HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
GIF version

Theorem merlem2 646
Description: Step 4 of Meredith's proof of Lukasiewicz axioms from his sole axiom.
Assertion
Ref Expression
merlem2 (((φφ) → χ) → (θχ))

Proof of Theorem merlem2
StepHypRef Expression
1 merlem1 645 . 2 ((((χχ) → (¬ φ → ¬ θ)) → φ) → (φφ))
2 meredith 644 . 2 (((((χχ) → (¬ φ → ¬ θ)) → φ) → (φφ)) → (((φφ) → χ) → (θχ)))
31, 2ax-mp 6 1 (((φφ) → χ) → (θχ))
Colors of variables: wff set class
Syntax hints:  ¬ wn 1   → wi 2
This theorem is referenced by:  merlem3 647  merlem12 656
This theorem was proved from axioms:  ax-1 3  ax-2 4  ax-3 5  ax-mp 6
metamath.org