Proof of Theorem endisj
| Step | Hyp | Ref
| Expression |
| 1 | | endisj.1 |
. . . 4
⊢ A
∈ V |
| 2 | | 0ex 1745 |
. . . 4
⊢ ∅ ∈ V |
| 3 | 1, 2 | xpsnen 3339 |
. . 3
⊢ (A
× {∅}) ≈ A |
| 4 | | endisj.2 |
. . . 4
⊢ B
∈ V |
| 5 | | p0ex 1885 |
. . . 4
⊢ {∅} ∈ V |
| 6 | 4, 5 | xpsnen 3339 |
. . 3
⊢ (B
× {{∅}}) ≈ B |
| 7 | 3, 6 | pm3.2i 234 |
. 2
⊢ ((A
× {∅}) ≈ A ∧
(B × {{∅}}) ≈ B) |
| 8 | | 0nep0 1887 |
. . 3
⊢ ¬ ∅ = {∅} |
| 9 | | xpsndisj 2655 |
. . 3
⊢ (¬ ∅ = {∅} →
((A × {∅}) ∩ (B × {{∅}})) = ∅) |
| 10 | 8, 9 | ax-mp 6 |
. 2
⊢ ((A
× {∅}) ∩ (B ×
{{∅}})) = ∅ |
| 11 | 1, 5 | xpex 2488 |
. . 3
⊢ (A
× {∅}) ∈ V |
| 12 | | snex 1859 |
. . . 4
⊢ {{∅}} ∈ V |
| 13 | 4, 12 | xpex 2488 |
. . 3
⊢ (B
× {{∅}}) ∈ V |
| 14 | | breq1 2065 |
. . . . 5
⊢ (x =
(A × {∅}) → (x ≈ A
↔ (A × {∅}) ≈
A)) |
| 15 | | breq1 2065 |
. . . . 5
⊢ (y =
(B × {{∅}}) → (y ≈ B
↔ (B × {{∅}}) ≈
B)) |
| 16 | 14, 15 | bi2anan9 478 |
. . . 4
⊢ ((x =
(A × {∅}) ∧ y = (B ×
{{∅}})) → ((x ≈ A ∧ y
≈ B) ↔ ((A × {∅}) ≈ A ∧ (B
× {{∅}}) ≈ B))) |
| 17 | | ineq12 1640 |
. . . . 5
⊢ ((x =
(A × {∅}) ∧ y = (B ×
{{∅}})) → (x ∩ y) = ((A ×
{∅}) ∩ (B ×
{{∅}}))) |
| 18 | 17 | cleq1d 1109 |
. . . 4
⊢ ((x =
(A × {∅}) ∧ y = (B ×
{{∅}})) → ((x ∩ y) = ∅ ↔ ((A × {∅}) ∩ (B × {{∅}})) = ∅)) |
| 19 | 16, 18 | anbi12d 476 |
. . 3
⊢ ((x =
(A × {∅}) ∧ y = (B ×
{{∅}})) → (((x ≈ A ∧ y
≈ B) ∧ (x ∩ y) =
∅) ↔ (((A × {∅})
≈ A ∧ (B × {{∅}}) ≈ B) ∧ ((A
× {∅}) ∩ (B ×
{{∅}})) = ∅))) |
| 20 | 11, 13, 19 | cla4e2v 1406 |
. 2
⊢ ((((A
× {∅}) ≈ A ∧
(B × {{∅}}) ≈ B) ∧ ((A
× {∅}) ∩ (B ×
{{∅}})) = ∅) → ∃x∃y((x ≈
A ∧ y ≈ B)
∧ (x ∩ y) = ∅)) |
| 21 | 7, 10, 20 | mp2an 520 |
1
⊢ ∃x∃y((x ≈
A ∧ y ≈ B)
∧ (x ∩ y) = ∅) |