Statement List for Metamath Proof Explorer - 301-400 - Page 4 of 58
| Type | Label | Description |
| Statement |
| |
| Theorem | exp43 301 |
An exportation inference.
|
| ⊢
(((φ ∧ ψ) ∧ (χ ∧ θ)) → τ)
⇒ ⊢ (φ → (ψ → (χ → (θ → τ)))) |
| |
| Theorem | exp44 302 |
An exportation inference.
|
| ⊢
((φ ∧ ((ψ ∧ χ) ∧ θ)) → τ)
⇒ ⊢ (φ → (ψ → (χ → (θ → τ)))) |
| |
| Theorem | exp45 303 |
An exportation inference.
|
| ⊢
((φ ∧ (ψ ∧ (χ ∧ θ))) → τ)
⇒ ⊢ (φ → (ψ → (χ → (θ → τ)))) |
| |
| Theorem | impac 304 |
Importation with conjunction in consequent.
|
| ⊢
(φ → (ψ → χ))
⇒ ⊢ ((φ ∧ ψ) → (χ ∧ ψ)) |
| |
| Theorem | adantl 305 |
Inference adding a conjunct to the left of an antecedent.
|
| ⊢
(φ → ψ)
⇒ ⊢ ((χ ∧ φ) → ψ) |
| |
| Theorem | adantr 306 |
Inference adding a conjunct to the right of an antecedent.
|
| ⊢
(φ → ψ)
⇒ ⊢ ((φ ∧ χ) → ψ) |
| |
| Theorem | adantld 307 |
Deduction adding a conjunct to the left of an antecedent.
|
| ⊢
(φ → (ψ → χ))
⇒ ⊢ (φ → ((θ ∧ ψ) → χ)) |
| |
| Theorem | adantrd 308 |
Deduction adding a conjunct to the right of an antecedent.
|
| ⊢
(φ → (ψ → χ))
⇒ ⊢ (φ → ((ψ ∧ θ) → χ)) |
| |
| Theorem | adantll 309 |
Deduction adding a conjunct to an antecedent.
|
| ⊢
((φ ∧ ψ) → χ)
⇒ ⊢ (((θ ∧ φ) ∧ ψ) → χ) |
| |
| Theorem | adantlr 310 |
Deduction adding a conjunct to an antecedent.
|
| ⊢
((φ ∧ ψ) → χ)
⇒ ⊢ (((φ ∧ θ) ∧ ψ) → χ) |
| |
| Theorem | adantrl 311 |
Deduction adding a conjunct to an antecedent.
|
| ⊢
((φ ∧ ψ) → χ)
⇒ ⊢ ((φ ∧ (θ ∧ ψ)) → χ) |
| |
| Theorem | adantrr 312 |
Deduction adding a conjunct to an antecedent.
|
| ⊢
((φ ∧ ψ) → χ)
⇒ ⊢ ((φ ∧ (ψ ∧ θ)) → χ) |
| |
| Theorem | adantlll 313 |
Deduction adding a conjunct to an antecedent.
|
| ⊢
(((φ ∧ ψ) ∧ χ) → θ)
⇒ ⊢ ((((τ ∧ φ) ∧ ψ) ∧ χ) → θ) |
| |
| Theorem | adantlrl 314 |
Deduction adding a conjunct to an antecedent.
|
| ⊢
(((φ ∧ ψ) ∧ χ) → θ)
⇒ ⊢ (((φ ∧ (τ ∧ ψ)) ∧ χ) → θ) |
| |
| Theorem | adantlrr 315 |
Deduction adding a conjunct to an antecedent.
|
| ⊢
(((φ ∧ ψ) ∧ χ) → θ)
⇒ ⊢ (((φ ∧ (ψ ∧ τ)) ∧ χ) → θ) |
| |
| Theorem | adantrll 316 |
Deduction adding a conjunct to an antecedent.
|
| ⊢
((φ ∧ (ψ ∧ χ)) → θ)
⇒ ⊢ ((φ ∧ ((τ ∧ ψ) ∧ χ)) → θ) |
| |
| Theorem | adantrlr 317 |
Deduction adding a conjunct to an antecedent.
|
| ⊢
((φ ∧ (ψ ∧ χ)) → θ)
⇒ ⊢ ((φ ∧ ((ψ ∧ τ) ∧ χ)) → θ) |
| |
| Theorem | adantrrl 318 |
Deduction adding a conjunct to an antecedent.
|
| ⊢
((φ ∧ (ψ ∧ χ)) → θ)
⇒ ⊢ ((φ ∧ (ψ ∧ (τ ∧ χ))) → θ) |
| |
| Theorem | adantrrr 319 |
Deduction adding a conjunct to an antecedent.
|
| ⊢
((φ ∧ (ψ ∧ χ)) → θ)
⇒ ⊢ ((φ ∧ (ψ ∧ (χ ∧ τ))) → θ) |
| |
| Theorem | ad2antll 320 |
Deduction adding conjuncts to an antecedent.
|
| ⊢
(φ → ψ)
⇒ ⊢ (((φ ∧ χ) ∧ θ) → ψ) |
| |
| Theorem | ad2antlr 321 |
Deduction adding conjuncts to an antecedent.
|
| ⊢
(φ → ψ)
⇒ ⊢ (((χ ∧ φ) ∧ θ) → ψ) |
| |
| Theorem | ad2antrl 322 |
Deduction adding conjuncts to an antecedent.
|
| ⊢
(φ → ψ)
⇒ ⊢ ((χ ∧ (φ ∧ θ)) → ψ) |
| |
| Theorem | ad2antrr 323 |
Deduction adding conjuncts to an antecedent.
|
| ⊢
(φ → ψ)
⇒ ⊢ ((χ ∧ (θ ∧ φ)) → ψ) |
| |
| Theorem | biimpa 324 |
Inference from a logical equivalence.
|
| ⊢
(φ → (ψ ↔ χ))
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | biimpar 325 |
Inference from a logical equivalence.
|
| ⊢
(φ → (ψ ↔ χ))
⇒ ⊢ ((φ ∧ χ) → ψ) |
| |
| Theorem | biimpac 326 |
Inference from a logical equivalence.
|
| ⊢
(φ → (ψ ↔ χ))
⇒ ⊢ ((ψ ∧ φ) → χ) |
| |
| Theorem | biimparc 327 |
Inference from a logical equivalence.
|
| ⊢
(φ → (ψ ↔ χ))
⇒ ⊢ ((χ ∧ φ) → ψ) |
| |
| Theorem | jaob 328 |
Disjunction of antecedents. Compare Theorem *4.77 of
[WhiteheadRussell] p. 121.
|
| ⊢
(((φ ∨ χ) → ψ) ↔ ((φ → ψ) ∧ (χ → ψ))) |
| |
| Theorem | jaod 329 |
Deduction disjoining the antecedents of two implications.
|
| ⊢
(φ → (ψ → χ))
& ⊢ (φ → (θ → χ))
⇒ ⊢ (φ → ((ψ ∨ θ) → χ)) |
| |
| Theorem | jaao 330 |
Inference conjoining and disjoining the antecedents of two
implications.
|
| ⊢
(φ → (ψ → χ))
& ⊢ (θ → (τ → χ))
⇒ ⊢ ((φ ∧ θ) → ((ψ ∨ τ) → χ)) |
| |
| Theorem | anidm 331 |
Idempotent law for conjunction. Theorem *4.24 of [WhiteheadRussell]
p. 117.
|
| ⊢
((φ ∧ φ) ↔ φ) |
| |
| Theorem | anidms 332 |
Inference from idempotent law for conjunction.
|
| ⊢
((φ ∧ φ) → ψ)
⇒ ⊢ (φ → ψ) |
| |
| Theorem | ancom 333 |
Commutative law for conjunction. Theorem *4.3 of [WhiteheadRussell]
p. 118.
|
| ⊢
((φ ∧ ψ) ↔ (ψ ∧ φ)) |
| |
| Theorem | ancoms 334 |
Inference commuting conjunction in antecedent. Notational convention:
We sometimes suffix with "s" the label of an inference that
manipulates
an antecedent, leaving the consequent unchanged. The "s"
means that the
inference eliminates the need for a syllogism (syl 12)
-type inference
in a proof.
|
| ⊢
((φ ∧ ψ) → χ)
⇒ ⊢ ((ψ ∧ φ) → χ) |
| |
| Theorem | ancomsd 335 |
Deduction commuting conjunction in antecedent.
|
| ⊢
(φ → ((ψ ∧ χ) → θ))
⇒ ⊢ (φ → ((χ ∧ ψ) → θ)) |
| |
| Theorem | anass 336 |
Associative law for conjunction. Theorem *4.32 of [WhiteheadRussell]
p. 118.
|
| ⊢
(((φ ∧ ψ) ∧ χ) ↔ (φ ∧ (ψ ∧ χ))) |
| |
| Theorem | anasss 337 |
Associative law for conjunction applied to antecedent (eliminates
syllogism).
|
| ⊢
(((φ ∧ ψ) ∧ χ) → θ)
⇒ ⊢ ((φ ∧ (ψ ∧ χ)) → θ) |
| |
| Theorem | anassrs 338 |
Associative law for conjunction applied to antecedent (eliminates
syllogism).
|
| ⊢
((φ ∧ (ψ ∧ χ)) → θ)
⇒ ⊢ (((φ ∧ ψ) ∧ χ) → θ) |
| |
| Theorem | imdistan 339 |
Distribution of implication with conjunction.
|
| ⊢
((φ → (ψ → χ)) ↔ ((φ ∧ ψ) → (φ ∧ χ))) |
| |
| Theorem | imdistani 340 |
Distribution of implication with conjunction.
|
| ⊢
(φ → (ψ → χ))
⇒ ⊢ ((φ ∧ ψ) → (φ ∧ χ)) |
| |
| Theorem | imdistanri 341 |
Distribution of implication with conjunction.
|
| ⊢
(φ → (ψ → χ))
⇒ ⊢ ((ψ ∧ φ) → (χ ∧ φ)) |
| |
| Theorem | imdistand 342 |
Distribution of implication with conjunction (deduction rule).
|
| ⊢
(φ → (ψ → (χ → θ)))
⇒ ⊢ (φ → ((ψ ∧ χ) → (ψ ∧ θ))) |
| |
| Theorem | sylan 343 |
A syllogism inference.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (θ → φ)
⇒ ⊢ ((θ ∧ ψ) → χ) |
| |
| Theorem | sylanb 344 |
A syllogism inference.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (θ ↔ φ)
⇒ ⊢ ((θ ∧ ψ) → χ) |
| |
| Theorem | sylanbr 345 |
A syllogism inference.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (φ ↔ θ)
⇒ ⊢ ((θ ∧ ψ) → χ) |
| |
| Theorem | sylan2 346 |
A syllogism inference.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (θ → ψ)
⇒ ⊢ ((φ ∧ θ) → χ) |
| |
| Theorem | sylan2b 347 |
A syllogism inference.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (θ ↔ ψ)
⇒ ⊢ ((φ ∧ θ) → χ) |
| |
| Theorem | sylan2br 348 |
A syllogism inference.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (ψ ↔ θ)
⇒ ⊢ ((φ ∧ θ) → χ) |
| |
| Theorem | syl2an 349 |
A double syllogism inference.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (θ → φ)
& ⊢ (τ → ψ)
⇒ ⊢ ((θ ∧ τ) → χ) |
| |
| Theorem | syl2anb 350 |
A double syllogism inference.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (θ ↔ φ)
& ⊢ (τ ↔ ψ)
⇒ ⊢ ((θ ∧ τ) → χ) |
| |
| Theorem | syl2anbr 351 |
A double syllogism inference.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (φ ↔ θ)
& ⊢ (ψ ↔ τ)
⇒ ⊢ ((θ ∧ τ) → χ) |
| |
| Theorem | syland 352 |
A syllogism deduction.
|
| ⊢
(φ → ((ψ ∧ χ) → θ))
& ⊢ (φ → (τ → ψ))
⇒ ⊢ (φ → ((τ ∧ χ) → θ)) |
| |
| Theorem | sylan2d 353 |
A syllogism deduction.
|
| ⊢
(φ → ((ψ ∧ χ) → θ))
& ⊢ (φ → (τ → χ))
⇒ ⊢ (φ → ((ψ ∧ τ) → θ)) |
| |
| Theorem | syl2and 354 |
A syllogism deduction.
|
| ⊢
(φ → ((ψ ∧ χ) → θ))
& ⊢ (φ → (τ → ψ))
& ⊢ (φ → (η → χ))
⇒ ⊢ (φ → ((τ ∧ η) → θ)) |
| |
| Theorem | sylan12 355 |
A syllogism inference.
|
| ⊢
(((φ ∧ ψ) ∧ χ) → θ)
& ⊢ (τ → ψ)
⇒ ⊢ (((φ ∧ τ) ∧ χ) → θ) |
| |
| Theorem | sylani 356 |
A syllogism inference.
|
| ⊢
(φ → ((ψ ∧ χ) → θ))
& ⊢ (τ → ψ)
⇒ ⊢ (φ → ((τ ∧ χ) → θ)) |
| |
| Theorem | sylan2i 357 |
A syllogism inference.
|
| ⊢
(φ → ((ψ ∧ χ) → θ))
& ⊢ (τ → χ)
⇒ ⊢ (φ → ((ψ ∧ τ) → θ)) |
| |
| Theorem | syl2ani 358 |
A syllogism inference.
|
| ⊢
(φ → ((ψ ∧ χ) → θ))
& ⊢ (τ → ψ)
& ⊢ (η → χ)
⇒ ⊢ (φ → ((τ ∧ η) → θ)) |
| |
| Theorem | sylan9 359 |
Nested syllogism inference conjoining dissimilar antecedents.
|
| ⊢
(φ → (ψ → χ))
& ⊢ (θ → (χ → τ))
⇒ ⊢ ((φ ∧ θ) → (ψ → τ)) |
| |
| Theorem | sylan9r 360 |
Nested syllogism inference conjoining dissimilar antecedents.
|
| ⊢
(φ → (ψ → χ))
& ⊢ (θ → (χ → τ))
⇒ ⊢ ((θ ∧ φ) → (ψ → τ)) |
| |
| Theorem | sylanc 361 |
A syllogism inference combined with contraction.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (θ → φ)
& ⊢ (θ → ψ)
⇒ ⊢ (θ → χ) |
| |
| Theorem | sylancb 362 |
A syllogism inference combined with contraction.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (θ ↔ φ)
& ⊢ (θ ↔ ψ)
⇒ ⊢ (θ → χ) |
| |
| Theorem | sylancbr 363 |
A syllogism inference combined with contraction.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ (φ ↔ θ)
& ⊢ (ψ ↔ θ)
⇒ ⊢ (θ → χ) |
| |
| Theorem | pm2.61an1 364 |
Elimination of an antecedent.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ ((¬ φ ∧ ψ) → χ)
⇒ ⊢ (ψ → χ) |
| |
| Theorem | pm2.61an2 365 |
Elimination of an antecedent.
|
| ⊢
((φ ∧ ψ) → χ)
& ⊢ ((φ ∧ ¬ ψ) → χ)
⇒ ⊢ (φ → χ) |
| |
| Theorem | abai 366 |
Introduce one conjunct as an antecedent to the another.
|
| ⊢
((φ ∧ ψ) ↔ (φ ∧ (φ → ψ))) |
| |
| Theorem | anbi2i 367 |
Introduce a left conjunct to both sides of a logical equivalence.
|
| ⊢
(φ ↔ ψ)
⇒ ⊢ ((χ ∧ φ) ↔ (χ ∧ ψ)) |
| |
| Theorem | anbi1i 368 |
Introduce a right conjunct to both sides of a logical equivalence.
|
| ⊢
(φ ↔ ψ)
⇒ ⊢ ((φ ∧ χ) ↔ (ψ ∧ χ)) |
| |
| Theorem | anbi12i 369 |
Conjoin both sides of two equivalences.
|
| ⊢
(φ ↔ ψ)
& ⊢ (χ ↔ θ)
⇒ ⊢ ((φ ∧ χ) ↔ (ψ ∧ θ)) |
| |
| Theorem | an12 370 |
A rearrangement of conjuncts.
|
| ⊢
((φ ∧ (ψ ∧ χ)) ↔ (ψ ∧ (φ ∧ χ))) |
| |
| Theorem | an23 371 |
A rearrangement of conjuncts.
|
| ⊢
(((φ ∧ ψ) ∧ χ) ↔ ((φ ∧ χ) ∧ ψ)) |
| |
| Theorem | an1s 372 |
Deduction rearranging conjuncts.
|
| ⊢
((φ ∧ (ψ ∧ χ)) → θ)
⇒ ⊢ ((ψ ∧ (φ ∧ χ)) → θ) |
| |
| Theorem | an1rs 373 |
Deduction rearranging conjuncts.
|
| ⊢
(((φ ∧ ψ) ∧ χ) → θ)
⇒ ⊢ (((φ ∧ χ) ∧ ψ) → θ) |
| |
| Theorem | anabs1 374 |
Absorption into embedded conjunct.
|
| ⊢
(((φ ∧ ψ) ∧ φ) ↔ (φ ∧ ψ)) |
| |
| Theorem | anabs5 375 |
Absorption into embedded conjunct.
|
| ⊢
((φ ∧ (φ ∧ ψ)) ↔ (φ ∧ ψ)) |
| |
| Theorem | anabs7 376 |
Absorption into embedded conjunct.
|
| ⊢
((ψ ∧ (φ ∧ ψ)) ↔ (φ ∧ ψ)) |
| |
| Theorem | anabsi5 377 |
Absorption of antecedent into conjunction.
|
| ⊢
(φ → ((φ ∧ ψ) → χ))
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | anabsi6 378 |
Absorption of antecedent into conjunction.
|
| ⊢
(φ → ((ψ ∧ φ) → χ))
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | anabsi7 379 |
Absorption of antecedent into conjunction.
|
| ⊢
(ψ → ((φ ∧ ψ) → χ))
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | anabsi8 380 |
Absorption of antecedent into conjunction.
|
| ⊢
(ψ → ((ψ ∧ φ) → χ))
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | anabss1 381 |
Absorption of antecedent into conjunction.
|
| ⊢
(((φ ∧ ψ) ∧ φ) → χ)
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | anabss3 382 |
Absorption of antecedent into conjunction.
|
| ⊢
(((φ ∧ ψ) ∧ ψ) → χ)
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | anabss4 383 |
Absorption of antecedent into conjunction.
|
| ⊢
(((ψ ∧ φ) ∧ ψ) → χ)
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | anabss5 384 |
Absorption of antecedent into conjunction.
|
| ⊢
((φ ∧ (φ ∧ ψ)) → χ)
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | anabss7 385 |
Absorption of antecedent into conjunction.
|
| ⊢
((ψ ∧ (φ ∧ ψ)) → χ)
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | anabsan 386 |
Absorption of antecedent with conjunction.
|
| ⊢
(((φ ∧ φ) ∧ ψ) → χ)
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | anabsan2 387 |
Absorption of antecedent with conjunction.
|
| ⊢
((φ ∧ (ψ ∧ ψ)) → χ)
⇒ ⊢ ((φ ∧ ψ) → χ) |
| |
| Theorem | an4 388 |
Rearrangement of 4 conjuncts.
|
| ⊢
(((φ ∧ ψ) ∧ (χ ∧ θ)) ↔ ((φ ∧ χ) ∧ (ψ ∧ θ))) |
| |
| Theorem | an42 389 |
Rearrangement of 4 conjuncts.
|
| ⊢
(((φ ∧ ψ) ∧ (χ ∧ θ)) ↔ ((φ ∧ χ) ∧ (θ ∧ ψ))) |
| |
| Theorem | an4s 390 |
Inference rearranging 4 conjuncts in antecedent.
|
| ⊢
(((φ ∧ ψ) ∧ (χ ∧ θ)) → τ)
⇒ ⊢ (((φ ∧ χ) ∧ (ψ ∧ θ)) → τ) |
| |
| Theorem | an42s 391 |
Inference rearranging 4 conjuncts in antecedent.
|
| ⊢
(((φ ∧ ψ) ∧ (χ ∧ θ)) → τ)
⇒ ⊢ (((φ ∧ χ) ∧ (θ ∧ ψ)) → τ) |
| |
| Theorem | anandi 392 |
Distribution of conjunction over conjunction.
|
| ⊢
((φ ∧ (ψ ∧ χ)) ↔ ((φ ∧ ψ) ∧ (φ ∧ χ))) |
| |
| Theorem | anandir 393 |
Distribution of conjunction over conjunction.
|
| ⊢
(((φ ∧ ψ) ∧ χ) ↔ ((φ ∧ χ) ∧ (ψ ∧ χ))) |
| |
| Theorem | anandis 394 |
Inference that undistributes conjunction in the antecedent.
|
| ⊢
(((φ ∧ ψ) ∧ (φ ∧ χ)) → τ)
⇒ ⊢ ((φ ∧ (ψ ∧ χ)) → τ) |
| |
| Theorem | anandirs 395 |
Inference that undistributes conjunction in the antecedent.
|
| ⊢
(((φ ∧ χ) ∧ (ψ ∧ χ)) → τ)
⇒ ⊢ (((φ ∧ ψ) ∧ χ) → τ) |
| |
| Theorem | bi 396 |
A theorem similar to the standard definition of the biconditional.
Definition of [Margaris] p. 49.
|
| ⊢
((φ ↔ ψ) ↔ ((φ → ψ) ∧ (ψ → φ))) |
| |
| Theorem | impbid 397 |
Deduce an equivalence from two implications.
|
| ⊢
(φ → (ψ → χ))
& ⊢ (φ → (χ → ψ))
⇒ ⊢ (φ → (ψ ↔ χ)) |
| |
| Theorem | bicom 398 |
Commutative law for equivalence. Theorem *4.21 of [WhiteheadRussell]
p. 117.
|
| ⊢
((φ ↔ ψ) ↔ (ψ ↔ φ)) |
| |
| Theorem | bicomd 399 |
Commute two sides of a biconditional in a deduction.
|
| ⊢
(φ → (ψ ↔ χ))
⇒ ⊢ (φ → (χ ↔ ψ)) |
| |
| Theorem | pm4.11 400 |
Contraposition. Theorem *4.11 of [WhiteheadRussell] p. 117.
|
| ⊢
((φ ↔ ψ) ↔ (¬ φ ↔ ¬ ψ)) |