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Statement List for Metamath Proof Explorer - 3601-3700 - Page 37 of 58
TypeLabelDescription
Statement
 
Theoremnumthcor 3601 Any set is strictly dominated by some ordinal.
(AB → ∃x ∈ On Ax)
 
Theoremweth 3602 Well-ordering theorem: any set A can be well-ordered. This is an equivalent of the Axiom of Choice. Theorem 6 of [Suppes] p. 242.
AV    ⇒   x x We A
 
Theoremzornlem1 3603 Lemma for Zorn's lemma.
AV    &   B = {f∣∃h ∈ On (f Fn h ∧ ∀th (ft) = (G ‘(ft)))}    &   F = B    &   C = {zA∣∀g ∈ ran fgRz}    &   D = {zA∣∀g ∈ (Fx)gRz}    &   G = {⟨f, t⟩∣t = {vC∣∀uC ¬ uwv}}    ⇒   ((x ∈ On ∧ (w We A ∧ ¬ D = ∅)) → (Fx) ∈ D)
 
Theoremzornlem2 3604 Lemma for Zorn's lemma.
AV    &   B = {f∣∃h ∈ On (f Fn h ∧ ∀th (ft) = (G ‘(ft)))}    &   F = B    &   C = {zA∣∀g ∈ ran fgRz}    &   D = {zA∣∀g ∈ (Fx)gRz}    &   G = {⟨f, t⟩∣t = {vC∣∀uC ¬ uwv}}    ⇒   ((x ∈ On ∧ (w We A ∧ ¬ D = ∅)) → (yx → (Fy)R(Fx)))
 
Theoremzornlem3 3605 Lemma for Zorn's lemma.
AV    &   B = {f∣∃h ∈ On (f Fn h ∧ ∀th (ft) = (G ‘(ft)))}    &   F = B    &   C = {zA∣∀g ∈ ran fgRz}    &   D = {zA∣∀g ∈ (Fx)gRz}    &   G = {⟨f, t⟩∣t = {vC∣∀uC ¬ uwv}}    ⇒   ((R Po A ∧ (x ∈ On ∧ (w We A ∧ ¬ D = ∅))) → (yx → ¬ (Fx) = (Fy)))
 
Theoremzornlem4 3606 Lemma for Zorn's lemma.
AV    &   B = {f∣∃h ∈ On (f Fn h ∧ ∀th (ft) = (G ‘(ft)))}    &   F = B    &   C = {zA∣∀g ∈ ran fgRz}    &   D = {zA∣∀g ∈ (Fx)gRz}    &   G = {⟨f, t⟩∣t = {vC∣∀uC ¬ uwv}}    ⇒   ((R Po Aw We A) → ∃x ∈ On D = ∅)
 
Theoremzornlem5 3607 Lemma for Zorn's lemma.
AV    &   B = {f∣∃h ∈ On (f Fn h ∧ ∀th (ft) = (G ‘(ft)))}    &   F = B    &   C = {zA∣∀g ∈ ran fgRz}    &   D = {zA∣∀g ∈ (Fx)gRz}    &   G = {⟨f, t⟩∣t = {vC∣∀uC ¬ uwv}}    &   H = {zA∣∀g ∈ (Fy)gRz}    ⇒   (((w We Ax ∈ On) ∧ ∀yx ¬ H = ∅) → (Fx) ⊆ A)
 
Theoremzornlem6 3608 Lemma for Zorn's lemma.
AV    &   B = {f∣∃h ∈ On (f Fn h ∧ ∀th (ft) = (G ‘(ft)))}    &   F = B    &   C = {zA∣∀g ∈ ran fgRz}    &   D = {zA∣∀g ∈ (Fx)gRz}    &   G = {⟨f, t⟩∣t = {vC∣∀uC ¬ uwv}}    &   H = {zA∣∀g ∈ (Fy)gRz}    ⇒   (R Po A → (((w We Ax ∈ On) ∧ ∀yx ¬ H = ∅) → R Or (Fx)))
 
Theoremzornlem7 3609 Lemma for Zorn's lemma.
AV    &   B = {f∣∃h ∈ On (f Fn h ∧ ∀th (ft) = (G ‘(ft)))}    &   F = B    &   C = {zA∣∀g ∈ ran fgRz}    &   D = {zA∣∀g ∈ (Fx)gRz}    &   G = {⟨f, t⟩∣t = {vC∣∀uC ¬ uwv}}    &   H = {zA∣∀g ∈ (Fy)gRz}    ⇒   ((R Po A ∧ ∀s((sAR Or s) → ∃aArs (rRar = a))) → ∃aAbA ¬ aRb)
 
Theoremzorn2lem 3610 Lemma for zorn2 3612.
(z{⟨x, y⟩∣xy}wzw)
 
Theoremzorn 3611 Zorn's Lemma of [Monk1] p. 117. This theorem is equivalent to the Axiom of Choice and states that every partially ordered set A (with an ordering relation R) in which every totally ordered subset has an upper bound, contains at least one maximal element. The main proof consists of lemmas zornlem1 3603 through zornlem7 3609; this final piece mainly changes bound variables to eliminate the hypotheses of zornlem7 3609.
AV    ⇒   ((R Po A ∧ ∀w((wAR Or w) → ∃xAzw (zRxz = x))) → ∃xAyA ¬ xRy)
 
Theoremzorn2 3612 Zorn's Lemma. If the union of every chain (with respect to inclusion) in a set belongs to the set, then the set contains a maximal element. This theorem is equivalent to the Axiom of Choice. Theorem 6M of [Enderton] p. 151.
AV    ⇒   (∀z((zA ∧ ∀xzyz (xyyx)) → zA) → ∃xAyA ¬ xy)
 
Theoremfodom 3613 An onto function implies dominance of range over domain. Lemma 10.20 of [Kunen] p. 30. This theorem uses the Axiom of Choice ac7g 3570.
AV    ⇒   (F:AontoBBA)
 
Theoremfodomg 3614 An onto function implies dominance of range over domain.
(AC → (F:AontoBBA))
 
Theoremfodomb 3615 Equivalence of an onto mapping and dominance for a non-empty set. Proposition 10.35 of [TakeutiZaring] p. 93.
AV    &   BV    ⇒   ((¬ A = ∅ ∧ ∃f f:AontoB) ↔ (∅ ≺ BBA))
 
Theoremimadomg 3616 An image of a function under a set is dominated by the set. Proposition 10.34 of [TakeutiZaring] p. 92.
(AB → (Fun F → (FA) ≼ A))
 
Theoremfnrndomg 3617 The range of a function is dominated by its domain.
(AB → (F Fn A → ran FA))
 
Theoremhtalem 3618 Lemma for defining an emulation of Hilbert's epsilon. Hilbert's epsilon is described at http://plato.stanford.edu/entries/epsilon-calculus/. This theorem is equivalent to Hilbert's "transfinite axiom," described on that page, with the additional R We A antecedent. The element B is the epsilon that the theorem emulates.
AV    &   B = {xA∣∀yA ¬ yRx}    ⇒   ((R We A ∧ ¬ A = ∅) → BA)
 
Theoremhta 3619 A ZFC emulation of Hilbert's transfinite axiom. The set B has the properties of Hilbert's epsilon, except that it also depends on a well-ordering R. This theorem arose from discussions with Raph Levien on 5-Mar-04 about translating the HOL proof language, which uses Hilbert's epsilon.

Hilbert's epsilon is described at http://plato.stanford.edu/entries/epsilon-calculus/. This theorem differs from Hilbert's transfinite axiom described on that page in that it requires R We A as an antecedent. Class A collects the sets of least rank for which φ(x) is true. Class B, which emulates the epsilon, is the minimum element in a well-ordering R on A.

If a well-ordering R on A can be expressed in a closed form, as might be the case if we are working with say natural numbers, we can eliminate the antecedent with modus ponens, giving us the exact equivalent of Hilbert's transfinite axiom. Otherwise, we replace R with a dummy set variable, say w, and attach w We A as an antecedent in each step of the ZFC version of the HOL proof until the epsilon is eliminated. At that point, B (which will have w as a free variable) will no longer be present, and we can eliminate w We A by applying 19.23aiv 952 and weth 3602, using scottexs 3543 to establish the existence of A.

For a version of this theorem scheme using class (meta)variables instead of wff (meta)variables, see htalem 3618.

A = {x∣(φ ∧ ∀y([y / x]φ → (rank ‘x) ⊆ (rank ‘y)))}    &   B = {xA∣∀yA ¬ yRx}    ⇒   (R We A → (φ → [B / x]φ))
 
Syntaxccrd 3620 Extend class definition to include the cardinal size function.
class card
 
Syntaxcale 3621 Extend class definition to include the aleph function.
class
 
Syntaxccf 3622 Extend class definition to include the cofinality function.
class cf
 
Definitiondf-card 3623 Define the cardinal number function. The cardinal number of a set is the least ordinal number equinumerous to it. In other words, it is the "size" of the set. Definition of [Enderton] p. 197. See cardval 3633 for its value, cardval2 3661 for a simpler version of its value. The principle theorem relating cardinality to equinumerosity is carden 3638. Our notation is from Enderton. Other textbooks often use a double bar over the set to express this function.
card = {⟨x, y⟩∣y = {z ∈ On∣zx}}
 
Definitiondf-aleph 3624 Define the aleph function. Our definition expresses Definition 12 of [Suppes] p. 229 in a closed form, from which we derive the recursive definition as theorems aleph0 3669, alephsuc 3672, and alephlim 3670. The aleph function provides a one-to-one, onto mapping from the ordinal numbers to the infinite cardinal numbers. Roughly, any aleph is the smallest infinite cardinal number whose size is strictly greater than any aleph before it.
ℵ = rec({⟨x, y⟩∣y = {z ∈ On∣xz}}, ω)
 
Definitiondf-cf 3625 Define the cofinality function. Definition B of Saharon Shelah, Cardinal Arithmetic (1994), p. xxx. See cfval 3701 for its value and a description.
cf = {⟨x, y⟩∣(x ∈ On ∧ y = {z∣∃w(z = (card ‘w) ∧ (wx ∧ ∀vxuw vu))})}
 
Theoremoncardval 3626 The value of the cardinal number function with an ordinal number as its argument. Unlike cardval 3633, this theorem does not require the Axiom of Choice.
(A ∈ On → (card ‘A) = {x ∈ On∣xA})
 
Theoremoncardon 3627 The cardinal number of an ordinal number is an ordinal number. Unlike cardon 3634, this theorem does not require the Axiom of Choice.
(A ∈ On → (card ‘A) ∈ On)
 
Theoremoncardid 3628 Any ordinal number is equinumerous to its cardinal number. Unlike cardid 3635, this theorem does not require the Axiom of Choice.
(A ∈ On → (card ‘A) ≈ A)
 
Theoremcardonle 3629 The cardinal of an ordinal number is less than or equal to the ordinal number. Proposition 10.6(3) of [TakeutiZaring] p. 85.
(A ∈ On → (card ‘A) ⊆ A)
 
Theoremcard0 3630 The cardinality of the empty set is the empty set.
(card ‘∅) = ∅
 
Theoremcardnn 3631 The cardinality of a natural number is the number. Corollary 10.23 of [TakeutiZaring] p. 90.
(A ∈ ω → (card ‘A) = A)
 
Theoremcardom 3632 The set of natural numbers is a cardinal number. Theorem 18.11 of [Monk1] p. 133.
(card ‘ω) = ω
 
Theoremcardval 3633 The value of the cardinal number function. Definition 10.4 of [TakeutiZaring] p. 85. See cardval2 3661 for a simpler version of its value.
(card ‘A) = {x ∈ On∣xA}
 
Theoremcardon 3634 The cardinal number of a set is an ordinal number. Proposition 10.6(1) of [TakeutiZaring] p. 85. Unlike Takeuti/Zaring's proposition, we need the Axiom of Choice (in cardval 3633) because of our slightly different definition of of cardinal number.
(card ‘A) ∈ On
 
Theoremcardid 3635 Any set is equinumerous to its cardinal number. Proposition 10.5 of [TakeutiZaring] p. 85.
(card ‘A) ≈ A
 
Theoremoncard 3636 A set is a cardinal number iff it equals its own cardinal number. Proposition 10.9 of [TakeutiZaring] p. 85.
(∃x A = (card ‘x) ↔ A = (card ‘A))
 
Theoremcardne 3637 No member of a cardinal number of a set is equinumerous to the set. Proposition 10.6(2) of [TakeutiZaring] p. 85.
(A ∈ (card ‘B) → ¬ AB)
 
Theoremcarden 3638 Two sets are equinumerous iff their cardinal numbers are equal. This important theorem expresses the essential concept behind "cardinality" or "size". This theorem appears as Proposition 10.10 of [TakeutiZaring] p. 85, Theorem 7P of [Enderton] p. 197, and Theorem 9 of [Suppes] p. 242 (among others). The Axiom of Choice is required for its proof.

The theory of cardinality can also be developed without AC by introducing "card" as a primitive notion and stating this theorem as an axiom, as is done with the axiom for cardinal numbers in [Suppes] p. 111. Finally, if we allow the Axiom of Regularity, we can avoid AC by defining the cardinal number of a set as the set of all sets equinumerous to it and having least possible rank (see karden 3551).

((ACBD) → ((card ‘A) = (card ‘B) ↔ AB))
 
Theoremcardeq0 3639 Only the empty set has cardinality zero.
(AB → ((card ‘A) = ∅ ↔ A = ∅))
 
Theoremcardsn 3640 A singleton has cardinality one.
(AB → (card ‘{A}) = 1o)
 
Theoremcarddomi 3641 Two sets have the dominance relationship if their cardinalities have the subset relationship.
(AC → ((card ‘A) ⊆ (card ‘B) → AB))
 
Theoremcarddom 3642 Two sets have the dominance relationship iff their cardinalities have the subset relationship. Equation (i) of [Quine] p. 232.
((ACBD) → ((card ‘A) ⊆ (card ‘B) ↔ AB))
 
Theoremcardsdom 3643 Two sets have the strict dominance relationship iff their cardinalities have the membership relationship. Corollary 19.7(2) of [Eisenberg] p. 310.
((ACBD) → ((card ‘A) ∈ (card ‘B) ↔ AB))
 
Theoremdomtri 3644 Trichotomy law for dominance and strict dominance. This theorem is equivalent to the Axiom of Choice.
((ACBD) → (AB ↔ ¬ BA))
 
Theorementri 3645 Trichotomy of equinumerosity and strict dominance. This theorem is equivalent to the Axiom of Choice. Theorem 8 of [Suppes] p. 242.
((ACBD) → (ABABBA))
 
Theorementri2 3646 Trichotomy of dominance and strict dominance.
((ACBD) → (ABBA))
 
Theorementri3 3647 Trichotomy of dominance. This theorem is equivalent to the Axiom of Choice. Part of Proposition 4.42(d) of [Mendelson] p. 275.
((ACBD) → (ABBA))
 
Theoremsucdom 3648 Strict dominance of a set over a natural number is the same as dominance over its successor. The proof uses AC and Infinity. It is unclear if a proof without using these is possible, unlike the weaker versions omsucdom 3418, sucdomi 3419, and finsucdom 3421.
((A ∈ ω ∧ BC) → (AB ↔ suc AB))
 
Theoremunxpdomlem 3649 Lemma for unxpdom 3650.
AV    &   BV    ⇒   ((1oA ∧ 1oB) → (AB) ≼ (A × B))
 
Theoremunxpdom 3650 Cross product dominates union for sets with cardinality greater than 1. Proposition 10.36 of [TakeutiZaring] p. 93.
((1oA ∧ 1oB) → (AB) ≼ (A × B))
 
Theoremunxpdom2 3651 Corollary of unxpdom 3650.
AV    &   BV    ⇒   ((1oABA) → (AB) ≼ (A × A))
 
Theoremsucxpdom 3652 Cross product dominates successor for set with cardinality greater than 1. Proposition 10.38 of [TakeutiZaring] p. 93 (but generalized to arbitrary sets, not just ordinals, with a proof using AC).
(1oA → suc A ≼ (A × A))
 
Theoremsdomel 3653 Strict dominance implies ordinal membership.
((A ∈ On ∧ B ∈ On) → (ABAB))
 
Theoremsdomsdomcard 3654 A set strictly dominates iff its cardinal strictly dominates.
(ABA ≺ (card ‘B))
 
Theoremcardcard 3655 The cardinality of the cardinality of a set equals the cardinality of the set. Proposition 10.11 of [TakeutiZaring] p. 85.
(card ‘(card ‘A)) = (card ‘A)
 
Theoremcanth3 3656 Cantor's theorem in terms of cardinals. This theorem tells us that no matter how large a cardinal number is, there is a still larger cardinal number. Theorem 18.12 of [Monk1] p. 133.
(AB → (card ‘A) ∈ (card ‘℘A))
 
Theoremcardlim 3657 An infinite cardinal is a limit ordinal. Equivalent to Exercise 4 of [TakeutiZaring] p. 91.
(ω ⊆ (card ‘A) ↔ Lim (card ‘A))
 
Theoremcardsdomel 3658 A cardinal strictly dominates its members. Equivalent to Proposition 10.37 of [TakeutiZaring] p. 93 (use cardsdom 3643 to obtain the exact proposition from this one).
(A ∈ On → (ABA ∈ (card ‘B)))
 
Theoremiscard 3659 Two ways to express the property of being a cardinal number.
((card ‘A) = A ↔ (A ∈ On ∧ ∀xA xA))
 
Theoremiscard2 3660 Two ways to express the property of being a cardinal number. Definition 8 of [Suppes] p. 225.
((card ‘A) = A ↔ (A ∈ On ∧ ∀x ∈ On (AxAx)))
 
Theoremcardval2 3661 An alternate version of the value of the cardinal number of a set. Compare cardval 3633. This theorem could be used to give us a simpler definition of card in place of df-card 3623. It apparently does not occur in the literature.
(card ‘A) = {x ∈ On∣xA}
 
Theoremondomon 3662 The collection of ordinal numbers dominated by a set is an ordinal number. (In general, not all collections of ordinal numbers are ordinal.) Theorem 56 of [Suppes] p. 227.
(AB → {x ∈ On∣xA} ∈ On)
 
Theoremondomcard 3663 The class of ordinal numbers dominated by a set is a cardinal number. Theorem 59 of [Suppes] p. 228.
(AB → (card ‘{x ∈ On∣xA}) = {x ∈ On∣xA})
 
Theoremcarduni 3664 The union of a set of cardinals is a cardinal. Theorem 18.14 of [Monk1] p. 133.
(AB → (∀xA (card ‘x) = x → (card ‘A) = A))
 
Theoremcardiun 3665 The indexed union of a set of cardinals is a cardinal.
(AC → (∀xA (card ‘B) = B → (card ‘xA B) = xA B))
 
Theoremcardmin 3666 The smallest ordinal that strictly dominates a set is a cardinal.
(AB → (card ‘{x ∈ On∣Ax}) = {x ∈ On∣Ax})
 
Theoremcardprc 3667 The class of all cardinal numbers is not a set (i.e. is a proper class). Theorem 19.8 of [Eisenberg] p. 310.
¬ {x∣(card ‘x) = x} ∈ V
 
Theoremalephfnon 3668 The aleph function is a function on the class of ordinal numbers.
ℵ Fn On
 
Theoremaleph0 3669 The first infinite cardinal number, discovered by Georg Cantor in 1873, has the same size as the set of natural numbers ω (and under our particular definition is also equal to it). In the literature, the argument of the aleph function is often written as a subscript, and the first aleph is written ℵ0. Exercise 3 of [TakeutiZaring] p. 91. Also Definition 12(i) of [Suppes] p. 228. From Kuratowski and Mostowski, Set Theory, p. 95: "Aleph...the first letter in the Hebrew alphabet...is also the first letter of the Hebrew word...(einsoph, meaning infinity), which is a cabbalistic appellation of the deity. The notation is due to Cantor, who was deeply interested in mysticism."
(ℵ ‘∅) = ω
 
Theoremalephlim 3670 Value of the aleph function at a limit ordinal. Definition 12(iii) of [Suppes] p. 91.
((AB ∧ Lim A) → (ℵ ‘A) = xA (ℵ ‘x))
 
Theoremalephon 3671 An aleph is an ordinal number.
(ℵ ‘A) ∈ On
 
Theoremalephsuc 3672 Value of the aleph function at a successor ordinal. Definition 12(ii) of [Suppes] p. 91.
(A ∈ On → (ℵ ‘suc A) = {x ∈ On∣(ℵ ‘A) ≺ x})
 
Theoremalephcard 3673 Every aleph is a cardinal number. Theorem 65 of [Suppes] p. 229.
(card ‘(ℵ ‘A)) = (ℵ ‘A)
 
Theoremalephnbtwn 3674 No cardinal can be sandwiched between an aleph and its successor aleph. Theorem 67 of [Suppes] p. 229.
((card ‘B) = B → ¬ ((ℵ ‘A) ∈ BB ∈ (ℵ ‘suc A)))
 
Theoremalephnbtwn2 3675 No set has equinumerosity between an aleph and its successor aleph.
¬ ((ℵ ‘A) ≺ BB ≺ (ℵ ‘suc A))
 
Theoremaleph1 3676 The set exponentiation of 2 to the aleph-zero has cardinality of at least aleph-one. (If we were to assume the Continuum Hypothesis, their cardinalities would be the same.)
(ℵ ‘1o) ≼ (2om (ℵ ‘∅))
 
Theoremalephordlem1 3677 Lemma for alephordi 3679.
(A ∈ On → (ℵ ‘A) ≺ (ℵ ‘suc A))
 
Theoremalephordlem2 3678 Lemma for alephordi 3679.
((BV ∧ Lim B) → (AB → (ℵ ‘A) ≼ (ℵ ‘B)))
 
Theoremalephordi 3679 Strict ordering property of the aleph function.
(B ∈ On → (AB → (ℵ ‘A) ≺ (ℵ ‘B)))
 
Theoremalephord 3680 Ordering property of the aleph function.
((A ∈ On ∧ B ∈ On) → (AB ↔ (ℵ ‘A) ≺ (ℵ ‘B)))
 
Theoremalephord2 3681 Ordering property of the aleph function. Theorem 8A(a) of [Enderton] p. 213 and its converse.
((A ∈ On ∧ B ∈ On) → (AB ↔ (ℵ ‘A) ∈ (ℵ ‘B)))
 
Theoremalephord2i 3682 Ordering property of the aleph function. Theorem 66 of [Suppes] p. 229.
(B ∈ On → (AB → (ℵ ‘A) ∈ (ℵ ‘B)))
 
Theoremalephord3 3683 Ordering property of the aleph function.
((A ∈ On ∧ B ∈ On) → (AB ↔ (ℵ ‘A) ⊆ (ℵ ‘B)))
 
Theoremaleph11 3684 The aleph function is one-to-one.
((A ∈ On ∧ B ∈ On) → ((ℵ ‘A) = (ℵ ‘B) ↔ A = B))
 
Theoremalephsucdom 3685 A set dominated by an aleph is strictly dominated by its successor aleph and vice-versa.
(B ∈ On → (A ≼ (ℵ ‘B) ↔ A ≺ (ℵ ‘suc B)))
 
Theoremalephsuc2 3686 An alternate representation of a successor aleph. Using this theorem we could define the aleph function with {z ∈ On∣zx} in place of {z ∈ On∣xz} in df-aleph 3624.
(A ∈ On → (ℵ ‘suc A) = {x ∈ On∣x ≼ (ℵ ‘A)})
 
Theoremalephgeom 3687 Every aleph is greater than or equal to the set of natural numbers.
(A ∈ On ↔ ω ⊆ (ℵ ‘A))
 
Theoremalephislim 3688 Every aleph is a limit ordinal.
(A ∈ On ↔ Lim (ℵ ‘A))
 
Theoremalephle 3689 The argument of the aleph function is less than or equal to its value. Exercise 2 of [TakeutiZaring] p. 91. (Later, in alephfp2 (future), we will that equality can sometimes hold.)
(A ∈ On → A ⊆ (ℵ ‘A))
 
Theoremcardaleph 3690 Given any transfinite cardinal number A, there is exactly one aleph that is equal to it. Here we compute that aleph explicitly.
((ω ⊆ A ∧ (card ‘A) = A) → A = (ℵ ‘{x ∈ On∣A ⊆ (ℵ ‘x)}))
 
Theoremcardalephex 3691 Every transfinite cardinal is an aleph and vice-versa. Theorem 8A(b) of [Enderton] p. 213 and its converse.
(ω ⊆ A → ((card ‘A) = A ↔ ∃x ∈ On A = (ℵ ‘x)))
 
Theoremisinfcard 3692 Two ways of expressing the property of being a transfinite cardinal.
((ω ⊆ A ∧ (card ‘A) = A) ↔ A ∈ ran ℵ)
 
Theoremiscard3 3693 Two ways of expressing the property of being a cardinal number.
((card ‘A) = AA ∈ (ω ∪ ran ℵ))
 
Theoremcardnum 3694 Two ways of expressing the class of all cardinal numbers, which consists of the finite ordinals in ω plus the transfinite alephs.
{x∣(card ‘x) = x} = (ω ∪ ran ℵ)
 
Theoremcarduniima 3695 The union of the image of a mapping to cardinals is a cardinal. Proposition 11.16 of [TakeutiZaring] p. 104.
(AB → (F:A–→(ω ∪ ran ℵ) → (FA) ∈ (ω ∪ ran ℵ)))
 
Theoremcardinfima 3696 If a mapping to cardinals has an infinite value, then the union of its image is an infinite cardinal. Corollary 11.17 of [TakeutiZaring] p. 104.
(AB → ((F:A–→(ω ∪ ran ℵ) ∧ ∃xA (Fx) ∈ ran ℵ) → (FA) ∈ ran ℵ))
 
Theoremalephiso 3697 Aleph is an order isomorphism of the class of ordinal numbers onto the class of infinite cardinals. Definition 10.27 of [TakeutiZaring] p. 90.
ℵ Isom E, E (On, {x∣(ω ⊆ x ∧ (card ‘x) = x)})
 
Theoremalephprc 3698 The class of all transfinite cardinal numbers (the range of the aleph function) is a proper class. Proposition 10.26 of [TakeutiZaring] p. 90.
¬ ran ℵ ∈ V
 
Theoremalephsson 3699 The class of transfinite cardinals (the range of the aleph function) is a subclass of the class of ordinal numbers.
ran ℵ ⊆ On
 
Theoremcflem 3700 A lemma used to simplify cofinality computations, showing the existence of the cardinal of an unbounded subset of a set A.
(AB → ∃xy(x = (card ‘y) ∧ (yA ∧ ∀zAwy zw)))

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