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Statement List for Metamath Proof Explorer - 4301-4400 - Page 44 of 58
TypeLabelDescription
Statement
 
Theoremlelt 4301 'Less than or equal to' in terms of 'less than'.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (AB ↔ ¬ B < A)
 
Theoremltle 4302 'Less than' implies 'less than or equal to'.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (A < BAB)
 
Theoremltlei 4303 'Less than' implies 'less than or equal to' (inference).
A ∈ ℝ    &   B ∈ ℝ    &   A < B    ⇒   AB
 
Theoremeqle 4304 Equality implies 'less than or equal to'.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (A = BAB)
 
Theoremltne 4305 'Less than' implies not equal.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (A < B → ¬ A = B)
 
Theoremletri 4306 Trichotomy law for 'less than or equal to'.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (ABBA)
 
Theoremlttr 4307 'Less than' is transitive. Theorem I.17 of [Apostol] p. 20.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   ((A < BB < C) → A < C)
 
Theoremlelttr 4308 'Less than or equal to', 'less than' transitive law.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   ((ABB < C) → A < C)
 
Theoremltletr 4309 'Less than', 'less than or equal to' transitive law.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   ((A < BBC) → A < C)
 
Theoremletr 4310 'Less than or equal to' is transitive.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   ((ABBC) → AC)
 
Theoremle2tri3 4311 Extended trichotomy law for 'less than or equal to'.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   ((ABBCCA) ↔ (A = BB = CC = A))
 
Theoremltadd2 4312 Addition to both sides of 'less than'.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   (A < B ↔ (C + A) < (C + B))
 
Theoremltadd1 4313 Addition to both sides of 'less than'. Theorem I.18 of [Apostol] p. 20.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   (A < B ↔ (A + C) < (B + C))
 
Theoremleadd1 4314 Addition to both sides of 'less than or equal to'.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   (AB ↔ (A + C) ≤ (B + C))
 
Theoremleadd2 4315 Addition to both sides of 'less than or equal to'.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   (AB ↔ (C + A) ≤ (C + B))
 
Theoremltsubadd 4316 'Less than' relationship between subtraction and addition.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   ((AB) < CA < (C + B))
 
Theoremltsubadd2 4317 'Less than' relationship between subtraction and addition.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   ((AB) < CA < (B + C))
 
Theoremlesubadd2 4318 'Less than or equal to' relationship between subtraction and addition.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   ((AB) ≤ CA ≤ (B + C))
 
Theoremlesubadd 4319 'Less than or equal to' relationship between subtraction and addition.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   ((AB) ≤ CA ≤ (C + B))
 
Theoremltaddsub 4320 'Less than' relationship between subtraction and addition.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   ((A + B) < CA < (CB))
 
Theoremlt2add 4321 Adding both side of two inequalities. Theorem I.25 of [Apostol] p. 20.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    &   D ∈ ℝ    ⇒   ((A < CB < D) → (A + B) < (C + D))
 
Theoremle2add 4322 Adding both side of two inequalities.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    &   D ∈ ℝ    ⇒   ((ACBD) → (A + B) ≤ (C + D))
 
Theoremaddgt0 4323 Addition of 2 positive numbers is positive.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 < A ∧ 0 < B) → 0 < (A + B))
 
Theoremaddge0 4324 Addition of 2 nonnegative numbers is nonnegative.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ∧ 0 ≤ B) → 0 ≤ (A + B))
 
Theoremaddgegt0 4325 Addition of nonnegative and positive numbers is positive.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ∧ 0 < B) → 0 < (A + B))
 
Theoremaddgt0i 4326 Addition of 2 positive numbers is positive.
A ∈ ℝ    &   B ∈ ℝ    &   0 < A    &   0 < B    ⇒   0 < (A + B)
 
Theoremltaddpos 4327 Adding a positive number to another number increases it.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (0 < AB < (B + A))
 
Theoremposdif 4328 Comparison of two numbers whose difference is positive.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (A < B ↔ 0 < (BA))
 
Theoremadd20 4329 Two nonnegative numbers are zero iff their sum is zero.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ∧ 0 ≤ B) → ((A + B) = 0 ↔ (A = 0 ∧ B = 0)))
 
Theoremltneg 4330 Negative of both sides of 'less than'. Theorem I.23 of [Apostol] p. 20.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (A < B ↔ -B < -A)
 
Theoremleneg 4331 Negative of both sides of 'less than or equal to'.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (AB ↔ -B ≤ -A)
 
Theoremltnegcon1 4332 Contraposition of negative in 'less than'.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (-A < B ↔ -B < A)
 
Theoremltnegcon2 4333 Contraposition of negative in 'less than'.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (A < -BB < -A)
 
Theoremmulgt0 4334 The product of two positive numbers is positive.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 < A ∧ 0 < B) → 0 < (A · B))
 
Theoremmulge0 4335 The product of two nonnegative numbers is nonnegative.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ∧ 0 ≤ B) → 0 ≤ (A · B))
 
Theoremmulgt0i 4336 The product of two positive numbers is positive.
A ∈ ℝ    &   B ∈ ℝ    &   0 < A    &   0 < B    ⇒   0 < (A · B)
 
Theoremltmullem 4337 Multiplication of both sides of 'less than' by a positive number. Theorem I.19 of [Apostol] p. 20.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   (0 < C → (A < B → (A · C) < (B · C)))
 
Theoremltnr 4338 'Less than' is irreflexive.
A ∈ ℝ    ⇒    ¬ A < A
 
Theoremleid 4339 'Less than or equal to' is reflexive.
A ∈ ℝ    ⇒   AA
 
Theoremgt0ne0 4340 Positive means non-zero (useful for ordering theorems involving division).
A ∈ ℝ    ⇒   (0 < AA ≠ 0)
 
Theoremlesub0 4341 Lemma to show a nonnegative number is zero.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ AB ≤ (BA)) ↔ A = 0)
 
Theoremsubge0 4342 Nonnegative subtraction.
A ∈ ℝ    &   B ∈ ℝ    ⇒   (0 ≤ (AB) ↔ BA)
 
Theoremsqgt0 4343 A non-zero square is positive. Theorem I.20 of [Apostol] p. 20.
A ∈ ℝ    ⇒   A = 0 → 0 < (A · A))
 
Theoremsqge0 4344 A square is nonnegative.
A ∈ ℝ    ⇒   0 ≤ (A · A)
 
Theoremgt0ne0i 4345 Positive implies nonzero.
A ∈ ℝ    &   0 < A    ⇒   A ≠ 0
 
Theoremgt0ne0t 4346 Positive implies nonzero.
(A ∈ ℝ → (0 < AA ≠ 0))
 
Theoremletrit 4347 Trichotomy law.
((A ∈ ℝ ∧ B ∈ ℝ) → (ABBA))
 
Theoremltadd1t 4348 Addition to both sides of 'less than'.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → (A < B ↔ (A + C) < (B + C)))
 
Theoremltadd2t 4349 Addition to both sides of 'less than'.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → (A < B ↔ (C + A) < (C + B)))
 
Theoremleadd1t 4350 Addition to both sides of 'less than or equal to'.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → (AB ↔ (A + C) ≤ (B + C)))
 
Theoremleadd2t 4351 Addition to both sides of 'less than or equal to'.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → (AB ↔ (C + A) ≤ (C + B)))
 
Theoremlesub1t 4352 Subtraction from both sides of 'less than or equal to'.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → (AB ↔ (AC) ≤ (BC)))
 
Theoremltsubaddt 4353 'Less than' relationship between subtraction and addition.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → ((AB) < CA < (C + B)))
 
Theoremltsubadd2t 4354 'Less than' relationship between subtraction and addition.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → ((AB) < CA < (B + C)))
 
Theoremlesubaddt 4355 'Less than or equal to' relationship between subtraction and addition.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → ((AB) ≤ CA ≤ (C + B)))
 
Theoremlesubadd2t 4356 'Less than or equal to' relationship between subtraction and addition.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → ((AB) ≤ CA ≤ (B + C)))
 
Theoremltaddsubt 4357 'Less than' relationship between subtraction and addition.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → ((A + B) < CA < (CB)))
 
Theoremltaddsub2t 4358 'Less than' relationship between subtraction and addition.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → ((A + B) < CB < (CA)))
 
Theoremltsub23t 4359 'Less than' relationship between subtraction and addition.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → ((AB) < C ↔ (AC) < B))
 
Theoremltsub13t 4360 'Less than' relationship between subtraction and addition.
((A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ) → (A < (BC) ↔ C < (BA)))
 
Theoremlt2addt 4361 Adding both sides of two 'less than' relations. Theorem I.25 of [Apostol] p. 20.
(((A ∈ ℝ ∧ B ∈ ℝ) ∧ (C ∈ ℝ ∧ D ∈ ℝ)) → ((A < CB < D) → (A + B) < (C + D)))
 
Theoremaddge0t 4362 Addition of 2 nonnegative numbers is nonnegative.
((A ∈ ℝ ∧ B ∈ ℝ) → ((0 ≤ A ∧ 0 ≤ B) → 0 ≤ (A + B)))
 
Theoremltaddpost 4363 Adding a positive number to another number increases it.
((A ∈ ℝ ∧ B ∈ ℝ) → (0 < AB < (B + A)))
 
Theoremltsubpost 4364 Subtracting a positive number from another number decreases it.
((A ∈ ℝ ∧ B ∈ ℝ) → (0 < A ↔ (BA) < B))
 
Theoremposdift 4365 Comparison of two numbers whose difference is positive.
((A ∈ ℝ ∧ B ∈ ℝ) → (A < B ↔ 0 < (BA)))
 
Theoremltnegt 4366 Negative of both sides of 'less than'. Theorem I.23 of [Apostol] p. 20.
((A ∈ ℝ ∧ B ∈ ℝ) → (A < B ↔ -B < -A))
 
Theoremltnegcon1t 4367 Contraposition of negative in 'less than'.
((A ∈ ℝ ∧ B ∈ ℝ) → (-A < B ↔ -B < A))
 
Theoremlenegt 4368 Negative of both sides of 'less than or equal to'.
((A ∈ ℝ ∧ B ∈ ℝ) → (AB ↔ -B ≤ -A))
 
Theoremlenegcon1t 4369 Contraposition of negative in 'less than or equal to'.
((A ∈ ℝ ∧ B ∈ ℝ) → (-AB ↔ -BA))
 
Theoremlt0neg1t 4370 Comparison of a number and its negative to zero. Theorem I.23 of [Apostol] p. 20.
(A ∈ ℝ → (A < 0 ↔ 0 < -A))
 
Theoremlt0neg2t 4371 Comparison of a number and its negative to zero.
(A ∈ ℝ → (0 < A ↔ -A < 0))
 
Theoremle0neg1t 4372 Comparison of a number and its negative to zero.
(A ∈ ℝ → (A ≤ 0 ↔ 0 ≤ -A))
 
Theoremle0neg2t 4373 Comparison of a number and its negative to zero.
(A ∈ ℝ → (0 ≤ A ↔ -A ≤ 0))
 
Theoremlesub0t 4374 Lemma to show a nonnegative number is zero.
((A ∈ ℝ ∧ B ∈ ℝ) → ((0 ≤ AB ≤ (BA)) ↔ A = 0))
 
Theoremmulge0t 4375 The product of two nonnegative numbers is nonnegative.
((A ∈ ℝ ∧ B ∈ ℝ) → ((0 ≤ A ∧ 0 ≤ B) → 0 ≤ (A · B)))
 
Theoremltsqt 4376 A non-zero square is positive. Theorem I.20 of [Apostol] p. 20.
(A ∈ ℝ → (¬ A = 0 → 0 < (A · A)))
 
Theoremlt01 4377 0 is less than 1. Theorem I.21 of [Apostol] p. 20.
0 < 1
 
Theoremeqneg 4378 A number equal to its negative is zero.
A ∈ ℂ    ⇒   (A = -AA = 0)
 
Theoremnegne0 4379 A number is non-zero iff its negative is non-zero.
A ∈ ℂ    ⇒   (A ≠ 0 ↔ -A ≠ 0)
 
Theoremnegn0 4380 The negative of a non-zero number is non-zero.
A ∈ ℂ    &   A ≠ 0    ⇒   -A ≠ 0
 
Theoremelimgt0 4381 Hypothesis for weak deduction theorem to eliminate 0 < A.
0 < if(0 < A, A, 1)
 
Theoremelimge0 4382 Hypothesis for weak deduction theorem to eliminate 0 ≤ A.
0 ≤ if(0 ≤ A, A, 0)
 
Theoremltplus1t 4383 A number is less than itself plus 1.
(A ∈ ℝ → A < (A + 1))
 
Theoremltplus1 4384 A number is less than itself plus 1.
A ∈ ℝ    ⇒   A < (A + 1)
 
Theoremrecgt0i 4385 The reciprocal of a positive number is positive. Exercise 4 of [Apostol] p. 21.
A ∈ ℝ    &   0 < A    ⇒   0 < (1 / A)
 
Theoremrecgt0 4386 The reciprocal of a positive number is positive. Exercise 4 of [Apostol] p. 21.
A ∈ ℝ    ⇒   (0 < A → 0 < (1 / A))
 
Theoremprodgt0i 4387 If a number and its product are positive, so is the multiplier.
A ∈ ℝ    &   B ∈ ℝ    &   0 < A    ⇒   (0 < (A · B) → 0 < B)
 
Theoremprodgt0 4388 If a number and its product are positive, so is the multiplier.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 < A ∧ 0 < (A · B)) → 0 < B)
 
Theoremdivgt0lem 4389 The ratio of two positive numbers is positive.
A ∈ ℝ    &   B ∈ ℝ    &   0 < B    ⇒   (0 < A → 0 < (A / B))
 
Theoremdivgt0 4390 The ratio of two positive numbers is positive.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 < A ∧ 0 < B) → 0 < (A / B))
 
Theoremdivgt0i 4391 The ratio of two positive numbers is positive.
A ∈ ℝ    &   B ∈ ℝ    &   0 < A    &   0 < B    ⇒   0 < (A / B)
 
Theoremdivge0 4392 The ratio of nonnegative and positive numbers is nonnegative.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ∧ 0 < B) → 0 ≤ (A / B))
 
Theoremltmul1i 4393 Multiplication of both sides of 'less than' by a positive number. Theorem I.19 of [Apostol] p. 20.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    &   0 < C    ⇒   (A < B ↔ (A · C) < (B · C))
 
Theoremltmul1 4394 Multiplication of both sides of 'less than' by a positive number. Theorem I.19 of [Apostol] p. 20.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   (0 < C → (A < B ↔ (A · C) < (B · C)))
 
Theoremltmul2 4395 Multiplication of both sides of 'less than' by a positive number. Theorem I.19 of [Apostol] p. 20.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   (0 < C → (A < B ↔ (C · A) < (C · B)))
 
Theoremlemul2 4396 Multiplication of both sides of 'less than or equal to' by a positive number.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   (0 < C → (AB ↔ (C · A) ≤ (C · B)))
 
Theoremlemul1 4397 Multiplication of both sides of 'less than or equal to' by a positive number.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   (0 < C → (AB ↔ (A · C) ≤ (B · C)))
 
Theoremltdivi 4398 Division of both sides of 'less than' by a positive number.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    &   0 < C    ⇒   (A < B ↔ (A / C) < (B / C))
 
Theoremltdiv 4399 Division of both sides of 'less than' by a positive number.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   (0 < C → (A < B ↔ (A / C) < (B / C)))
 
Theoremltmuldiv 4400 'Less than' relationship between division and multiplication.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    ⇒   (0 < C → ((A · C) < BA < (B / C)))

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