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Theorem map0 3268
Description: Set exponentiation is empty iff the base is empty and the exponent is not empty. Theorem 97 of [Suppes] p. 89.
Hypotheses
Ref Expression
map0.1 AV
map0.2 BV
Assertion
Ref Expression
map0 ((Am B) = ∅ ↔ (A = ∅ ∧ ¬ B = ∅))

Proof of Theorem map0
StepHypRef Expression
1 map0.1 . . . . . 6 AV
2 map0.2 . . . . . 6 BV
31, 2mapval 3264 . . . . 5 (Am B) = {ff:B–→A}
43cleq1i 1108 . . . 4 ((Am B) = ∅ ↔ {ff:B–→A} = ∅)
5 snssi 1851 . . . . . . . 8 (xA → {x} ⊆ A)
6 visset 1350 . . . . . . . . . 10 xV
76fconst 2774 . . . . . . . . 9 (B × {x}):B–→{x}
8 fss 2759 . . . . . . . . 9 (((B × {x}):B–→{x} ∧ {x} ⊆ A) → (B × {x}):B–→A)
97, 8mpan 518 . . . . . . . 8 ({x} ⊆ A → (B × {x}):B–→A)
10 snex 1859 . . . . . . . . . 10 {x} ∈ V
112, 10xpex 2488 . . . . . . . . 9 (B × {x}) ∈ V
12 feq1 2748 . . . . . . . . 9 (f = (B × {x}) → (f:B–→A ↔ (B × {x}):B–→A))
1311, 12cla4ev 1401 . . . . . . . 8 ((B × {x}):B–→A → ∃f f:B–→A)
145, 9, 133syl 21 . . . . . . 7 (xA → ∃f f:B–→A)
151419.23aiv 952 . . . . . 6 (∃x xA → ∃f f:B–→A)
16 n0 1714 . . . . . 6 A = ∅ ↔ ∃x xA)
17 abn0 1715 . . . . . 6 (¬ {ff:B–→A} = ∅ ↔ ∃f f:B–→A)
1815, 16, 173imtr4 192 . . . . 5 A = ∅ → ¬ {ff:B–→A} = ∅)
1918a3i 69 . . . 4 ({ff:B–→A} = ∅ → A = ∅)
204, 19sylbi 174 . . 3 ((Am B) = ∅ → A = ∅)
21 0nep0 1887 . . . . . 6 ¬ ∅ = {∅}
221map0e 3266 . . . . . . . 8 (Am ∅) = 1o
2322cleq1i 1108 . . . . . . 7 ((Am ∅) = ∅ ↔ 1o = ∅)
24 df1o2 3111 . . . . . . . 8 1o = {∅}
2524cleq1i 1108 . . . . . . 7 (1o = ∅ ↔ {∅} = ∅)
26 cleqcom 1103 . . . . . . 7 ({∅} = ∅ ↔ ∅ = {∅})
2723, 25, 263bitr 155 . . . . . 6 ((Am ∅) = ∅ ↔ ∅ = {∅})
2821, 27mtbir 167 . . . . 5 ¬ (Am ∅) = ∅
29 opreq2 3007 . . . . . 6 (B = ∅ → (Am B) = (Am ∅))
3029cleq1d 1109 . . . . 5 (B = ∅ → ((Am B) = ∅ ↔ (Am ∅) = ∅))
3128, 30mtbiri 539 . . . 4 (B = ∅ → ¬ (Am B) = ∅)
3231con2i 89 . . 3 ((Am B) = ∅ → ¬ B = ∅)
3320, 32jca 236 . 2 ((Am B) = ∅ → (A = ∅ ∧ ¬ B = ∅))
34 opreq1 3006 . . 3 (A = ∅ → (Am B) = (∅ ↑m B))
352map0b 3267 . . 3 B = ∅ → (∅ ↑m B) = ∅)
3634, 35sylan9eq 1144 . 2 ((A = ∅ ∧ ¬ B = ∅) → (Am B) = ∅)
3733, 36impbi 139 1 ((Am B) = ∅ ↔ (A = ∅ ∧ ¬ B = ∅))
Colors of variables: wff set class
Syntax hints:  ¬ wn 1   ↔ wb 127   ∧ wa 196  ∃wex 678  {cab 1090   = wceq 1091   ∈ wcel 1092  Vcvv 1348   ⊆ wss 1487  ∅c0 1707  {csn 1808   × cxp 2408  –→wf 2418  (class class class)co 3001  1oc1o 3099   ↑m cm 3258
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6  ax-4 673  ax-5 674  ax-6 675  ax-7 676  ax-gen 677  ax-8 798  ax-9 799  ax-10 800  ax-11 801  ax-12 802  ax-13 804  ax-14 805  ax-16 922  ax-17 925  ax-ext 1074  ax-rep 1075  ax-un 1076  ax-pow 1077
This theorem depends on definitions:  df-bi 128  df-or 197  df-an 198  df-3an 583  df-ex 679  df-sb 853  df-eu 1009  df-mo 1010  df-clab 1093  df-cleq 1097  df-clel 1099  df-ral 1205  df-rex 1206  df-v 1349  df-dif 1489  df-un 1490  df-in 1491  df-ss 1492  df-nul 1708  df-pw 1799  df-sn 1811  df-pr 1812  df-op 1815  df-uni 1920  df-br 2063  df-opab 2098  df-id 2125  df-suc 2205  df-xp 2424  df-rel 2425  df-cnv 2426  df-co 2427  df-dm 2428  df-rn 2429  df-res 2430  df-ima 2431  df-fun 2432  df-fn 2433  df-f 2434  df-fv 2438  df-opr 3003  df-oprab 3004  df-1o 3104  df-map 3259
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