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Statement List for Metamath Proof Explorer - 2501-2600 - Page 26 of 58
TypeLabelDescription
Statement
 
Theoremrele 2501 The membership relation is a relation.
Rel E
 
Theoremcoeq1 2502 Equality theorem for composition of two classes.
(A = B → (AC) = (BC))
 
Theoremcoeq2 2503 Equality theorem for composition of two classes.
(A = B → (CA) = (CB))
 
Theoremcoeq1i 2504 Equality inference for composition of two classes.
A = B    ⇒   (AC) = (BC)
 
Theoremcoeq2i 2505 Equality inference for composition of two classes.
A = B    ⇒   (CA) = (CB)
 
Theoremcoeq1d 2506 Equality deduction for composition of two classes.
(φA = B)    ⇒   (φ → (AC) = (BC))
 
Theoremcoeq2d 2507 Equality deduction for composition of two classes.
(φA = B)    ⇒   (φ → (CA) = (CB))
 
Theoremhbco 2508 Bound-variable hypothesis builder for function value.
(yA → ∀x yA)    &   (yB → ∀x yB)    ⇒   (y ∈ (AB) → ∀x y ∈ (AB))
 
Theoremopelco 2509 Ordered pair membership in a composition.
AV    &   BV    ⇒   (⟨A, B⟩ ∈ (CD) ↔ ∃x(ADxxCB))
 
Theorembrco 2510 Binary relation on a composition.
AV    &   BV    ⇒   (A(CD)B ↔ ∃x(ADxxCB))
 
Theoremopelcog 2511 Ordered pair membership in a composition.
((ARBS) → (⟨A, B⟩ ∈ (CD) ↔ ∃x(⟨A, x⟩ ∈ D ∧ ⟨x, B⟩ ∈ C)))
 
Theoremcnvss 2512 Subset theorem for converse.
(ABAB)
 
Theoremcnveq 2513 Equality theorem for converse.
(A = BA = B)
 
Theoremelcnv 2514 Membership in a converse. Equation (5) of [Suppes] p. 62.
(AR ↔ ∃xy(A = ⟨x, y⟩ ∧ yRx))
 
Theoremelcnv2 2515 Membership in a converse. Equation (5) of [Suppes] p. 62.
(AR ↔ ∃xy(A = ⟨x, y⟩ ∧ ⟨y, x⟩ ∈ R))
 
Theoremhbcnv 2516 Bound-variable hypothesis builder for converse.
(yA → ∀x yA)    ⇒   (yA → ∀x yA)
 
Theoremopelcnvg 2517 Ordered-pair membership in converse.
((ACBD) → (⟨A, B⟩ ∈ R ↔ ⟨B, A⟩ ∈ R))
 
Theoremopelcnv 2518 Ordered-pair membership in converse.
AV    &   BV    ⇒   (⟨A, B⟩ ∈ R ↔ ⟨B, A⟩ ∈ R)
 
Theorembrcnv 2519 The converse of a binary relation swaps arguments. Theorem 11 of [Suppes] p. 61.
AV    &   BV    ⇒   (ARBBRA)
 
Theoremcnvco 2520 Distributive law of converse over class composition. Theorem 26 of [Suppes] p. 64.
(AB) = (BA)
 
Theoremcnvuni 2521 The converse of a class union is the (indexed) union of the converses of its members.
A = xA x
 
Theoremdfdm3 2522 Alternate definition of domain. Definition 6.5(1) of [TakeutiZaring] p. 24.
dom A = {x∣∃yx, y⟩ ∈ A}
 
Theoremdfrn2 2523 Alternate definition of range. Definition 4 of [Suppes] p. 60.
ran A = {y∣∃x xAy}
 
Theoremdfrn3 2524 Alternate definition of range. Definition 6.5(2) of [TakeutiZaring] p. 24.
ran A = {y∣∃xx, y⟩ ∈ A}
 
Theoremdfdm4 2525 Alternate definition of domain.
dom A = ran A
 
Theoremdfdmf 2526 Domain definition requiring only that x and y not be 'free' in A (but not necessarily absent from it).
(zA → ∀x zA)    &   (zA → ∀y zA)    ⇒   dom A = {x∣∃yx, y⟩ ∈ A}
 
Theoremeldm 2527 Membership in a domain. Theorem 4 of [Suppes] p. 59.
AV    ⇒   (A ∈ dom B ↔ ∃y ABy)
 
Theoremeldm2 2528 Membership in a domain. Theorem 4 of [Suppes] p. 59.
AV    ⇒   (A ∈ dom B ↔ ∃yA, y⟩ ∈ B)
 
Theoremeldmg 2529 Domain membership. Theorem 4 of [Suppes] p. 59.
(AC → (A ∈ dom B ↔ ∃yA, y⟩ ∈ B))
 
Theoremdmss 2530 Subset theorem for domain.
(AB → dom A ⊆ dom B)
 
Theoremdmeq 2531 Equality theorem for domain.
(A = B → dom A = dom B)
 
Theoremdmeqi 2532 Equality inference for domain.
A = B    ⇒   dom A = dom B
 
Theoremdmeqd 2533 Equality deduction for domain.
(φA = B)    ⇒   (φ → dom A = dom B)
 
Theoremopeldm 2534 Membership of first of an ordered pair in a domain.
AV    ⇒   (⟨A, B⟩ ∈ CA ∈ dom C)
 
Theorembreldm 2535 Membership of first of a binary relation in a domain.
AV    ⇒   (ARBA ∈ dom R)
 
Theoremdmun 2536 The domain of a union is the union of domains. Exercise 56(a) of [Enderton] p. 65.
dom (AB) = (dom A ∪ dom B)
 
Theoremdmin 2537 The domain of an intersection belong to the intersection of domains. Theorem 6 of [Suppes] p. 60.
dom (AB) ⊆ (dom A ∩ dom B)
 
Theoremdmuni 2538 The domain of a union. Part of Exercise 8 of [Enderton] p. 41.
dom A = xA dom x
 
Theoremdmopab 2539 The domain of a class of ordered pairs.
dom {⟨x, y⟩∣φ} = {x∣∃yφ}
 
Theoremdmopabss 2540 Upper bound for the domain of a restricted class of ordered pairs.
dom {⟨x, y⟩∣(xAφ)} ⊆ A
 
Theoremdmopab2 2541 The domain of a restricted class of ordered pairs.
(∀xAyφ ↔ dom {⟨x, y⟩∣(xAφ)} = A)
 
Theoremdm0 2542 The domain of the empty set is empty. Part of Theorem 3.8(v) of [Monk1] p. 36.
dom ∅ = ∅
 
Theoremdmsn0 2543 The domain of the singleton of the empty set is empty.
dom {∅} = ∅
 
Theoremdmsnsn0 2544 The domain of the singleton of the singleton of the empty set is empty.
dom {{∅}} = ∅
 
Theoremdmi 2545 The domain of the identity relation is the universe.
dom I = V
 
Theoremdmv 2546 The domain of the universe is the universe.
dom V = V
 
Theoremdmsnop 2547 The domain of a singleton of an ordered pair is the singleton of the first member.
dom {⟨A, B⟩} = {A}
 
Theoremdmsnsnsn 2548 The domain of the singleton of the singleton of a singleton.
dom {{{A}}} = {A}
 
Theoremdm0rn0 2549 An empty domain implies an empty range.
(dom A = ∅ ↔ ran A = ∅)
 
Theoremreldm0 2550 A relation is empty iff its domain is empty.
(Rel A → (A = ∅ ↔ dom A = ∅))
 
Theoremdmexg 2551 The domain of a set is a set. Corollary 6.8(2) of [TakeutiZaring] p. 26.
(AB → dom AV)
 
Theoremdmxp 2552 The domain of a cross product. Part of Theorem 3.13(x) of [Monk1] p. 37.
B = ∅ → dom (A × B) = A)
 
Theoremdmxpid 2553 The domain of a cross product.
dom (A × A) = A
 
Theoremelreldm 2554 The first member of an ordered pair in a relation belongs to the domain of the relation.
((Rel ABA) → B ∈ dom A)
 
Theoremrneq 2555 Equality theorem for range.
(A = B → ran A = ran B)
 
Theoremrneqi 2556 Equality inference for range.
A = B    ⇒   ran A = ran B
 
Theoremrneqd 2557 Equality deduction for range.
(φA = B)    ⇒   (φ → ran A = ran B)
 
Theoremrnss 2558 Subset theorem for range.
(AB → ran A ⊆ ran B)
 
Theorembrelrn 2559 The second argument of a binary relation belongs to its range.
AV    &   BV    ⇒   (ACBB ∈ ran C)
 
Theoremopelrn 2560 Membership of second member of an ordered pair in a range.
AV    &   BV    ⇒   (⟨A, B⟩ ∈ CB ∈ ran C)
 
Theoremdfrnf 2561 Range definition requiring only that x and y not be 'free' in A (but not necessarily absent from it).
(zA → ∀x zA)    &   (zA → ∀y zA)    ⇒   ran A = {y∣∃xx, y⟩ ∈ A}
 
Theoremelrn 2562 Membership in a range.
AV    ⇒   (A ∈ ran B ↔ ∃xx, A⟩ ∈ B)
 
Theoremelrn2 2563 Membership in a range.
AV    ⇒   (A ∈ ran B ↔ ∃x xBA)
 
Theoremhbrn 2564 Bound-variable hypothesis builder for range.
(yA → ∀x yA)    ⇒   (y ∈ ran A → ∀x y ∈ ran A)
 
Theoremhbdm 2565 Bound-variable hypothesis builder for domain.
(yA → ∀x yA)    ⇒   (y ∈ dom A → ∀x y ∈ dom A)
 
Theoremrnopab 2566 The range of a class of ordered pairs.
ran {⟨x, y⟩∣φ} = {y∣∃xφ}
 
Theoremrn0 2567 The range of the empty set is empty. Part of Theorem 3.8(v) of [Monk1] p. 36.
ran ∅ = ∅
 
Theoremrelrn0 2568 A relation is empty iff its range is empty.
(Rel A → (A = ∅ ↔ ran A = ∅))
 
Theoremrnexg 2569 The range of a set is a set. Corollary 6.8(3) of [TakeutiZaring] p. 26. Similar to Lemma 3D of [Enderton] p. 41.
(AB → ran AV)
 
Theoremdmco 2570 Domain of a composition. Theorem 21 of [Suppes] p. 63.
dom (AB) ⊆ dom B
 
Theoremrnco 2571 Range of a composition.
ran (AB) ⊆ ran A
 
Theoremdmcosseq 2572 Domain of a composition.
(ran B ⊆ dom A → dom (AB) = dom B)
 
Theoremdmcoeq 2573 Domain of a composition.
(dom A = ran B → dom (AB) = dom B)
 
Theoremrncoeq 2574 Range of a composition.
(dom A = ran B → ran (AB) = ran A)
 
Theoremreseq1 2575 Equality theorem for restrictions.
(A = B → (AC) = (BC))
 
Theoremreseq2 2576 Equality theorem for restrictions.
(A = B → (CA) = (CB))
 
Theoremhbres 2577 Bound-variable hypothesis builder for restriction.
(yA → ∀x yA)    &   (yB → ∀x yB)    ⇒   (y ∈ (AB) → ∀x y ∈ (AB))
 
Theoremres0 2578 A restriction to the empty set is empty.
(A ↾ ∅) = ∅
 
Theoremopelres 2579 Ordered pair membership in a restriction. Exercise 13 of [TakeutiZaring] p. 25.
BV    ⇒   (⟨A, B⟩ ∈ (CD) ↔ (⟨A, B⟩ ∈ CAD))
 
Theoremopres 2580 Ordered pair membership in a restriction when the first member belongs to the restricting class.
BV    ⇒   (AD → (⟨A, B⟩ ∈ (CD) ↔ ⟨A, B⟩ ∈ C))
 
Theoremresieq 2581 A restricted identity relation is equivalent to equality in its domain.
((BACA) → (B(IA)CB = C))
 
Theoremresundi 2582 Distributive law for restriction over union. Theorem 31 of [Suppes] p. 65.
(A ↾ (BC)) = ((AB) ∪ (AC))
 
Theoremresundir 2583 Distributive law for restriction over union.
((AB) ↾ C) = ((AC) ∪ (BC))
 
Theoremdmres 2584 The domain of a restriction. Exercise 14 of [TakeutiZaring] p. 25.
dom (AB) = (B ∩ dom A)
 
Theoremssdmres 2585 A domain restricted to a subclass equals the subclass.
(A ⊆ dom B ↔ dom (BA) = A)
 
Theoremdmresexg 2586 The domain of a restriction to a set exists.
(BC → dom (AB) ∈ V)
 
Theoremresss 2587 A class includes its restriction. Exercise 15 of [TakeutiZaring] p. 25.
(AB) ⊆ A
 
Theoremrescom 2588 Commutative law for restriction.
((AB) ↾ C) = ((AC) ↾ B)
 
Theoremssres 2589 Subclass theorem for restriction.
(AB → (AC) ⊆ (BC))
 
Theoremssres2 2590 Subclass theorem for restriction.
(AB → (CA) ⊆ (CB))
 
Theoremrelres 2591 A restriction is a relation. Exercise 12 of [TakeutiZaring] p. 25.
Rel (AB)
 
Theoremresabs1 2592 Absorption law for restriction. Exercise 17 of [TakeutiZaring] p. 25.
(BC → ((AC) ↾ B) = (AB))
 
Theoremresabs2 2593 Absorption law for restriction.
(BC → ((AB) ↾ C) = (AB))
 
Theoremresidm 2594 Idempotent law for restriction.
((AB) ↾ B) = (AB)
 
Theoremresima 2595 A restriction to an image.
((AB) “ B) = (AB)
 
Theoremrelssres 2596 Simplification law for restriction.
((Rel A ∧ dom AB) → (AB) = A)
 
Theoremresexg 2597 The restriction of a set is a set.
(AC → (AB) ∈ V)
 
Theoremresopab 2598 Restriction of a class abstraction of ordered pairs.
({⟨x, y⟩∣φ} ↾ A) = {⟨x, y⟩∣(xAφ)}
 
Theoremiss 2599 A subclass of the identity function is the identity function restricted to its domain.
(AIA = (I ↾ dom A))
 
Theoremdmresi 2600 The domain of the restricted identity function.
dom (IA) = A

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