Proof of Theorem euuni
| Step | Hyp | Ref
| Expression |
| 1 | | euabex 1869 |
. . . 4
⊢ (∃!xφ →
{x∣φ} ∈ V) |
| 2 | | uniexg 1948 |
. . . 4
⊢ ({x∣φ}
∈ V → ∪{x∣φ}
∈ V) |
| 3 | 1, 2 | syl 12 |
. . 3
⊢ (∃!xφ →
∪{x∣φ} ∈ V) |
| 4 | | eueq 1427 |
. . . 4
⊢ (∪{x∣φ}
∈ V ↔ ∃!y y = ∪{x∣φ}) |
| 5 | | cleqcom 1103 |
. . . . 5
⊢ (y =
∪{x∣φ} ↔ ∪{x∣φ} = y) |
| 6 | 5 | bieu 1014 |
. . . 4
⊢ (∃!y y = ∪{x∣φ} ↔ ∃!y∪{x∣φ} =
y) |
| 7 | | hbab1 1095 |
. . . . . . 7
⊢ (z
∈ {x∣φ} → ∀x z ∈
{x∣φ}) |
| 8 | 7 | hbuni 1925 |
. . . . . 6
⊢ (z
∈ ∪{x∣φ}
→ ∀x z ∈ ∪{x∣φ}) |
| 9 | | ax-17 925 |
. . . . . 6
⊢ (z
∈ y → ∀x z ∈
y) |
| 10 | 8, 9 | hbeq 1171 |
. . . . 5
⊢ (∪{x∣φ} =
y → ∀x∪{x∣φ} =
y) |
| 11 | | ax-17 925 |
. . . . 5
⊢ (∪{x∣φ} =
x → ∀y∪{x∣φ} =
x) |
| 12 | | cleq2 1110 |
. . . . 5
⊢ (y =
x → (∪{x∣φ} = y
↔ ∪{x∣φ} =
x)) |
| 13 | 10, 11, 12 | cbveu 1018 |
. . . 4
⊢ (∃!y∪{x∣φ} =
y ↔ ∃!x∪{x∣φ} =
x) |
| 14 | 4, 6, 13 | 3bitr 155 |
. . 3
⊢ (∪{x∣φ}
∈ V ↔ ∃!x∪{x∣φ} = x) |
| 15 | 3, 14 | sylib 173 |
. 2
⊢ (∃!xφ →
∃!x∪{x∣φ} = x) |
| 16 | | eusn 1913 |
. . 3
⊢ (∃!xφ ↔
∃x{x∣φ} =
{x}) |
| 17 | | visset 1350 |
. . . . . . . 8
⊢ x
∈ V |
| 18 | 17 | snid 1830 |
. . . . . . 7
⊢ x
∈ {x} |
| 19 | | eleq2 1150 |
. . . . . . 7
⊢ ({x∣φ} =
{x} → (x ∈ {x∣φ}
↔ x ∈ {x})) |
| 20 | 18, 19 | mpbiri 169 |
. . . . . 6
⊢ ({x∣φ} =
{x} → x ∈ {x∣φ}) |
| 21 | | abid 1094 |
. . . . . 6
⊢ (x
∈ {x∣φ} ↔ φ) |
| 22 | 20, 21 | sylib 173 |
. . . . 5
⊢ ({x∣φ} =
{x} → φ) |
| 23 | | unieq 1927 |
. . . . . 6
⊢ ({x∣φ} =
{x} → ∪{x∣φ} = ∪{x}) |
| 24 | 17 | unisn 1932 |
. . . . . 6
⊢ ∪{x} = x |
| 25 | 23, 24 | syl6eq 1140 |
. . . . 5
⊢ ({x∣φ} =
{x} → ∪{x∣φ} = x) |
| 26 | 22, 25 | jca 236 |
. . . 4
⊢ ({x∣φ} =
{x} → (φ ∧ ∪{x∣φ} =
x)) |
| 27 | 26 | 19.22i 723 |
. . 3
⊢ (∃x{x∣φ} = {x}
→ ∃x(φ ∧ ∪{x∣φ} =
x)) |
| 28 | 16, 27 | sylbi 174 |
. 2
⊢ (∃!xφ →
∃x(φ ∧ ∪{x∣φ} =
x)) |
| 29 | | eupickb 1056 |
. . . 4
⊢ ((∃!xφ ∧
∃!x∪{x∣φ} = x
∧ ∃x(φ ∧ ∪{x∣φ} =
x)) → (φ ↔ ∪{x∣φ} = x)) |
| 30 | 29 | 3exp 611 |
. . 3
⊢ (∃!xφ →
(∃!x∪{x∣φ} = x
→ (∃x(φ ∧ ∪{x∣φ} =
x) → (φ ↔ ∪{x∣φ} = x)))) |
| 31 | 30 | imp3a 279 |
. 2
⊢ (∃!xφ →
((∃!x∪{x∣φ} = x
∧ ∃x(φ ∧ ∪{x∣φ} =
x)) → (φ ↔ ∪{x∣φ} = x))) |
| 32 | 15, 28, 31 | mp2and 526 |
1
⊢ (∃!xφ →
(φ ↔ ∪{x∣φ} = x)) |