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Theorem inssdif0 1754
Description: Intersection, subclass, and difference relationship.
Assertion
Ref Expression
inssdif0 ((AB) ⊆ C ↔ (A ∩ (BC)) = ∅)

Proof of Theorem inssdif0
StepHypRef Expression
1 impexp 276 . . . . 5 (((xAxB) → xC) ↔ (xA → (xBxC)))
2 iman 205 . . . . . 6 ((xBxC) ↔ ¬ (xB ∧ ¬ xC))
32imbi2i 160 . . . . 5 ((xA → (xBxC)) ↔ (xA → ¬ (xB ∧ ¬ xC)))
4 imnan 207 . . . . 5 ((xA → ¬ (xB ∧ ¬ xC)) ↔ ¬ (xA ∧ (xB ∧ ¬ xC)))
51, 3, 43bitr 155 . . . 4 (((xAxB) → xC) ↔ ¬ (xA ∧ (xB ∧ ¬ xC)))
6 elin 1635 . . . . 5 (x ∈ (AB) ↔ (xAxB))
76imbi1i 161 . . . 4 ((x ∈ (AB) → xC) ↔ ((xAxB) → xC))
8 elin 1635 . . . . . 6 (x ∈ (A ∩ (BC)) ↔ (xAx ∈ (BC)))
9 eldif 1496 . . . . . . 7 (x ∈ (BC) ↔ (xB ∧ ¬ xC))
109anbi2i 367 . . . . . 6 ((xAx ∈ (BC)) ↔ (xA ∧ (xB ∧ ¬ xC)))
118, 10bitr 151 . . . . 5 (x ∈ (A ∩ (BC)) ↔ (xA ∧ (xB ∧ ¬ xC)))
1211negbii 162 . . . 4 x ∈ (A ∩ (BC)) ↔ ¬ (xA ∧ (xB ∧ ¬ xC)))
135, 7, 123bitr4 158 . . 3 ((x ∈ (AB) → xC) ↔ ¬ x ∈ (A ∩ (BC)))
1413bial 695 . 2 (∀x(x ∈ (AB) → xC) ↔ ∀x ¬ x ∈ (A ∩ (BC)))
15 dfss2 1497 . 2 ((AB) ⊆ C ↔ ∀x(x ∈ (AB) → xC))
16 eq0 1719 . 2 ((A ∩ (BC)) = ∅ ↔ ∀x ¬ x ∈ (A ∩ (BC)))
1714, 15, 163bitr4 158 1 ((AB) ⊆ C ↔ (A ∩ (BC)) = ∅)
Colors of variables: wff set class
Syntax hints:  ¬ wn 1   → wi 2   ↔ wb 127   ∧ wa 196  ∀wal 672   = wceq 1091   ∈ wcel 1092   ∖ cdif 1484   ∩ cin 1486   ⊆ wss 1487  ∅c0 1707
This theorem is referenced by:  difdisj 1758  inf3lem3 3466
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-dif 1489  df-in 1491  df-ss 1492  df-nul 1708
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