 1 | eleq2i 1153 | . . 3 ⊢ (A ∈ {B, C, D} ↔ A ∈ ({B, C} ∪ {D})) |
| 3 | elun 1601 | . . 3 ⊢ (A ∈ ({B, C} ∪ {D}) ↔ (A ∈ {B, C} ∨ A ∈ {D})) | |
| 4 | eltp.1 | . . . . 5 ⊢ A ∈ V | |
| 5 | 4 | elpr 1823 | . . . 4 ⊢ (A ∈ {B, C} ↔ (A = B ∨ A = C)) |
| 6 | 4 | elsnc 1826 | . . . 4 ⊢ (A ∈ {D} ↔ A = D) |
| 7 | 5, 6 | orbi12i 216 | . . 3 ⊢ ((A ∈ {B, C} ∨ A ∈ {D}) ↔ ((A = B ∨ A = C) ∨ A = D)) |
| 8 | 2, 3, 7 | 3bitr 155 | . 2 ⊢ (A ∈ {B, C, D} ↔ ((A = B ∨ A = C) ∨ A = D)) |
| 9 | df-3or 582 | . 2 ⊢ ((A = B ∨ A = C ∨ A = D) ↔ ((A = B ∨ A = C) ∨ A = D)) | |
| 10 | 8, 9 | bitr4 154 | 1 ⊢ (A ∈ {B, C, D} ↔ (A = B ∨ A = C ∨ A = D)) |
| Colors of variables: wff set class |
| Syntax hints: ↔ wb 127 ∨ wo 195 ∨ w3o 580 = wceq 1091 ∈ wcel 1092 Vcvv 1348 ∪ cun 1485 {csn 1808 {cpr 1809 {ctp 1813 |
| This theorem is referenced by: dftp2 1835 tpss 1855 fr3nr 2178 |
| This theorem was proved from axioms: ax-1 3 ax-2 4 ax-3 5 ax-mp 6 ax-4 673 ax-5 674 ax-6 675 ax-7 676 ax-gen 677 ax-8 798 ax-9 799 ax-10 800 ax-11 801 ax-12 802 ax-16 922 ax-17 925 ax-ext 1074 |
| This theorem depends on definitions: df-bi 128 df-or 197 df-an 198 df-3or 582 df-ex 679 df-sb 853 df-clab 1093 df-cleq 1097 df-clel 1099 df-v 1349 df-un 1490 df-sn 1811 df-pr 1812 df-tp 1814 |