Proof of Theorem ltdivt
| Step | Hyp | Ref
| Expression |
| 1 | | breq1 2065 |
. . . 4
⊢ (A =
if(A ∈ ℝ, A, 0) → (A
< B ↔ if(A ∈ ℝ, A, 0) < B)) |
| 2 | | opreq1 3006 |
. . . . 5
⊢ (A =
if(A ∈ ℝ, A, 0) → (A
/ C) = (if(A ∈ ℝ, A, 0) / C)) |
| 3 | 2 | breq1d 2071 |
. . . 4
⊢ (A =
if(A ∈ ℝ, A, 0) → ((A
/ C) < (B / C) ↔
(if(A ∈ ℝ, A, 0) / C) <
(B / C))) |
| 4 | 1, 3 | bibi12d 477 |
. . 3
⊢ (A =
if(A ∈ ℝ, A, 0) → ((A
< B ↔ (A / C) <
(B / C)) ↔ (if(A
∈ ℝ, A, 0) < B ↔ (if(A
∈ ℝ, A, 0) / C) < (B /
C)))) |
| 5 | 4 | imbi2d 464 |
. 2
⊢ (A =
if(A ∈ ℝ, A, 0) → ((0 < C → (A <
B ↔ (A / C) <
(B / C))) ↔ (0 < C → (if(A
∈ ℝ, A, 0) < B ↔ (if(A
∈ ℝ, A, 0) / C) < (B /
C))))) |
| 6 | | breq2 2066 |
. . . 4
⊢ (B =
if(B ∈ ℝ, B, 0) → (if(A ∈ ℝ, A, 0) < B
↔ if(A ∈ ℝ, A, 0) < if(B
∈ ℝ, B, 0))) |
| 7 | | opreq1 3006 |
. . . . 5
⊢ (B =
if(B ∈ ℝ, B, 0) → (B
/ C) = (if(B ∈ ℝ, B, 0) / C)) |
| 8 | 7 | breq2d 2072 |
. . . 4
⊢ (B =
if(B ∈ ℝ, B, 0) → ((if(A ∈ ℝ, A, 0) / C) <
(B / C)
↔ (if(A ∈ ℝ, A, 0) / C) <
(if(B ∈ ℝ, B, 0) / C))) |
| 9 | 6, 8 | bibi12d 477 |
. . 3
⊢ (B =
if(B ∈ ℝ, B, 0) → ((if(A ∈ ℝ, A, 0) < B
↔ (if(A ∈ ℝ, A, 0) / C) <
(B / C)) ↔ (if(A
∈ ℝ, A, 0) < if(B ∈ ℝ, B, 0) ↔ (if(A ∈ ℝ, A, 0) / C) <
(if(B ∈ ℝ, B, 0) / C)))) |
| 10 | 9 | imbi2d 464 |
. 2
⊢ (B =
if(B ∈ ℝ, B, 0) → ((0 < C → (if(A
∈ ℝ, A, 0) < B ↔ (if(A
∈ ℝ, A, 0) / C) < (B /
C))) ↔ (0 < C → (if(A
∈ ℝ, A, 0) < if(B ∈ ℝ, B, 0) ↔ (if(A ∈ ℝ, A, 0) / C) <
(if(B ∈ ℝ, B, 0) / C))))) |
| 11 | | breq2 2066 |
. . 3
⊢ (C =
if(C ∈ ℝ, C, 0) → (0 < C ↔ 0 < if(C ∈ ℝ, C, 0))) |
| 12 | | opreq2 3007 |
. . . . 5
⊢ (C =
if(C ∈ ℝ, C, 0) → (if(A ∈ ℝ, A, 0) / C) =
(if(A ∈ ℝ, A, 0) / if(C
∈ ℝ, C, 0))) |
| 13 | | opreq2 3007 |
. . . . 5
⊢ (C =
if(C ∈ ℝ, C, 0) → (if(B ∈ ℝ, B, 0) / C) =
(if(B ∈ ℝ, B, 0) / if(C
∈ ℝ, C, 0))) |
| 14 | 12, 13 | breq12d 2073 |
. . . 4
⊢ (C =
if(C ∈ ℝ, C, 0) → ((if(A ∈ ℝ, A, 0) / C) <
(if(B ∈ ℝ, B, 0) / C)
↔ (if(A ∈ ℝ, A, 0) / if(C
∈ ℝ, C, 0)) < (if(B ∈ ℝ, B, 0) / if(C
∈ ℝ, C, 0)))) |
| 15 | 14 | bibi2d 470 |
. . 3
⊢ (C =
if(C ∈ ℝ, C, 0) → ((if(A ∈ ℝ, A, 0) < if(B
∈ ℝ, B, 0) ↔ (if(A ∈ ℝ, A, 0) / C) <
(if(B ∈ ℝ, B, 0) / C))
↔ (if(A ∈ ℝ, A, 0) < if(B
∈ ℝ, B, 0) ↔ (if(A ∈ ℝ, A, 0) / if(C
∈ ℝ, C, 0)) < (if(B ∈ ℝ, B, 0) / if(C
∈ ℝ, C, 0))))) |
| 16 | 11, 15 | imbi12d 474 |
. 2
⊢ (C =
if(C ∈ ℝ, C, 0) → ((0 < C → (if(A
∈ ℝ, A, 0) < if(B ∈ ℝ, B, 0) ↔ (if(A ∈ ℝ, A, 0) / C) <
(if(B ∈ ℝ, B, 0) / C)))
↔ (0 < if(C ∈ ℝ,
C, 0) → (if(A ∈ ℝ, A, 0) < if(B
∈ ℝ, B, 0) ↔ (if(A ∈ ℝ, A, 0) / if(C
∈ ℝ, C, 0)) < (if(B ∈ ℝ, B, 0) / if(C
∈ ℝ, C, 0)))))) |
| 17 | | ax0re 4063 |
. . . 4
⊢ 0 ∈ ℝ |
| 18 | 17 | elimel 1793 |
. . 3
⊢ if(A
∈ ℝ, A, 0) ∈
ℝ |
| 19 | 17 | elimel 1793 |
. . 3
⊢ if(B
∈ ℝ, B, 0) ∈
ℝ |
| 20 | 17 | elimel 1793 |
. . 3
⊢ if(C
∈ ℝ, C, 0) ∈
ℝ |
| 21 | 18, 19, 20 | ltdiv 4399 |
. 2
⊢ (0 < if(C ∈ ℝ, C, 0) → (if(A ∈ ℝ, A, 0) < if(B
∈ ℝ, B, 0) ↔ (if(A ∈ ℝ, A, 0) / if(C
∈ ℝ, C, 0)) < (if(B ∈ ℝ, B, 0) / if(C
∈ ℝ, C, 0)))) |
| 22 | 5, 10, 16, 21 | dedth3h 1788 |
1
⊢ ((A
∈ ℝ ∧ B ∈ ℝ ∧
C ∈ ℝ) → (0 < C → (A <
B ↔ (A / C) <
(B / C)))) |