Proof of Theorem findes
| Step | Hyp | Ref
| Expression |
| 1 | | dfsbcq 1442 |
. 2
⊢ (z =
∅ → ([z / x]φ ↔
[∅ / x]φ)) |
| 2 | | sbequ 877 |
. 2
⊢ (z =
y → ([z / x]φ ↔ [y / x]φ)) |
| 3 | | dfsbcq 1442 |
. 2
⊢ (z =
suc y → ([z / x]φ ↔ [suc y / x]φ)) |
| 4 | | sbequ12r 866 |
. 2
⊢ (z =
x → ([z / x]φ ↔ φ)) |
| 5 | | findes.1 |
. 2
⊢ [∅ / x]φ |
| 6 | | ax-17 925 |
. . . 4
⊢ (y
∈ ω → ∀x y ∈ ω) |
| 7 | | hbs1 986 |
. . . . 5
⊢ ([y /
x]φ
→ ∀x[y / x]φ) |
| 8 | | visset 1350 |
. . . . . . 7
⊢ y
∈ V |
| 9 | 8 | sucex 2303 |
. . . . . 6
⊢ suc y
∈ V |
| 10 | 9 | hbsbcv 1447 |
. . . . 5
⊢ ([suc y / x]φ → ∀x[suc y /
x]φ) |
| 11 | 7, 10 | hbim 702 |
. . . 4
⊢ (([y /
x]φ
→ [suc y / x]φ) →
∀x([y / x]φ → [suc y / x]φ)) |
| 12 | 6, 11 | hbim 702 |
. . 3
⊢ ((y
∈ ω → ([y / x]φ →
[suc y / x]φ)) →
∀x(y ∈ ω → ([y / x]φ → [suc y / x]φ))) |
| 13 | | eleq1 1149 |
. . . 4
⊢ (x =
y → (x ∈ ω ↔ y ∈ ω)) |
| 14 | | sbequ12 865 |
. . . . 5
⊢ (x =
y → (φ ↔ [y / x]φ)) |
| 15 | | suceq 2288 |
. . . . . 6
⊢ (x =
y → suc x = suc y) |
| 16 | | dfsbcq 1442 |
. . . . . 6
⊢ (suc x
= suc y → ([suc x / x]φ ↔ [suc y / x]φ)) |
| 17 | 15, 16 | syl 12 |
. . . . 5
⊢ (x =
y → ([suc x / x]φ ↔ [suc y / x]φ)) |
| 18 | 14, 17 | imbi12d 474 |
. . . 4
⊢ (x =
y → ((φ → [suc x / x]φ) ↔ ([y / x]φ → [suc y / x]φ))) |
| 19 | 13, 18 | imbi12d 474 |
. . 3
⊢ (x =
y → ((x ∈ ω → (φ → [suc x / x]φ)) ↔ (y ∈ ω → ([y / x]φ → [suc y / x]φ)))) |
| 20 | | findes.2 |
. . 3
⊢ (x
∈ ω → (φ → [suc
x / x]φ)) |
| 21 | 12, 19, 20 | chv2 850 |
. 2
⊢ (y
∈ ω → ([y / x]φ →
[suc y / x]φ)) |
| 22 | 1, 2, 3, 4, 5, 21 | finds 2397 |
1
⊢ (x
∈ ω → φ) |