Proof of Theorem fvreseq
| Step | Hyp | Ref
| Expression |
| 1 | | fnssres 2734 |
. . . 4
⊢ ((F Fn
A ∧ B ⊆ A)
→ (F ↾ B) Fn B) |
| 2 | | fnssres 2734 |
. . . 4
⊢ ((G Fn
A ∧ B ⊆ A)
→ (G ↾ B) Fn B) |
| 3 | 1, 2 | anim12i 268 |
. . 3
⊢ (((F
Fn A ∧ B ⊆ A)
∧ (G Fn A ∧ B
⊆ A)) → ((F ↾ B) Fn
B ∧ (G ↾ B) Fn
B)) |
| 4 | 3 | anandirs 395 |
. 2
⊢ (((F
Fn A ∧ G Fn A) ∧
B ⊆ A) → ((F
↾ B) Fn B ∧ (G
↾ B) Fn B)) |
| 5 | | cleqfv 2880 |
. . 3
⊢ (((F
↾ B) Fn B ∧ (G
↾ B) Fn B) → ((F
↾ B) = (G ↾ B)
↔ (B = B ∧ ∀x ∈ B
((F ↾ B) ‘x) =
((G ↾ B) ‘x)))) |
| 6 | | fvres 2840 |
. . . . . 6
⊢ (x
∈ B → ((F ↾ B)
‘x) = (F ‘x)) |
| 7 | | fvres 2840 |
. . . . . 6
⊢ (x
∈ B → ((G ↾ B)
‘x) = (G ‘x)) |
| 8 | 6, 7 | cleq12d 1115 |
. . . . 5
⊢ (x
∈ B → (((F ↾ B)
‘x) = ((G ↾ B)
‘x) ↔ (F ‘x) =
(G ‘x))) |
| 9 | 8 | birala 1228 |
. . . 4
⊢ (∀x ∈ B
((F ↾ B) ‘x) =
((G ↾ B) ‘x)
↔ ∀x ∈ B (F
‘x) = (G ‘x)) |
| 10 | | cleqid 1102 |
. . . . 5
⊢ B =
B |
| 11 | 10 | biantrur 544 |
. . . 4
⊢ (∀x ∈ B
((F ↾ B) ‘x) =
((G ↾ B) ‘x)
↔ (B = B ∧ ∀x ∈ B
((F ↾ B) ‘x) =
((G ↾ B) ‘x))) |
| 12 | 9, 11 | bitr3 153 |
. . 3
⊢ (∀x ∈ B
(F ‘x) = (G
‘x) ↔ (B = B ∧
∀x ∈ B ((F ↾
B) ‘x) = ((G ↾
B) ‘x))) |
| 13 | 5, 12 | syl6bbr 416 |
. 2
⊢ (((F
↾ B) Fn B ∧ (G
↾ B) Fn B) → ((F
↾ B) = (G ↾ B)
↔ ∀x ∈ B (F
‘x) = (G ‘x))) |
| 14 | 4, 13 | syl 12 |
1
⊢ (((F
Fn A ∧ G Fn A) ∧
B ⊆ A) → ((F
↾ B) = (G ↾ B)
↔ ∀x ∈ B (F
‘x) = (G ‘x))) |