HomeHome Metamath Proof Explorer < Previous   Next >
Bad symbols? Use Mozilla
(or GIF version for IE).

Jump to page: 1 1-100 2 101-200 3 201-300 4 301-400 5 401-500 6 501-600 7 601-700 8 701-800 9 801-900 10 901-1000 11 1001-1100 12 1101-1200 13 1201-1300 14 1301-1400 15 1401-1500 16 1501-1600 17 1601-1700 18 1701-1800 19 1801-1900 20 1901-2000 21 2001-2100 22 2101-2200 23 2201-2300 24 2301-2400 25 2401-2500 26 2501-2600 27 2601-2700 28 2701-2800 29 2801-2900 30 2901-3000 31 3001-3100 32 3101-3200 33 3201-3300 34 3301-3400 35 3401-3500 36 3501-3600 37 3601-3700 38 3701-3800 39 3801-3900 40 3901-4000 41 4001-4100 42 4101-4200 43 4201-4300 44 4301-4400 45 4401-4500 46 4501-4600 47 4601-4700 48 4701-4800 49 4801-4900 50 4901-5000 51 5001-5100 52 5101-5200 53 5201-5300 54 5301-5400 55 5401-5500 56 5501-5600 57 5601-5700 58 5701-5787

Color key:    Metamath Proof
Explorer  Metamath Proof Explorer (1-4957)   Hilbert Space Explorer  Hilbert Space Explorer (4958-5787)  

Statement List for Metamath Proof Explorer - 2401-2500 - Page 25 of 58
TypeLabelDescription
Statement
 
Theoremtfinds 2401 Principle of Transfinite Induction (inference schema) with implicit substitutions. The first four hypotheses establish the substitutions we need. The last three are the basis, the induction hypothesis for successors, and the induction hypothesis for limit ordinals. Theorem Schema 4 of [Suppes] p. 197.
(x = ∅ → (φψ))    &   (x = y → (φχ))    &   (x = suc y → (φθ))    &   (x = A → (φτ))    &   ψ    &   (y ∈ On → (χθ))    &   (Lim x → (∀yx χφ))    ⇒   (A ∈ On → τ)
 
Theoremtfindsg 2402 Transfinite Induction (inference schema) with implicit substitutions. The first four hypotheses establish the substitutions we need. The last three are the basis, the induction hypothesis for successors, and the induction hypothesis for limit ordinals. The basis of this version is an arbitrary ordinal B instead of zero. Remark of [TakeutiZaring] p. 57.
(x = B → (φψ))    &   (x = y → (φχ))    &   (x = suc y → (φθ))    &   (x = A → (φτ))    &   (B ∈ On → ψ)    &   (((y ∈ On ∧ B ∈ On) ∧ By) → (χθ))    &   (((Lim xB ∈ On) ∧ Bx) → (∀yx (Byχ) → φ))    ⇒   (((A ∈ On ∧ B ∈ On) ∧ BA) → τ)
 
Theoremtfindsg2 2403 Transfinite Induction (inference schema) with implicit substitutions. The first four hypotheses establish the substitutions we need. The last three are the basis, the induction hypothesis for successors, and the induction hypothesis for limit ordinals. The basis of this version is an arbitrary ordinal suc B instead of zero.
(x = suc B → (φψ))    &   (x = y → (φχ))    &   (x = suc y → (φθ))    &   (x = A → (φτ))    &   (B ∈ On → ψ)    &   ((y ∈ On ∧ By) → (χθ))    &   ((Lim xBx) → (∀yx (Byχ) → φ))    ⇒   ((A ∈ On ∧ BA) → τ)
 
Theoremtfindes 2404 Transfinite Induction with explicit substitution. The first hypothesis is the basis, the second is the induction hypothesis for successors, and the third is the induction hypothesis for limit ordinals. Theorem Schema 4 of [Suppes] p. 197.
[∅ / x]φ    &   (x ∈ On → (φ → [suc x / x]φ))    &   (Lim y → (∀xy φ → [y / x]φ))    ⇒   (x ∈ On → φ)
 
Theoremtfinds2 2405 Transfinite Induction (inference schema) with implicit substitutions. The first three hypotheses establish the substitutions we need. The last three are the basis and the induction hypotheses (for successor and limit ordinals respectively). Theorem Schema 4 of [Suppes] p. 197. The wff τ is an auxiliary antecedent to help shorten proofs using this theorem.
(x = ∅ → (φψ))    &   (x = y → (φχ))    &   (x = suc y → (φθ))    &   (τψ)    &   (y ∈ On → (τ → (χθ)))    &   (Lim x → (τ → (∀yx χφ)))    ⇒   (x ∈ On → (τφ))
 
Theoremtfinds3 2406 Principle of Transfinite Induction (inference schema) with implicit substitutions. The first four hypotheses establish the substitutions we need. The last three are the basis, the induction hypothesis for successors, and the induction hypothesis for limit ordinals.
(x = ∅ → (φψ))    &   (x = y → (φχ))    &   (x = suc y → (φθ))    &   (x = A → (φτ))    &   (ηψ)    &   (y ∈ On → (η → (χθ)))    &   (Lim x → (η → (∀yx χφ)))    ⇒   (A ∈ On → (ητ))
 
Theoremssnlim 2407 An ordinal subclass of non-limit ordinals is a class of natural numbers. Exercise 7 of [TakeutiZaring] p. 42.
((Ord AA ⊆ {x ∈ On∣ ¬ Lim x}) → A ⊆ ω)
 
Syntaxcxp 2408 Extend the definition of a class to include the cross product.
class (A × B)
 
Syntaxccnv 2409 Extend the definition of a class to include the converse of a class.
class A
 
Syntaxcdm 2410 Extend the definition of a class to include the domain of a class.
class dom A
 
Syntaxcrn 2411 Extend the definition of a class to include the range of a class.
class ran A
 
Syntaxcres 2412 Extend the definition of a class to include the restriction of a class. (Read: The restriction of A to B.)
class (AB)
 
Syntaxcima 2413 Extend the definition of a class to include the image of a class. (Read: The image of B under A.)
class (AB)
 
Syntaxccom 2414 Extend the definition of a class to include the composition of two classes. (Read: The composition of A and B.)
class (AB)
 
Syntaxwrel 2415 Extend the definition of a wff to include the relation predicate. (Read: A is a relation.)
wff Rel A
 
Syntaxwfun 2416 Extend the definition of a wff to include the function predicate. (Read: A is a function.)
wff Fun A
 
Syntaxwfn 2417 Extend the definition of a wff to include the function predicate with a domain. (Read: A is a function on B.)
wff A Fn B
 
Syntaxwf 2418 Extend the definition of a wff to include the function predicate with domain and range. (Read: F maps A into B.)
wff F:A–→B
 
Syntaxwf1 2419 Extend the definition of a wff to include one-to-one functions. (Read: F maps A one-to-one into B.)
wff F:A1-1B
 
Syntaxwfo 2420 Extend the definition of a wff to include onto functions. (Read: F maps A onto B.)
wff F:AontoB
 
Syntaxwf1o 2421 Extend the definition of a wff to include one-to-one onto functions. (Read: F maps A one-to-one onto B.)
wff F:A1-1-ontoB
 
Syntaxcfv 2422 Extend the definition of a class to include the value of a function. (Read: The value of F at A, or "F of A".)
class (FA)
 
Syntaxwiso 2423 Extend the definition of a wff to include the isomorphism property. (Read: H is an R, S isomorphism of A onto B.)
wff H Isom R, S (A, B)
 
Definitiondf-xp 2424 Define the cross product of two classes. Definition 9.11 of [Quine] p. 64.
(A × B) = {⟨x, y⟩∣(xAyB)}
 
Definitiondf-rel 2425 Define a relation. Definition 6.4(1) of [TakeutiZaring] p. 23. For an alternate definition, see dfrel2 2660.
(Rel AA ⊆ (V × V))
 
Definitiondf-cnv 2426 Define the converse of a class. Definition 9.12 of [Quine] p. 64. We use Quine's breve accent (smile) notation; as a prefix, it eliminates parentheses for us. Many authors use the postfix superscript "to the minus one".
A = {⟨x, y⟩∣yAx}
 
Definitiondf-co 2427 Define the composition of two classes. Definition 6.6(3) of [TakeutiZaring] p. 24. Note that Definition 7 of [Suppes] p. 63 reverses A and B, uses / instead of ∘, and calls the operation "relative product."
(AB) = {⟨x, y⟩∣∃z(xBzzAy)}
 
Definitiondf-dm 2428 Define the domain of a class. Definition 3 of [Suppes] p. 59.
dom A = {x∣∃y xAy}
 
Definitiondf-rn 2429 Define the range of a class. For an alternate definition, see dfrn2 2523.
ran A = dom A
 
Definitiondf-res 2430 Define the restriction of a class. Definition 6.6(1) of [TakeutiZaring] p. 24.
(AB) = (A ∩ (B × V))
 
Definitiondf-ima 2431 Define the image of a class. Definition 6.6(2) of [TakeutiZaring] p. 24. For an alternate definition, see dfima2 2604.
(AB) = ran (AB)
 
Definitiondf-fun 2432 Define a function. Definition 10.1 of [Quine] p. 65. For alternate definitions, see dffun2 2674, dffun3 2675, dffun4 2676, dffun5 2677, dffunmo 2679, dffun6 2687, and dffun7 2688.
(Fun A ↔ (Rel A ∧ (AA) ⊆ I))
 
Definitiondf-fn 2433 Define a function with domain. Definition 6.15(1) of [TakeutiZaring] p. 27.
(A Fn B ↔ (Fun A ∧ dom A = B))
 
Definitiondf-f 2434 Define a function (mapping) with domain and co-domain. Definition 6.15(3) of [TakeutiZaring] p. 27.
(F:A–→B ↔ (F Fn A ∧ ran FB))
 
Definitiondf-f1 2435 Define a one-to-one function. For an equivalent definition see f11 2780. Compare Definition 6.15(5) of [TakeutiZaring] p. 27.
(F:A1-1B ↔ (F:A–→B ∧ Fun F))
 
Definitiondf-fo 2436 Define an onto function. Definition 6.15(4) of [TakeutiZaring] p. 27.
(F:AontoB ↔ (F Fn A ∧ ran F = B))
 
Definitiondf-f1o 2437 Define a one-to-one onto function. For equivalent definitions see f1o2 2804, f1o3 2805, f1o4 2807, and f1o5 2808. Compare Definition 6.15(6) of [TakeutiZaring] p. 27.
(F:A1-1-ontoB ↔ (F:A1-1BF:AontoB))
 
Definitiondf-fv 2438 Define the value of a function. Although it has roots in Definition 10.2 of [Quine] p. 65, our definition apparently does not appear in the literature but is quite convenient: it can be applied to any class and evaluates to the empty set when it is not meaningful. The left apostrophe notation is common in set theory and means the same thing as the more familiar F(A) notation for a function's value at A, i.e. "F of A", but without context-dependent ambiguity. For more conventional alternate definitions, see fv2 2828 and fv3 2839; restricted equivalents are shown in funfv 2862 and funfv2 2863. For the familiar definition of function value in terms of ordered pair membership see funfvop 2857.
(FA) = {x∣(F “ {A}) = {x}}
 
Definitiondf-iso 2439 Define the isomorphism predicate. We read this as "H is an R, S isomorphism of A onto B." Normally, R and S are ordering relations on A and B respectively. Definition 6.28 of [TakeutiZaring] p. 32, whose notation is the same as ours except that R and S are subscripts.
(H Isom R, S (A, B) ↔ (H:A1-1-ontoB ∧ ∀xAyA (xRy ↔ (Hx)S(Hy))))
 
Theoremxpeq1 2440 Equality theorem for cross product.
(A = B → (A × C) = (B × C))
 
Theoremxpeq2 2441 Equality theorem for cross product.
(A = B → (C × A) = (C × B))
 
Theoremelxp 2442 Membership in a cross product.
(A ∈ (B × C) ↔ ∃xy(A = ⟨x, y⟩ ∧ (xByC)))
 
Theoremelxp2 2443 Membership in a cross product.
(A ∈ (B × C) ↔ ∃xByC A = ⟨x, y⟩)
 
Theoremhbxp 2444 Bound-variable hypothesis builder for cross product.
(yA → ∀x yA)    &   (yB → ∀x yB)    ⇒   (y ∈ (A × B) → ∀x y ∈ (A × B))
 
Theoremopelxpex 2445 The first member of an ordered pair of classes in a cross product exists. (This is a byproduct of our definition of ordered pair. Unfortunately existence is not implied for the second member.)
(⟨A, B⟩ ∈ (C × D) → AV)
 
Theorembrrelex 2446 A true binary relation on a relation implies the first argument is a set. (This is a property of our ordered pair definition.)
((Rel RARB) → AV)
 
Theorembrrelexi 2447 The first argument of a binary relation exists. (An artifact of our ordered pair definition.)
Rel R    ⇒   (ARBAV)
 
Theoremfconstopab 2448 Representation of a constant function using ordered pairs.
(A × {B}) = {⟨x, y⟩∣(xAy = B)}
 
Theoremvtoclr 2449 Variable to class conversion of transitive relation.
Rel R    &   ((xRyyRz) → xRz)    ⇒   (CD → ((ARBBRC) → ARC))
 
Theoremvtoclrbr 2450 Variable to class conversion of transitive, reflexive relation.
Rel R    &   ((xRyyRz) → xRz)    &   xRx    ⇒   ((ARBBRC) → ARC)
 
Theoremvtoclibr 2451 Variable to class conversion of transitive, irreflexive relation.
Rel R    &   ((xRyyRz) → xRz)    &    ¬ xRx    ⇒   ((ARBBRC) → ARC)
 
Theoremopelxp 2452 Ordered pair membership in a cross product.
BV    ⇒   (⟨A, B⟩ ∈ (C × D) ↔ (ACBD))
 
Theorembrxp 2453 Binary relation on a cross product.
BV    ⇒   (A(C × D)B ↔ (ACBD))
 
Theoremopelxpg 2454 Ordered pair membership in a cross product.
(BR → (⟨A, B⟩ ∈ (C × D) ↔ (ACBD)))
 
Theoremopelxpi 2455 Ordered pair membership in a cross product (implication).
((ACBD) → ⟨A, B⟩ ∈ (C × D))
 
Theoremralxp 2456 Universal quantification restricted to a cross product is equivalent to a double restricted quantification. The hypothesis specifies an implicit substitution.
(x = ⟨y, z⟩ → (φψ))    ⇒   (∀x ∈ (A × B)φ ↔ ∀yAzB ψ)
 
Theoremopthprc 2457 Justification theorem for an ordered pair definition that works for any classes, including proper classes. This is the definition implied by the footnote in [Jech] p. 78, which says, "The sophisticated reader will not object to our use of a pair of classes."
(((A × {∅}) ∪ (B × {{∅}})) = ((C × {∅}) ∪ (D × {{∅}})) ↔ (A = CB = D))
 
Theorembrelg 2458 Two things in a binary relation belong to the relation's domain.
R ⊆ (C × D)    ⇒   (BS → (ARB → (ACBD)))
 
Theorembrel 2459 Membership in superset of binary relation.
BV    &   R ⊆ (C × D)    ⇒   (ARB → (ACBD))
 
Theoremelxp3 2460 Membership in a cross product.
(A ∈ (B × C) ↔ ∃xy(⟨x, y⟩ = A ∧ ⟨x, y⟩ ∈ (B × C)))
 
Theoremxpundi 2461 Distributive law for cross product over union. Theorem 103 of [Suppes] p. 52.
(A × (BC)) = ((A × B) ∪ (A × C))
 
Theoremxpundir 2462 Distributive law for cross product over union. Similar to Theorem 103 of [Suppes] p. 52.
((AB) × C) = ((A × C) ∪ (B × C))
 
Theoremxpun 2463 The cross product of two unions.
((AB) × (CD)) = (((A × C) ∪ (A × D)) ∪ ((B × C) ∪ (B × D)))
 
Theoremelvv 2464 Membership in universal class of ordered pairs.
(A ∈ (V × V) ↔ ∃xy A = ⟨x, y⟩)
 
Theoremxpss 2465 A cross product is included in the ordered pair universe. Exercise 3 of [TakeutiZaring] p. 25.
(A × B) ⊆ (V × V)
 
Theorembrinxp 2466 Intersection of binary relation with cross product.
((ACBD) → (ARBA(R ∩ (C × D))B))
 
Theoremweinxp 2467 Intersection of well-ordering with cross product of its field.
(R We A ↔ (R ∩ (A × A)) We A)
 
Theoremopabssxp 2468 An abstraction relation is a subset of a related cross product.
{⟨x, y⟩∣((xAyB) ∧ φ)} ⊆ (A × B)
 
Theoremoptocl 2469 Implicit substitution of class for ordered pair.
D = (B × C)    &   (⟨x, y⟩ = A → (φψ))    &   ((xByC) → φ)    ⇒   (ADψ)
 
Theorem2optocl 2470 Implicit substitution of classes for ordered pairs.
R = (C × D)    &   (⟨x, y⟩ = A → (φψ))    &   (⟨z, w⟩ = B → (ψχ))    &   (((xCyD) ∧ (zCwD)) → φ)    ⇒   ((ARBR) → χ)
 
Theorem3optocl 2471 Implicit substitution of classes for ordered pairs.
R = (D × F)    &   (⟨x, y⟩ = A → (φψ))    &   (⟨z, w⟩ = B → (ψχ))    &   (⟨v, u⟩ = C → (χθ))    &   (((xDyF) ∧ (zDwF) ∧ (vDuF)) → φ)    ⇒   ((ARBRCR) → θ)
 
Theoremopbrop 2472 Ordered pair membership in a relation. Special case.
(((z = Aw = B) ∧ (v = Cu = D)) → (φψ))    &   R = {⟨x, y⟩∣((x ∈ (S × S) ∧ y ∈ (S × S)) ∧ ∃zwvu((x = ⟨z, w⟩ ∧ y = ⟨v, u⟩) ∧ φ))}    ⇒   (((ASBS) ∧ (CSDS)) → (⟨A, BRC, D⟩ ↔ ψ))
 
Theoremcbvop 2473 Change restricted bound variable to two restricted bound variables.
(x = ⟨y, z⟩ → (φψ))    ⇒   (∃x ∈ (A × B)φ ↔ ∃yAzB ψ)
 
Theoremxp0r 2474 The cross product with the empty set is empty. Part of Theorem 3.13(ii) of [Monk1] p. 37.
(∅ × A) = ∅
 
Theorem0nelxp 2475 The empty set is not a member of a cross product.
¬ ∅ ∈ (A × B)
 
Theoremonxpdisj 2476 Ordinal numbers and ordered pairs are disjoint collections. This theorem can be used if we want to extend a set of ordinal numbers or ordered pairs with disjoint elements. See also snsn0non 2371.
(On ∩ (V × V)) = ∅
 
Theoremreleq 2477 Equality theorem for relation predicate.
(A = B → (Rel A ↔ Rel B))
 
Theoremhbrel 2478 Bound-variable hypothesis builder for a relation.
(yA → ∀x yA)    ⇒   (Rel A → ∀xRel A)
 
Theoremssrel 2479 Subclass theorem for relation predicate. Theorem 2 of [Suppes] p. 58.
(AB → (Rel B → Rel A))
 
Theoremrelss 2480 A subclass relationship depends only on a relation's ordered pairs. Theorem 3.2(i) of [Monk1] p. 33.
(Rel A → (AB ↔ ∀xy(⟨x, y⟩ ∈ A → ⟨x, y⟩ ∈ B)))
 
Theoremrelssi 2481 Inference from subclass principle for relations.
Rel A    &   (⟨x, y⟩ ∈ A → ⟨x, y⟩ ∈ B)    ⇒   AB
 
Theoremrelssdv 2482 Deduction from subclass principle for relations.
(φ → Rel A)    &   (φ → (⟨x, y⟩ ∈ A → ⟨x, y⟩ ∈ B))    ⇒   (φAB)
 
Theoremcleqrel 2483 Extensionality principle for relations. Theorem 3.2(ii) of [Monk1] p. 33.
((Rel A ∧ Rel B) → (A = B ↔ ∀xy(⟨x, y⟩ ∈ A ↔ ⟨x, y⟩ ∈ B)))
 
Theoremcleqreli 2484 Inference from extensionality principle for relations.
Rel A    &   Rel B    &   (⟨x, y⟩ ∈ A ↔ ⟨x, y⟩ ∈ B)    ⇒   A = B
 
Theoremrelsn 2485 A singleton of an ordered pair is a relation.
AV    ⇒   Rel {⟨A, B⟩}
 
Theoremrelxp 2486 A cross product is a relation. Theorem 3.13(i) of [Monk1] p. 37.
Rel (A × B)
 
Theoremssxp 2487 Subset theorem for cross product. Generalization of Theorem 101 of [Suppes] p. 52.
((ABCD) → (A × C) ⊆ (B × D))
 
Theoremxpex 2488 The cross product of two sets is a set. Proposition 6.2 of [TakeutiZaring] p. 23.
AV    &   BV    ⇒   (A × B) ∈ V
 
Theoremxpexg 2489 The cross product of two sets is a set. Generalization of Proposition 6.2 of [TakeutiZaring] p. 23.
((ACBD) → (A × B) ∈ V)
 
Theoremrelun 2490 The union of two relations is a relation. Compare Exercise 5 of [TakeutiZaring] p. 25.
(Rel (AB) ↔ (Rel A ∧ Rel B))
 
Theoremrelin 2491 The intersection with a relation is a relation.
(Rel A → Rel (AB))
 
Theoremreldif 2492 A difference cutting down a relation is a relation.
(Rel A → Rel (AB))
 
Theoremreluni 2493 Union law for relations. Exercise 6 of [TakeutiZaring] p. 25 and its converse.
(Rel A ↔ ∀xA Rel x)
 
Theoremrelopab 2494 A class of ordered pairs is a relation.
Rel {⟨x, y⟩∣φ}
 
Theoreminopab 2495 Intersection of two ordered pair class abstractions.
({⟨x, y⟩∣φ} ∩ {⟨x, y⟩∣ψ}) = {⟨x, y⟩∣(φψ)}
 
Theoreminxp 2496 The intersection of two cross products. Exercise 9 of [TakeutiZaring] p. 25.
((A × B) ∩ (C × D)) = ((AC) × (BD))
 
Theoremxpindi 2497 Distributive law for cross product over intersection. Theorem 102 of [Suppes] p. 52.
(A × (BC)) = ((A × B) ∩ (A × C))
 
Theoremxpindir 2498 Distributive law for cross product over intersection. Similar to Theorem 102 of [Suppes] p. 52.
((AB) × C) = ((A × C) ∩ (B × C))
 
Theoremrel0 2499 The empty set is a relation.
Rel ∅
 
Theoremreli 2500 The identity relation is a relation. Part of Exercise 4.12(p) of [Mendelson] p. 235.
Rel I

  metamath.org < Previous  Next >