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Theorem in23 1652
Description: A rearrangement of intersection.
Assertion
Ref Expression
in23 ((AB) ∩ C) = ((AC) ∩ B)

Proof of Theorem in23
StepHypRef Expression
1 incom 1636 . . 3 (BC) = (CB)
21ineq2i 1642 . 2 (A ∩ (BC)) = (A ∩ (CB))
3 inass 1650 . 2 ((AB) ∩ C) = (A ∩ (BC))
4 inass 1650 . 2 ((AC) ∩ B) = (A ∩ (CB))
52, 3, 43eqtr4 1126 1 ((AB) ∩ C) = ((AC) ∩ B)
Colors of variables: wff set class
Syntax hints:   = wceq 1091   ∩ cin 1486
This theorem is referenced by:  wefrc 2195  rescom 2588
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-in 1491
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