Proof of Theorem ltexpri
| Step | Hyp | Ref
| Expression |
| 1 | | ltexpri.1 |
. . 3
⊢ B
∈ V |
| 2 | | ltrelpr 3895 |
. . 3
⊢ <P ⊆
(P × P) |
| 3 | 1, 2 | brel 2459 |
. 2
⊢ (A<P B → (A
∈ P ∧ B ∈
P)) |
| 4 | | ltprord 3928 |
. . . 4
⊢ ((A
∈ P ∧ B ∈
P) → (A<P B ↔ A ⊂
B)) |
| 5 | | opreq2 3007 |
. . . . . . . 8
⊢ (x =
{y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)}
→ (A +P
x) = (A
+P {y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)})) |
| 6 | 5 | cleq1d 1109 |
. . . . . . 7
⊢ (x =
{y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)}
→ ((A +P
x) = B
↔ (A +P
{y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)}) =
B)) |
| 7 | 6 | cla4egv 1397 |
. . . . . 6
⊢ ({y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)}
∈ P → ((A
+P {y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)}) =
B → ∃x(A
+P x) = B)) |
| 8 | | opreq2 3007 |
. . . . . . . . . . . 12
⊢ (y =
z → (w +Q y) = (w
+Q z)) |
| 9 | 8 | eleq1d 1155 |
. . . . . . . . . . 11
⊢ (y =
z → ((w +Q y) ∈ B
↔ (w +Q
z) ∈ B)) |
| 10 | 9 | anbi2d 468 |
. . . . . . . . . 10
⊢ (y =
z → ((¬ w ∈ A ∧
(w +Q y) ∈ B)
↔ (¬ w ∈ A ∧ (w
+Q z) ∈
B))) |
| 11 | 10 | biexdv 936 |
. . . . . . . . 9
⊢ (y =
z → (∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)
↔ ∃w(¬ w ∈ A ∧
(w +Q z) ∈ B))) |
| 12 | 11 | cbvabv 1424 |
. . . . . . . 8
⊢ {y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)} =
{z∣∃w(¬ w ∈
A ∧ (w +Q z) ∈ B)} |
| 13 | 12 | ltexprlem5 3940 |
. . . . . . 7
⊢ ((B
∈ P ∧ A ⊂
B) → {y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)}
∈ P) |
| 14 | 13 | adantll 309 |
. . . . . 6
⊢ (((A
∈ P ∧ B ∈
P) ∧ A ⊂ B) → {y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)}
∈ P) |
| 15 | 12 | ltexprlem6 3941 |
. . . . . . 7
⊢ (((A
∈ P ∧ B ∈
P) ∧ A ⊂ B) → (A
+P {y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)})
⊆ B) |
| 16 | 12 | ltexprlem7 3942 |
. . . . . . 7
⊢ (((A
∈ P ∧ B ∈
P) ∧ A ⊂ B) → B
⊆ (A +P
{y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)})) |
| 17 | 15, 16 | eqssd 1518 |
. . . . . 6
⊢ (((A
∈ P ∧ B ∈
P) ∧ A ⊂ B) → (A
+P {y∣∃w(¬ w ∈
A ∧ (w +Q y) ∈ B)}) =
B) |
| 18 | 7, 14, 17 | sylc 62 |
. . . . 5
⊢ (((A
∈ P ∧ B ∈
P) ∧ A ⊂ B) → ∃x(A
+P x) = B) |
| 19 | 18 | exp 291 |
. . . 4
⊢ ((A
∈ P ∧ B ∈
P) → (A ⊂ B → ∃x(A
+P x) = B)) |
| 20 | 4, 19 | sylbid 178 |
. . 3
⊢ ((A
∈ P ∧ B ∈
P) → (A<P B → ∃x(A
+P x) = B)) |
| 21 | | eleq1 1149 |
. . . . . . . 8
⊢ ((A
+P x) = B → ((A
+P x) ∈
P ↔ B ∈
P)) |
| 22 | | visset 1350 |
. . . . . . . . . 10
⊢ x
∈ V |
| 23 | | dmplp 3909 |
. . . . . . . . . 10
⊢ dom +P =
(P × P) |
| 24 | | 0npr 3890 |
. . . . . . . . . 10
⊢ ¬ ∅ ∈
P |
| 25 | 22, 23, 24 | ndmoprrcl 3060 |
. . . . . . . . 9
⊢ ((A
+P x) ∈
P → (A ∈
P ∧ x ∈
P)) |
| 26 | 25 | pm3.27d 262 |
. . . . . . . 8
⊢ ((A
+P x) ∈
P → x ∈
P) |
| 27 | 21, 26 | syl6bir 188 |
. . . . . . 7
⊢ ((A
+P x) = B → (B
∈ P → x ∈
P)) |
| 28 | 27 | com12 13 |
. . . . . 6
⊢ (B
∈ P → ((A
+P x) = B → x
∈ P)) |
| 29 | 28 | adantl 305 |
. . . . 5
⊢ ((A
∈ P ∧ B ∈
P) → ((A
+P x) = B → x
∈ P)) |
| 30 | 29 | ancrd 247 |
. . . 4
⊢ ((A
∈ P ∧ B ∈
P) → ((A
+P x) = B → (x
∈ P ∧ (A
+P x) = B))) |
| 31 | 30 | 19.22dv 947 |
. . 3
⊢ ((A
∈ P ∧ B ∈
P) → (∃x(A +P x) = B →
∃x(x ∈ P ∧ (A +P x) = B))) |
| 32 | 20, 31 | syld 27 |
. 2
⊢ ((A
∈ P ∧ B ∈
P) → (A<P B → ∃x(x ∈
P ∧ (A
+P x) = B))) |
| 33 | 3, 32 | mpcom 49 |
1
⊢ (A<P B → ∃x(x ∈
P ∧ (A
+P x) = B)) |