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Theorem iunxun 2035
Description: Separate a union in the index of an indexed union.
Assertion
Ref Expression
iunxun x ∈ (AB)C = (xA CxB C)

Proof of Theorem iunxun
StepHypRef Expression
1 df-rex 1206 . . . 4 (∃x ∈ (AB)yC ↔ ∃x(x ∈ (AB) ∧ yC))
2 elun 1601 . . . . . . 7 (x ∈ (AB) ↔ (xAxB))
32anbi1i 368 . . . . . 6 ((x ∈ (AB) ∧ yC) ↔ ((xAxB) ∧ yC))
4 andir 457 . . . . . 6 (((xAxB) ∧ yC) ↔ ((xAyC) ∨ (xByC)))
53, 4bitr 151 . . . . 5 ((x ∈ (AB) ∧ yC) ↔ ((xAyC) ∨ (xByC)))
65biex 733 . . . 4 (∃x(x ∈ (AB) ∧ yC) ↔ ∃x((xAyC) ∨ (xByC)))
7 19.43 767 . . . . 5 (∃x((xAyC) ∨ (xByC)) ↔ (∃x(xAyC) ∨ ∃x(xByC)))
8 eliun 1998 . . . . . . 7 (yxA C ↔ ∃xA yC)
9 df-rex 1206 . . . . . . 7 (∃xA yC ↔ ∃x(xAyC))
108, 9bitr 151 . . . . . 6 (yxA C ↔ ∃x(xAyC))
11 eliun 1998 . . . . . . 7 (yxB C ↔ ∃xB yC)
12 df-rex 1206 . . . . . . 7 (∃xB yC ↔ ∃x(xByC))
1311, 12bitr 151 . . . . . 6 (yxB C ↔ ∃x(xByC))
1410, 13orbi12i 216 . . . . 5 ((yxA CyxB C) ↔ (∃x(xAyC) ∨ ∃x(xByC)))
157, 14bitr4 154 . . . 4 (∃x((xAyC) ∨ (xByC)) ↔ (yxA CyxB C))
161, 6, 153bitr 155 . . 3 (∃x ∈ (AB)yC ↔ (yxA CyxB C))
17 eliun 1998 . . 3 (yx ∈ (AB)C ↔ ∃x ∈ (AB)yC)
18 elun 1601 . . 3 (y ∈ (xA CxB C) ↔ (yxA CyxB C))
1916, 17, 183bitr4 158 . 2 (yx ∈ (AB)Cy ∈ (xA CxB C))
2019cleqri 1101 1 x ∈ (AB)C = (xA CxB C)
Colors of variables: wff set class
Syntax hints:   ∨ wo 195   ∧ wa 196  ∃wex 678   = wceq 1091   ∈ wcel 1092  ∃wrex 1202   ∪ cun 1485  ciun 1994
This theorem is referenced by:  kmlem10 3589
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-16 922  ax-17 925  ax-ext 1074
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-ex 679  df-sb 853  df-clab 1093  df-cleq 1097  df-clel 1099  df-rex 1206  df-v 1349  df-un 1490  df-iun 1996
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