HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
GIF version

Theorem exan 784
Description: Place a conjunct in the scope of an existential quantifier.
Hypothesis
Ref Expression
exan.1 (∃xφψ)
Assertion
Ref Expression
exan x(φψ)

Proof of Theorem exan
StepHypRef Expression
1 hbe1 709 . . . . 5 (∃xφ → ∀xxφ)
2119.27 750 . . . 4 (∀x(ψ ∧ ∃xφ) ↔ (∀xψ ∧ ∃xφ))
3 exan.1 . . . . 5 (∃xφψ)
4 ancom 333 . . . . 5 ((∃xφψ) ↔ (ψ ∧ ∃xφ))
53, 4mpbi 164 . . . 4 (ψ ∧ ∃xφ)
62, 5mpgbi 685 . . 3 (∀xψ ∧ ∃xφ)
7 19.29 752 . . 3 ((∀xψ ∧ ∃xφ) → ∃x(ψφ))
86, 7ax-mp 6 . 2 x(ψφ)
9 exancom 736 . 2 (∃x(ψφ) ↔ ∃x(φψ))
108, 9mpbi 164 1 x(φψ)
Colors of variables: wff set class
Syntax hints:   ∧ wa 196  ∀wal 672  ∃wex 678
This theorem is referenced by:  bm1.3ii 1481
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-gen 677
This theorem depends on definitions:  df-bi 128  df-an 198  df-ex 679
metamath.org