Proof of Theorem fh2
| Step | Hyp | Ref
| Expression |
| 1 | | fh1.2 |
. . . . 5
⊢ B
∈ Cℋ |
| 2 | | fh1.1 |
. . . . 5
⊢ A
∈ Cℋ |
| 3 | 1, 2 | chincl 5382 |
. . . 4
⊢ (B
∩ A) ∈
Cℋ |
| 4 | | fh1.3 |
. . . . 5
⊢ C
∈ Cℋ |
| 5 | 1, 4 | chincl 5382 |
. . . 4
⊢ (B
∩ C) ∈
Cℋ |
| 6 | 3, 5 | chjcl 5379 |
. . 3
⊢ ((B
∩ A) ∨ℋ (B ∩ C))
∈ Cℋ |
| 7 | 2, 4 | chjcl 5379 |
. . . . 5
⊢ (A
∨ℋ C) ∈
Cℋ |
| 8 | 1, 7 | chincl 5382 |
. . . 4
⊢ (B
∩ (A ∨ℋ C)) ∈ Cℋ |
| 9 | 8 | chshi 5132 |
. . 3
⊢ (B
∩ (A ∨ℋ C)) ∈ Sℋ |
| 10 | 1, 2, 4 | ledi 5447 |
. . 3
⊢ ((B
∩ A) ∨ℋ (B ∩ C))
⊆ (B ∩ (A ∨ℋ C)) |
| 11 | 3, 5 | chdmj1 5402 |
. . . . . . . 8
⊢ (⊥ ‘((B ∩ A)
∨ℋ (B ∩ C))) = ((⊥ ‘(B ∩ A))
∩ (⊥ ‘(B ∩ C))) |
| 12 | 1, 2 | chdmm1 5398 |
. . . . . . . . 9
⊢ (⊥ ‘(B ∩ A)) =
((⊥ ‘B) ∨ℋ
(⊥ ‘A)) |
| 13 | 12 | ineq1i 1641 |
. . . . . . . 8
⊢ ((⊥ ‘(B ∩ A))
∩ (⊥ ‘(B ∩ C))) = (((⊥ ‘B) ∨ℋ (⊥ ‘A)) ∩ (⊥ ‘(B ∩ C))) |
| 14 | 11, 13 | eqtr 1119 |
. . . . . . 7
⊢ (⊥ ‘((B ∩ A)
∨ℋ (B ∩ C))) = (((⊥ ‘B) ∨ℋ (⊥ ‘A)) ∩ (⊥ ‘(B ∩ C))) |
| 15 | 14 | ineq2i 1642 |
. . . . . 6
⊢ ((B
∩ (A ∨ℋ C)) ∩ (⊥ ‘((B ∩ A)
∨ℋ (B ∩ C)))) = ((B
∩ (A ∨ℋ C)) ∩ (((⊥ ‘B) ∨ℋ (⊥ ‘A)) ∩ (⊥ ‘(B ∩ C)))) |
| 16 | | in4 1653 |
. . . . . 6
⊢ ((B
∩ (A ∨ℋ C)) ∩ (((⊥ ‘B) ∨ℋ (⊥ ‘A)) ∩ (⊥ ‘(B ∩ C)))) =
((B ∩ ((⊥ ‘B) ∨ℋ (⊥ ‘A))) ∩ ((A
∨ℋ C) ∩ (⊥
‘(B ∩ C)))) |
| 17 | | fh1.4 |
. . . . . . . . . . 11
⊢ A Com
B |
| 18 | 2, 1, 17 | cmcmi 5506 |
. . . . . . . . . 10
⊢ B Com
A |
| 19 | 1, 2, 18 | cmcm2i 5507 |
. . . . . . . . 9
⊢ B Com
(⊥ ‘A) |
| 20 | 2 | chocl 5192 |
. . . . . . . . . 10
⊢ (⊥ ‘A) ∈ Cℋ |
| 21 | 1, 20 | cmbr3 5509 |
. . . . . . . . 9
⊢ (B Com
(⊥ ‘A) ↔ (B ∩ ((⊥ ‘B) ∨ℋ (⊥ ‘A))) = (B ∩
(⊥ ‘A))) |
| 22 | 19, 21 | mpbi 164 |
. . . . . . . 8
⊢ (B
∩ ((⊥ ‘B)
∨ℋ (⊥ ‘A)))
= (B ∩ (⊥ ‘A)) |
| 23 | | incom 1636 |
. . . . . . . 8
⊢ (B
∩ (⊥ ‘A)) = ((⊥
‘A) ∩ B) |
| 24 | 22, 23 | eqtr 1119 |
. . . . . . 7
⊢ (B
∩ ((⊥ ‘B)
∨ℋ (⊥ ‘A)))
= ((⊥ ‘A) ∩ B) |
| 25 | 24 | ineq1i 1641 |
. . . . . 6
⊢ ((B
∩ ((⊥ ‘B)
∨ℋ (⊥ ‘A)))
∩ ((A ∨ℋ C) ∩ (⊥ ‘(B ∩ C)))) =
(((⊥ ‘A) ∩ B) ∩ ((A
∨ℋ C) ∩ (⊥
‘(B ∩ C)))) |
| 26 | 15, 16, 25 | 3eqtr 1123 |
. . . . 5
⊢ ((B
∩ (A ∨ℋ C)) ∩ (⊥ ‘((B ∩ A)
∨ℋ (B ∩ C)))) = (((⊥ ‘A) ∩ B)
∩ ((A ∨ℋ C) ∩ (⊥ ‘(B ∩ C)))) |
| 27 | | in4 1653 |
. . . . 5
⊢ (((⊥ ‘A) ∩ B)
∩ ((A ∨ℋ C) ∩ (⊥ ‘(B ∩ C)))) =
(((⊥ ‘A) ∩ (A ∨ℋ C)) ∩ (B
∩ (⊥ ‘(B ∩ C)))) |
| 28 | 2 | pjococ 5272 |
. . . . . . . . 9
⊢ (⊥ ‘(⊥ ‘A)) = A |
| 29 | 28 | opreq1i 3009 |
. . . . . . . 8
⊢ ((⊥ ‘(⊥ ‘A)) ∨ℋ C) = (A
∨ℋ C) |
| 30 | 29 | ineq2i 1642 |
. . . . . . 7
⊢ ((⊥ ‘A) ∩ ((⊥ ‘(⊥ ‘A)) ∨ℋ C)) = ((⊥ ‘A) ∩ (A
∨ℋ C)) |
| 31 | | fh1.5 |
. . . . . . . . 9
⊢ A Com
C |
| 32 | 2, 4, 31 | cmcm3i 5508 |
. . . . . . . 8
⊢ (⊥ ‘A) Com C |
| 33 | 20, 4 | cmbr3 5509 |
. . . . . . . 8
⊢ ((⊥ ‘A) Com C ↔
((⊥ ‘A) ∩ ((⊥
‘(⊥ ‘A))
∨ℋ C)) = ((⊥
‘A) ∩ C)) |
| 34 | 32, 33 | mpbi 164 |
. . . . . . 7
⊢ ((⊥ ‘A) ∩ ((⊥ ‘(⊥ ‘A)) ∨ℋ C)) = ((⊥ ‘A) ∩ C) |
| 35 | 30, 34 | eqtr3 1121 |
. . . . . 6
⊢ ((⊥ ‘A) ∩ (A
∨ℋ C)) = ((⊥
‘A) ∩ C) |
| 36 | 35 | ineq1i 1641 |
. . . . 5
⊢ (((⊥ ‘A) ∩ (A
∨ℋ C)) ∩ (B ∩ (⊥ ‘(B ∩ C)))) =
(((⊥ ‘A) ∩ C) ∩ (B
∩ (⊥ ‘(B ∩ C)))) |
| 37 | 26, 27, 36 | 3eqtr 1123 |
. . . 4
⊢ ((B
∩ (A ∨ℋ C)) ∩ (⊥ ‘((B ∩ A)
∨ℋ (B ∩ C)))) = (((⊥ ‘A) ∩ C)
∩ (B ∩ (⊥ ‘(B ∩ C)))) |
| 38 | | inass 1650 |
. . . 4
⊢ (((⊥ ‘A) ∩ C)
∩ (B ∩ (⊥ ‘(B ∩ C)))) =
((⊥ ‘A) ∩ (C ∩ (B ∩
(⊥ ‘(B ∩ C))))) |
| 39 | | in12 1651 |
. . . . . . . 8
⊢ (C
∩ (B ∩ (⊥ ‘(B ∩ C)))) =
(B ∩ (C ∩ (⊥ ‘(B ∩ C)))) |
| 40 | | inass 1650 |
. . . . . . . 8
⊢ ((B
∩ C) ∩ (⊥ ‘(B ∩ C))) =
(B ∩ (C ∩ (⊥ ‘(B ∩ C)))) |
| 41 | 39, 40 | eqtr4 1122 |
. . . . . . 7
⊢ (C
∩ (B ∩ (⊥ ‘(B ∩ C)))) =
((B ∩ C) ∩ (⊥ ‘(B ∩ C))) |
| 42 | 5 | chocin 5376 |
. . . . . . 7
⊢ ((B
∩ C) ∩ (⊥ ‘(B ∩ C))) =
0ℋ |
| 43 | 41, 42 | eqtr 1119 |
. . . . . 6
⊢ (C
∩ (B ∩ (⊥ ‘(B ∩ C)))) =
0ℋ |
| 44 | 43 | ineq2i 1642 |
. . . . 5
⊢ ((⊥ ‘A) ∩ (C
∩ (B ∩ (⊥ ‘(B ∩ C))))) =
((⊥ ‘A) ∩
0ℋ) |
| 45 | 20 | chm0 5411 |
. . . . 5
⊢ ((⊥ ‘A) ∩ 0ℋ) =
0ℋ |
| 46 | 44, 45 | eqtr 1119 |
. . . 4
⊢ ((⊥ ‘A) ∩ (C
∩ (B ∩ (⊥ ‘(B ∩ C))))) =
0ℋ |
| 47 | 37, 38, 46 | 3eqtr 1123 |
. . 3
⊢ ((B
∩ (A ∨ℋ C)) ∩ (⊥ ‘((B ∩ A)
∨ℋ (B ∩ C)))) = 0ℋ |
| 48 | 6, 9, 10, 47 | omlsi 5250 |
. 2
⊢ ((B
∩ A) ∨ℋ (B ∩ C)) =
(B ∩ (A ∨ℋ C)) |
| 49 | 48 | cleqcomi 1105 |
1
⊢ (B
∩ (A ∨ℋ C)) = ((B ∩
A) ∨ℋ (B ∩ C)) |