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Theorem inxp 2496
Description: The intersection of two cross products. Exercise 9 of [TakeutiZaring] p. 25.
Assertion
Ref Expression
inxp ((A × B) ∩ (C × D)) = ((AC) × (BD))

Proof of Theorem inxp
StepHypRef Expression
1 relxp 2486 . . 3 Rel (A × B)
2 relin 2491 . . 3 (Rel (A × B) → Rel ((A × B) ∩ (C × D)))
31, 2ax-mp 6 . 2 Rel ((A × B) ∩ (C × D))
4 relxp 2486 . 2 Rel ((AC) × (BD))
5 an4 388 . . . 4 (((xAyB) ∧ (xCyD)) ↔ ((xAxC) ∧ (yByD)))
6 visset 1350 . . . . . 6 yV
76opelxp 2452 . . . . 5 (⟨x, y⟩ ∈ (A × B) ↔ (xAyB))
86opelxp 2452 . . . . 5 (⟨x, y⟩ ∈ (C × D) ↔ (xCyD))
97, 8anbi12i 369 . . . 4 ((⟨x, y⟩ ∈ (A × B) ∧ ⟨x, y⟩ ∈ (C × D)) ↔ ((xAyB) ∧ (xCyD)))
10 elin 1635 . . . . 5 (x ∈ (AC) ↔ (xAxC))
11 elin 1635 . . . . 5 (y ∈ (BD) ↔ (yByD))
1210, 11anbi12i 369 . . . 4 ((x ∈ (AC) ∧ y ∈ (BD)) ↔ ((xAxC) ∧ (yByD)))
135, 9, 123bitr4 158 . . 3 ((⟨x, y⟩ ∈ (A × B) ∧ ⟨x, y⟩ ∈ (C × D)) ↔ (x ∈ (AC) ∧ y ∈ (BD)))
14 elin 1635 . . 3 (⟨x, y⟩ ∈ ((A × B) ∩ (C × D)) ↔ (⟨x, y⟩ ∈ (A × B) ∧ ⟨x, y⟩ ∈ (C × D)))
156opelxp 2452 . . 3 (⟨x, y⟩ ∈ ((AC) × (BD)) ↔ (x ∈ (AC) ∧ y ∈ (BD)))
1613, 14, 153bitr4 158 . 2 (⟨x, y⟩ ∈ ((A × B) ∩ (C × D)) ↔ ⟨x, y⟩ ∈ ((AC) × (BD)))
173, 4, 16cleqreli 2484 1 ((A × B) ∩ (C × D)) = ((AC) × (BD))
Colors of variables: wff set class
Syntax hints:   ∧ wa 196   = wceq 1091   ∈ wcel 1092   ∩ cin 1486  ⟨cop 1810   × cxp 2408  Rel wrel 2415
This theorem is referenced by:  xpindi 2497  xpindir 2498  resabs1 2592  xpdisj1 2653  xpdisj2 2654
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-13 804  ax-14 805  ax-16 922  ax-17 925  ax-ext 1074  ax-rep 1075  ax-pow 1077
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-v 1349  df-dif 1489  df-un 1490  df-in 1491  df-ss 1492  df-nul 1708  df-pw 1799  df-sn 1811  df-pr 1812  df-op 1815  df-opab 2098  df-xp 2424  df-rel 2425
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