Proof of Theorem iunrab
| Step | Hyp | Ref
| Expression |
| 1 | | df-rab 1208 |
. 2
⊢ {z
∈ B∣∃x ∈ A
[z / y]φ} =
{z∣(z ∈ B ∧
∃x ∈ A [z / y]φ)} |
| 2 | | ax-17 925 |
. . 3
⊢ (x
∈ B → ∀y x ∈
B) |
| 3 | | ax-17 925 |
. . 3
⊢ (x
∈ B → ∀z x ∈
B) |
| 4 | | ax-17 925 |
. . 3
⊢ (∃x ∈ A φ → ∀z∃x ∈
A φ) |
| 5 | | ax-17 925 |
. . . 4
⊢ (x
∈ A → ∀y x ∈
A) |
| 6 | | hbs1 986 |
. . . 4
⊢ ([z /
y]φ
→ ∀y[z / y]φ) |
| 7 | 5, 6 | hbrex 1238 |
. . 3
⊢ (∃x ∈ A
[z / y]φ →
∀y∃x ∈ A
[z / y]φ) |
| 8 | | sbequ12 865 |
. . . 4
⊢ (y =
z → (φ ↔ [z / y]φ)) |
| 9 | 8 | birexdv 1220 |
. . 3
⊢ (y =
z → (∃x ∈ A φ ↔ ∃x ∈ A
[z / y]φ)) |
| 10 | 2, 3, 4, 7, 9 | cbvrab 1425 |
. 2
⊢ {y
∈ B∣∃x ∈ A φ} = {z
∈ B∣∃x ∈ A
[z / y]φ} |
| 11 | | eliun 1998 |
. . . 4
⊢ (z
∈ ∪x ∈
A {y
∈ B∣φ} ↔ ∃x ∈ A
z ∈ {y ∈ B∣φ}) |
| 12 | 2 | elrabsf 1456 |
. . . . 5
⊢ (z
∈ {y ∈ B∣φ}
↔ (z ∈ B ∧ [z /
y]φ)) |
| 13 | 12 | birex 1224 |
. . . 4
⊢ (∃x ∈ A
z ∈ {y ∈ B∣φ}
↔ ∃x ∈ A (z ∈
B ∧ [z / y]φ)) |
| 14 | | r19.42v 1303 |
. . . 4
⊢ (∃x ∈ A
(z ∈ B ∧ [z /
y]φ) ↔ (z ∈ B ∧
∃x ∈ A [z / y]φ)) |
| 15 | 11, 13, 14 | 3bitr 155 |
. . 3
⊢ (z
∈ ∪x ∈
A {y
∈ B∣φ} ↔ (z ∈ B ∧
∃x ∈ A [z / y]φ)) |
| 16 | 15 | biabri 1180 |
. 2
⊢ ∪x ∈ A
{y ∈ B∣φ} =
{z∣(z ∈ B ∧
∃x ∈ A [z / y]φ)} |
| 17 | 1, 10, 16 | 3eqtr4r 1127 |
1
⊢ ∪x ∈ A
{y ∈ B∣φ} =
{y ∈ B∣∃x
∈ A φ} |