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Theorem merlem10 654
Description: Step 19 of Meredith's proof of Lukasiewicz axioms from his sole axiom.
Assertion
Ref Expression
merlem10 ((φ → (φψ)) → (θ → (φψ)))

Proof of Theorem merlem10
StepHypRef Expression
1 meredith 644 . 2 (((((φφ) → (¬ φ → ¬ φ)) → φ) → φ) → ((φφ) → (φφ)))
2 meredith 644 . . 3 ((((((φψ) → φ) → (¬ φ → ¬ θ)) → φ) → φ) → ((φ → (φψ)) → (θ → (φψ))))
3 merlem9 653 . . 3 (((((((φψ) → φ) → (¬ φ → ¬ θ)) → φ) → φ) → ((φ → (φψ)) → (θ → (φψ)))) → ((((((φφ) → (¬ φ → ¬ φ)) → φ) → φ) → ((φφ) → (φφ))) → ((φ → (φψ)) → (θ → (φψ)))))
42, 3ax-mp 6 . 2 ((((((φφ) → (¬ φ → ¬ φ)) → φ) → φ) → ((φφ) → (φφ))) → ((φ → (φψ)) → (θ → (φψ))))
51, 4ax-mp 6 1 ((φ → (φψ)) → (θ → (φψ)))
Colors of variables: wff set class
Syntax hints:  ¬ wn 1   → wi 2
This theorem is referenced by:  merlem11 655
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6
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