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Statement List for Metamath Proof Explorer - 4101-4200 - Page 42 of 58
TypeLabelDescription
Statement
 
Theorem1cn 4101 1 is a complex number.
1 ∈ ℂ
 
Theoremelimne0 4102 Hypothesis for weak deduction theorem to eliminate A ≠ 0.
if(A ≠ 0, A, 1) ≠ 0
 
Theoremadddirt 4103 Distributive law for complex numbers.
((A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ) → ((A + B) · C) = ((A · C) + (B · C)))
 
Theoremaddcl 4104 Closure law for addition.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (A + B) ∈ ℂ
 
Theoremmulcl 4105 Closure law for multiplication.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (A · B) ∈ ℂ
 
Theoremaddcom 4106 Commutative law for addition.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (A + B) = (B + A)
 
Theoremmulcom 4107 Commutative law for multiplication.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (A · B) = (B · A)
 
Theoremaddass 4108 Associative law for addition.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((A + B) + C) = (A + (B + C))
 
Theoremmulass 4109 Associative law for multiplication.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((A · B) · C) = (A · (B · C))
 
Theoremadddi 4110 Distributive law.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   (A · (B + C)) = ((A · B) + (A · C))
 
Theoremadddir 4111 Distributive law.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((A + B) · C) = ((A · C) + (B · C))
 
Theoremaddid1 4112 Identity law for addition.
A ∈ ℂ    ⇒   (A + 0) = A
 
Theoremaddid2 4113 Identity law for addition.
A ∈ ℂ    ⇒   (0 + A) = A
 
Theoremmulid1 4114 Identity law for multiplication.
A ∈ ℂ    ⇒   (A · 1) = A
 
Theoremmulid2 4115 Identity law for multiplication.
A ∈ ℂ    ⇒   (1 · A) = A
 
Theoremnegex 4116 Existence of negatives.
A ∈ ℂ    ⇒   x ∈ ℂ (A + x) = 0
 
Theoremrecex 4117 Existence of reciprocals.
A ∈ ℂ    &   A ≠ 0    ⇒   x ∈ ℂ (A · x) = 1
 
Theoremreaddcl 4118 Closure law for addition of reals.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (A + B) ∈ ℝ
 
Theoremremulcl 4119 Closure law for multiplication of reals.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (A · B) ∈ ℝ
 
Theoremaddcan 4120 Cancellation law for addition. Theorem I.1 of [Apostol] p. 18.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((A + B) = (A + C) ↔ B = C)
 
Theoremaddcan2 4121 Cancellation law for addition.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((A + C) = (B + C) ↔ A = B)
 
Theoremaddcant 4122 Cancellation law for addition. Theorem I.1 of [Apostol] p. 18. This proof illustrates how dedth3h 1788 can be used to convert the assumptions of addcan 4120 into antecedents. This general method can be used to convert deductions into theorems as needed.
((A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ) → ((A + B) = (A + C) ↔ B = C))
 
Theoremaddcan2t 4123 Cancellation law for addition.
((A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ) → ((A + C) = (B + C) ↔ A = B))
 
Theoremnegeu 4124 Existential uniqueness of negatives. Theorem I.2 of [Apostol] p. 18.
A ∈ ℂ    &   B ∈ ℂ    ⇒   ∃!x ∈ ℂ (A + x) = B
 
Theoremadd12t 4125 Commutative/associative law that swaps the first two terms in a triple sum.
((A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ) → (A + (B + C)) = (B + (A + C)))
 
Theoremadd23t 4126 Commutative/associative law that swaps the last two terms in a triple sum.
((A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ) → ((A + B) + C) = ((A + C) + B))
 
Theoremadd4t 4127 Rearrangement of 4 terms in a sum.
(((A ∈ ℂ ∧ B ∈ ℂ) ∧ (C ∈ ℂ ∧ D ∈ ℂ)) → ((A + B) + (C + D)) = ((A + C) + (B + D)))
 
Theoremadd12 4128 Commutative/associative law that swaps the first two terms in a triple sum.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   (A + (B + C)) = (B + (A + C))
 
Theoremadd23 4129 Commutative/associative law that swaps the last two terms in a triple sum.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((A + B) + C) = ((A + C) + B)
 
Theoremadd4 4130 Rearrangement of 4 terms in a sum.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    &   D ∈ ℂ    ⇒   ((A + B) + (C + D)) = ((A + C) + (B + D))
 
Theoremadd42 4131 Rearrangement of 4 terms in a sum.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    &   D ∈ ℂ    ⇒   ((A + B) + (C + D)) = ((A + C) + (D + B))
 
Theoremaddid2t 4132 Identity law for addition.
(A ∈ ℂ → (0 + A) = A)
 
Definitiondf-sub 4133 Define subtraction. Theorem subval 4134 shows it value (and describes how this definition works), theorem subadd 4143 relates it to addition, and theorems subcl 4139 and resubcl 4174 prove its closure laws.
− = {⟨⟨x, y⟩, z⟩∣((x ∈ ℂ ∧ y ∈ ℂ) ∧ z = {w ∈ ℂ∣(y + w) = x})}
 
Theoremsubval 4134 Value of subtraction, which is the (unique) element x such that B + x = A. The notation {x ∈ ℂ∣(B + x) = A} may at first seem cryptic but is actually a way of saying "the element x such that B + x = A" (see Theorem 8.17 of [Quine] p. 56); this works because there is only one such x as shown by negeu 4124, allowing us to exploit eusn 1913 and unisn 1932 (which you will find if you trace back the proof of subcl 4139).
A ∈ ℂ    &   B ∈ ℂ    ⇒   (AB) = {x ∈ ℂ∣(B + x) = A}
 
Definitiondf-neg 4135 Define the negative of a number (unary minus). We use different symbols for unary minus (-) and subtraction (−) to prevent syntax ambiguity. See cneg 4090 for a discussion of this.
-A = (0 − A)
 
Theoremnegeq 4136 Equality theorem for negatives.
(A = B → -A = -B)
 
Theoremnegeqi 4137 Equality inference for negatives.
A = B    ⇒   -A = -B
 
Theoremnegeqd 4138 Equality deduction for negatives.
(φA = B)    ⇒   (φ → -A = -B)
 
Theoremsubcl 4139 Closure law for subtraction.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (AB) ∈ ℂ
 
Theoremsubclt 4140 Closure law for subtraction.
((A ∈ ℂ ∧ B ∈ ℂ) → (AB) ∈ ℂ)
 
Theoremnegclt 4141 Closure law for negative.
(A ∈ ℂ → -A ∈ ℂ)
 
Theoremnegcl 4142 Closure law for negative.
A ∈ ℂ    ⇒   -A ∈ ℂ
 
Theoremsubadd 4143 Relationship between subtraction and addition.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((AB) = C ↔ (B + C) = A)
 
Theoremsubsub 4144 Relationship between subtraction and subtraction.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((AB) = C ↔ (AC) = B)
 
Theoremsubaddt 4145 Relationship between subtraction and addition.
((A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ) → ((AB) = C ↔ (B + C) = A))
 
Theoremsubaddeq 4146 Subtraction and addition of equals.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (A + (BA)) = B
 
Theoremnegid 4147 Addition of a number and its negative.
A ∈ ℂ    ⇒   (A + -A) = 0
 
Theoremsubneg 4148 Relationship between subtraction and negative. Theorem I.3 of [Apostol] p. 18.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (AB) = (A + -B)
 
Theoremsubnegt 4149 Relationship between subtraction and negative. Theorem I.3 of [Apostol] p. 18.
((A ∈ ℂ ∧ B ∈ ℂ) → (AB) = (A + -B))
 
Theoremaddsubasst 4150 Associative-type law for subtraction and addition.
((A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ) → ((A + B) − C) = (A + (BC)))
 
Theoremaddsubt 4151 Law for subtraction and addition.
((A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ) → ((A + B) − C) = ((AC) + B))
 
Theoremaddsubass 4152 Associative-type law for subtraction and addition.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((A + B) − C) = (A + (BC))
 
Theoremaddsub 4153 Law for subtraction and addition.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((A + B) − C) = ((AC) + B)
 
Theoremnegneg 4154 A number is equal to the negative of its negative. Theorem I.4 of [Apostol] p. 18.
A ∈ ℂ    ⇒   --A = A
 
Theoremsubid 4155 Subtraction of a number from itself.
A ∈ ℂ    ⇒   (AA) = 0
 
Theoremsubid1 4156 Identity law for subtraction.
A ∈ ℂ    ⇒   (A − 0) = A
 
Theoremnegnegt 4157 A number is equal to the negative of its negative. Theorem I.4 of [Apostol] p. 18.
(A ∈ ℂ → --A = A)
 
Theoremsubneg2t 4158 Relationship between subtraction and negative.
((A ∈ ℂ ∧ B ∈ ℂ) → (A − -B) = (A + B))
 
Theoremsubidt 4159 Subtraction of a number from itself.
(A ∈ ℂ → (AA) = 0)
 
Theoremsubid1t 4160 Identity law for subtraction.
(A ∈ ℂ → (A − 0) = A)
 
Theorempncant 4161 Cancellation law for subtraction.
((A ∈ ℂ ∧ B ∈ ℂ) → ((A + B) − B) = A)
 
Theoremnpcant 4162 Cancellation law for subtraction.
((A ∈ ℂ ∧ B ∈ ℂ) → ((AB) + B) = A)
 
Theoremsubeq0 4163 If the difference between two numbers is zero, they are equal.
A ∈ ℂ    &   B ∈ ℂ    ⇒   ((AB) = 0 ↔ A = B)
 
Theoremneg11 4164 Negative is one-to-one.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (-A = -BA = B)
 
Theoremnegcon1 4165 Negative contraposition law.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (-A = B ↔ -B = A)
 
Theoremnegcon2 4166 Negative contraposition law.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (A = -BB = -A)
 
Theoremnegcon1t 4167 Negative contraposition law.
((A ∈ ℂ ∧ B ∈ ℂ) → (-A = B ↔ -B = A))
 
Theoremnegcon2t 4168 Negative contraposition law.
((A ∈ ℂ ∧ B ∈ ℂ) → (A = -BB = -A))
 
Theoremsubeq0t 4169 If the difference between two numbers is zero, they are equal.
((A ∈ ℂ ∧ B ∈ ℂ) → ((AB) = 0 ↔ A = B))
 
Theoremneg0 4170 Minus 0 equals 0.
-0 = 0
 
Theoremrenegcl 4171 Closure law for negative of reals.
A ∈ ℝ    ⇒   -A ∈ ℝ
 
Theoremrenegclt 4172 Closure law for negative of reals.
(A ∈ ℝ → -A ∈ ℝ)
 
Theoremresubclt 4173 Closure law for subtraction of reals.
((A ∈ ℝ ∧ B ∈ ℝ) → (AB) ∈ ℝ)
 
Theoremresubcl 4174 Closure law for subtraction of reals.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (AB) ∈ ℝ
 
Theoremmulid2t 4175 Identity law for multiplication. Note: see ax1id 4077 for commuted version.
(A ∈ ℂ → (1 · A) = A)
 
Theoremmul23t 4176 Commutative/associative law.
((A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ) → ((A · B) · C) = ((A · C) · B))
 
Theoremmul4t 4177 Rearrangement of 4 factors.
(((A ∈ ℂ ∧ B ∈ ℂ) ∧ (C ∈ ℂ ∧ D ∈ ℂ)) → ((A · B) · (C · D)) = ((A · C) · (B · D)))
 
Theoremmul12 4178 Commutative/associative law that swaps the first two factors in a triple product.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   (A · (B · C)) = (B · (A · C))
 
Theoremmul23 4179 Commutative/associative law that swaps the last two factors in a triple product.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((A · B) · C) = ((A · C) · B)
 
Theoremmul4 4180 Rearrangement of 4 factors.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    &   D ∈ ℂ    ⇒   ((A · B) · (C · D)) = ((A · C) · (B · D))
 
Theoremmuladd 4181 Product of sums.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    &   D ∈ ℂ    ⇒   ((A + B) · (C + D)) = (((A · C) + (D · B)) + ((A · D) + (C · B)))
 
Theoremsubdi 4182 Distribution of multiplication over subtraction. Theorem I.5 of [Apostol] p. 18.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   (A · (BC)) = ((A · B) − (A · C))
 
Theoremsubdir 4183 Distribution of multiplication over subtraction. Theorem I.5 of [Apostol] p. 18.
A ∈ ℂ    &   B ∈ ℂ    &   C ∈ ℂ    ⇒   ((AB) · C) = ((A · C) − (B · C))
 
Theoremsubdit 4184 Distribution of multiplication over subtraction. Theorem I.5 of [Apostol] p. 18.
((A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ) → (A · (BC)) = ((A · B) − (A · C)))
 
Theoremmulzer1 4185 Multiplication by 0. Theorem I.6 of [Apostol] p. 18.
A ∈ ℂ    ⇒   (A · 0) = 0
 
Theoremmulzer2 4186 Multiplication by 0. Theorem I.6 of [Apostol] p. 18.
A ∈ ℂ    ⇒   (0 · A) = 0
 
Theorem1p1times 4187 Two times a number.
A ∈ ℂ    ⇒   ((1 + 1) · A) = (A + A)
 
Theoremmulzer1t 4188 Multiplication by 0. Theorem I.6 of [Apostol] p. 18.
(A ∈ ℂ → (A · 0) = 0)
 
Theoremmulzer2t 4189 Multiplication by 0. Theorem I.6 of [Apostol] p. 18.
(A ∈ ℂ → (0 · A) = 0)
 
Theoremmulneg1 4190 Product with negative is negative of product. Theorem I.12 of [Apostol] p. 18.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (-A · B) = -(A · B)
 
Theoremmulneg2 4191 Product with negative is negative of product.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (A · -B) = -(A · B)
 
Theoremmul2neg 4192 Product of two negatives. Theorem I.12 of [Apostol] p. 18.
A ∈ ℂ    &   B ∈ ℂ    ⇒   (-A · -B) = (A · B)
 
Theoremnegdi 4193 Distribution of negative over addition.
A ∈ ℂ    &   B ∈ ℂ    ⇒   -(A + B) = (-A + -B)
 
Theoremnegdi2 4194 Distribution of negative over subtraction.
A ∈ ℂ    &   B ∈ ℂ    ⇒   -(AB) = (-A + B)
 
Theoremnegdi3 4195 Distribution of negative over subtraction.
A ∈ ℂ    &   B ∈ ℂ    ⇒   -(AB) = (BA)
 
Theoremmulneg1t 4196 Product with negative is negative of product. Theorem I.12 of [Apostol] p. 18.
((A ∈ ℂ ∧ B ∈ ℂ) → (-A · B) = -(A · B))
 
Theoremmulneg2t 4197 The product with a negative is the negative of the product.
((A ∈ ℂ ∧ B ∈ ℂ) → (A · -B) = -(A · B))
 
Theoremmulneg12t 4198 Swap the negative sign in a product.
((A ∈ ℂ ∧ B ∈ ℂ) → (-A · B) = (A · -B))
 
Theoremmul2negt 4199 Product of two negatives. Theorem I.12 of [Apostol] p. 18.
((A ∈ ℂ ∧ B ∈ ℂ) → (-A · -B) = (A · B))
 
Theoremnegdit 4200 Distribution of negative over addition.
((A ∈ ℂ ∧ B ∈ ℂ) → -(A + B) = (-A + -B))

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