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Statement List for Metamath Proof Explorer - 4701-4800 - Page 48 of 58
TypeLabelDescription
Statement
 
Theoremle2sqe 4701 Two nonnegative reals compare the same as their squares.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ∧ 0 ≤ B) → (AB ↔ (A↑2) ≤ (B↑2)))
 
Theoremsqe11 4702 The square function is one-to-one for nonnegative reals.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ∧ 0 ≤ B) → ((A↑2) = (B↑2) ↔ A = B))
 
Theoremsqegt0 4703 The square of a non-zero real is positive.
A ∈ ℝ    ⇒   (A ≠ 0 → 0 < (A↑2))
 
Theoremsqege0 4704 A square of a real is nonnegative.
A ∈ ℝ    ⇒   0 ≤ (A↑2)
 
Theoremsqe11t 4705 The square function is one-to-one for nonnegative reals.
((A ∈ ℝ ∧ B ∈ ℝ) → ((0 ≤ A ∧ 0 ≤ B) → ((A↑2) = (B↑2) ↔ A = B)))
 
Theoremlt2sqet 4706 Two nonnegative numbers compare the same as their squares.
((A ∈ ℝ ∧ B ∈ ℝ) → ((0 ≤ A ∧ 0 ≤ B) → (A < B ↔ (A↑2) < (B↑2))))
 
Theoremle2sqet 4707 Two nonnegative numbers compare the same as their squares.
((A ∈ ℝ ∧ B ∈ ℝ) → ((0 ≤ A ∧ 0 ≤ B) → (AB ↔ (A↑2) ≤ (B↑2))))
 
Theoremsqege0t 4708 A square of a real is nonnegative.
(A ∈ ℝ → 0 ≤ (A↑2))
 
Theoremsq1 4709 The square of 1 is 1.
(1↑2) = 1
 
Theoremsq2 4710 The square of 2 is 4.
(2↑2) = 4
 
Theoremcu2 4711 The cube of 2 is 8.
(2↑3) = 8
 
Theorembinom 4712 Binomial expansion.
A ∈ ℂ    &   B ∈ ℂ    ⇒   ((A + B)↑2) = (((A↑2) + (2 · (A · B))) + (B↑2))
 
Theoremdiscrlem1 4713 Lemma for discriminant theorem.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    &   D = -(B / (2 · A))    &   0 < A    ⇒   (0 ≤ (((A · (D↑2)) + (B · D)) + C) ↔ ((B↑2) − (4 · (A · C))) ≤ 0)
 
Theoremdiscrlem2 4714 Lemma for discriminant theorem.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    &   D = -(B / (2 · A))    &   (D ∈ ℝ → 0 ≤ (((A · (D↑2)) + (B · D)) + C))    ⇒   (0 < A → ((B↑2) − (4 · (A · C))) ≤ 0)
 
Theoremdiscrlem3 4715 Lemma for discriminant theorem.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    &   D = ((C + 1) / -B)    &   (D ∈ ℝ → 0 ≤ (((A · (D↑2)) + (B · D)) + C))    ⇒   (0 = A → ((B↑2) − (4 · (A · C))) ≤ 0)
 
Theoremdiscrlem 4716 If a quadratic polynomial (with a nonnegative high-order coefficient) is nonnegative for all values, then its discriminant is non-positive.
A ∈ ℝ    &   B ∈ ℝ    &   C ∈ ℝ    &   x ∈ ℝ 0 ≤ (((A · (x↑2)) + (B · x)) + C)    ⇒   (0 ≤ A → ((B↑2) − (4 · (A · C))) ≤ 0)
 
Theoremnnsqcl 4717 The square of a natural number is a natural number.
A ∈ ℕ    ⇒   (A↑2) ∈ ℕ
 
Theoremnnlesq 4718 A natural number is less than or equal to its square.
A ∈ ℕ    ⇒   A ≤ (A↑2)
 
Theoremnneo 4719 A natural number is even or odd but not both.
A ∈ ℕ    ⇒   ((A / 2) ∈ ℕ ↔ ¬ ((A + 1) / 2) ∈ ℕ)
 
Theoremnnesq 4720 A natural number is even iff its square is even.
A ∈ ℕ    ⇒   ((A / 2) ∈ ℕ ↔ ((A↑2) / 2) ∈ ℕ)
 
Theoremnn0le2sqet 4721 Two nonnegative integers compare the same as their squares. (Contributed by Raph Levien, 10-Dec-02.)
A ∈ ℕ0    &   B ∈ ℕ0    ⇒   (AB ↔ (A · A) ≤ (B · B))
 
Theoremnn0opthlem1 4722 A rather pretty lemma for nn0opth 4724. (Contributed by Raph Levien, 10-Dec-02.)
A ∈ ℕ0    &   C ∈ ℕ0    ⇒   (A < C ↔ ((A · A) + (2 · A)) < (C · C))
 
Theoremnn0opthlem2 4723 Lemma for nn0opth 4724. (Contributed by Raph Levien, 10-Dec-02.)
A ∈ ℕ0    &   B ∈ ℕ0    &   C ∈ ℕ0    &   D ∈ ℕ0    ⇒   ((BADC) → (A < C → ¬ ((A · A) + B) = ((C · C) + D)))
 
Theoremnn0opth 4724 An ordered pair theorem for nonnegative integers. Theorem 17.3 of [Quine] p. 124. We can represent an ordered pair of nonnegative integers A and B by (((A + B) · (A + B)) + B). If two such ordered pairs are equal, their first elements are equal and their second elements are equal. Contrast this ordered pair representation with the standard one df-op 1815 that works for any set. (Contributed by Raph Levien, 10-Dec-02.)
A ∈ ℕ0    &   B ∈ ℕ0    &   C ∈ ℕ0    &   D ∈ ℕ0    ⇒   ((((A + B) · (A + B)) + B) = (((C + D) · (C + D)) + D) ↔ (A = CB = D))
 
Theoremnn0opth2 4725 An ordered pair theorem for nonnegative integers. Theorem 17.3 of [Quine] p. 124. See nn0opth 4724.
A ∈ ℕ0    &   B ∈ ℕ0    &   C ∈ ℕ0    &   D ∈ ℕ0    ⇒   ((((A + B)↑2) + B) = (((C + D)↑2) + D) ↔ (A = CB = D))
 
Theoremnn0opth2t 4726 An ordered pair theorem for nonnegative integers. Theorem 17.3 of [Quine] p. 124. See nn0opth 4724.
(((A ∈ ℕ0B ∈ ℕ0) ∧ (C ∈ ℕ0D ∈ ℕ0)) → ((((A + B)↑2) + B) = (((C + D)↑2) + D) ↔ (A = CB = D)))
 
Syntaxcsqr 4727 Extend class notation to include positive square root of a positive real number.
class
 
Definitiondf-sqr 4728 Define a function whose value is the square root of a nonnegative real number. The square root of x is the supremum of all reals whose square is less than x. See sqrcl 4758 for its closure, sqrval 4729 for its value, sqrsqe 4774 and sqsqr 4775 for its relationship to squares, and sqr11 4761 for uniqueness.
√ = {⟨x, y⟩∣((x ∈ ℝ ∧ 0 ≤ x) ∧ y = sup({z ∈ ℝ∣(0 ≤ z ∧ (z · z) ≤ x)}, ℝ, < ))}
 
Theoremsqrval 4729 Value of square root function.
((A ∈ ℝ ∧ 0 ≤ A) → (√ ‘A) = sup({x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}, ℝ, < ))
 
Theoremsqr0 4730 Square root of zero.
(√ ‘0) = 0
 
Theoremsqrlem1 4731 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    ⇒   A < ((1 + A) · (1 + A))
 
Theoremsqrlem2 4732 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    ⇒   ((A / (1 + A)) · (A / (1 + A))) < A
 
Theoremsqrlem3 4733 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    ⇒   0 < (A / (1 + A))
 
Theoremsqrlem4 4734 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    ⇒   (DS ↔ (D ∈ ℝ ∧ (0 ≤ D ∧ (D · D) ≤ A)))
 
Theoremsqrlem5 4735 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    ⇒   ((D ∈ ℝ ∧ (0 < D ∧ (D · D) < A)) → DS)
 
Theoremsqrlem6 4736 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    ⇒   (S ⊆ ℝ ∧ S ≠ ∅ ∧ ∃x ∈ ℝ ∀yS y < x)
 
Theoremsqrlem7 4737 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    &   B = sup(S, ℝ, < )    ⇒   B ∈ ℝ
 
Theoremsqrlem8 4738 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    &   B = sup(S, ℝ, < )    ⇒   0 < B
 
Theoremsqrlem9 4739 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   C ∈ ℝ    &   0 < B    &   A < (B · B)    &   C = ((B + (A / B)) / (1 + 1))    ⇒   0 < C
 
Theoremsqrlem10 4740 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   C ∈ ℝ    &   0 < B    &   A < (B · B)    &   C = ((B + (A / B)) / (1 + 1))    ⇒   C < B
 
Theoremsqrlem11 4741 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   C ∈ ℝ    &   0 < B    &   A < (B · B)    &   C = ((B + (A / B)) / (1 + 1))    ⇒   A < (C · C)
 
Theoremsqrlem12 4742 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   C ∈ ℝ    &   0 < B    &   A < (B · B)    &   C = ((B + (A / B)) / (1 + 1))    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    ⇒   (DSD < C)
 
Theoremsqrlem13 4743 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   C ∈ ℝ    &   0 < B    &   A < (B · B)    &   C = ((B + (A / B)) / (1 + 1))    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    ⇒   (B = sup(S, ℝ, < ) → ¬ C < B)
 
Theoremsqrlem14 4744 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   C ∈ ℝ    &   0 < B    &   A < (B · B)    &   C = ((B + (A / B)) / (1 + 1))    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    ⇒    ¬ B = sup(S, ℝ, < )
 
Theoremsqrlem15 4745 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   0 < B    &   C ∈ ℝ    &   0 < C    ⇒   B < (B + C)
 
Theoremsqrlem16 4746 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   0 < B    &   C ∈ ℝ    &   0 < C    &   C < B    ⇒   (C < ((A − (B · B)) / (((1 + 1) + 1) · B)) → ((B + C) · (B + C)) < A)
 
Theoremsqrlem17 4747 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   0 < B    &   C ∈ ℝ    &   0 < C    &   C < B    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    ⇒   (C < ((A − (B · B)) / (((1 + 1) + 1) · B)) → (B + C) ∈ S)
 
Theoremsqrlem18 4748 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   0 < B    &   C ∈ ℝ    &   0 < C    &   C < B    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    ⇒   (C < ((A − (B · B)) / (((1 + 1) + 1) · B)) → ¬ B = sup(S, ℝ, < ))
 
Theoremsqrlem19 4749 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   0 < B    &   (B · B) < A    ⇒   0 < ((A − (B · B)) / (((1 + 1) + 1) · B))
 
Theoremsqrlem20 4750 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   B ∈ ℝ    &   0 < B    &   (B · B) < A    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    ⇒    ¬ B = sup(S, ℝ, < )
 
Theoremsqrlem21 4751 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    &   B = sup(S, ℝ, < )    ⇒    ¬ A < (B · B)
 
Theoremsqrlem22 4752 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    &   B = sup(S, ℝ, < )    ⇒    ¬ (B · B) < A
 
Theoremsqrlem23 4753 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    &   S = {x ∈ ℝ∣(0 ≤ x ∧ (x · x) ≤ A)}    &   B = sup(S, ℝ, < )    ⇒   (B · B) = A
 
Theoremsqrlem24 4754 Lemma for square root closure.
A ∈ ℝ    &   0 < A    ⇒   (√ ‘A) ∈ ℝ
 
Theoremsqrgt0i 4755 The square root of a positive real is positive.
A ∈ ℝ    &   0 < A    ⇒   0 < (√ ‘A)
 
Theoremsqrlem26 4756 Lemma for square root theorem.
A ∈ ℝ    &   0 < A    ⇒   ((√ ‘A) · (√ ‘A)) = A
 
Theoremsqrth 4757 Square root theorem. Theorem I.35 of [Apostol] p. 29.
A ∈ ℝ    ⇒   (0 ≤ A → ((√ ‘A) · (√ ‘A)) = A)
 
Theoremsqrcl 4758 The square root of a nonnegative real is a real.
A ∈ ℝ    ⇒   (0 ≤ A → (√ ‘A) ∈ ℝ)
 
Theoremsqrgt0 4759 The square root of a positive real is positive.
A ∈ ℝ    ⇒   (0 < A → 0 < (√ ‘A))
 
Theoremsqrge0 4760 The square root of a nonnegative real is nonnegative.
A ∈ ℝ    ⇒   (0 ≤ A → 0 ≤ (√ ‘A))
 
Theoremsqr11 4761 The square root function is one-to-one.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ∧ 0 ≤ B) → ((√ ‘A) = (√ ‘B) ↔ A = B))
 
Theoremsqrmuli 4762 Square root distributes over multiplication.
A ∈ ℝ    &   B ∈ ℝ    &   0 ≤ A    &   0 ≤ B    ⇒   (√ ‘(A · B)) = ((√ ‘A) · (√ ‘B))
 
Theoremsqrmul 4763 Square root distributes over multiplication.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ∧ 0 ≤ B) → (√ ‘(A · B)) = ((√ ‘A) · (√ ‘B)))
 
Theoremsqrsq 4764 Relationship between square root and squares.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ∧ 0 ≤ B) → ((√ ‘A) = BA = (B · B)))
 
Theoremsqrle 4765 Square root is monotonic.
A ∈ ℝ    &   B ∈ ℝ    ⇒   ((0 ≤ A ∧ 0 ≤ B) → (AB ↔ (√ ‘A) ≤ (√ ‘B)))
 
Theoremsqrsqid 4766 Square root of square.
A ∈ ℝ    ⇒   (0 ≤ A → (√ ‘(A · A)) = A)
 
Theoremsqrclt 4767 The square root of a nonnegative real is a real.
((A ∈ ℝ ∧ 0 ≤ A) → (√ ‘A) ∈ ℝ)
 
Theoremsqrgt0t 4768 The square root of a positive real is positive.
((A ∈ ℝ ∧ 0 < A) → 0 < (√ ‘A))
 
Theoremsqrge0t 4769 The square root of a nonnegative real is nonnegative.
((A ∈ ℝ ∧ 0 ≤ A) → 0 ≤ (√ ‘A))
 
Theoremsqr00t 4770 A square root is zero iff its argument is 0.
((A ∈ ℝ ∧ 0 ≤ A) → ((√ ‘A) = 0 ↔ A = 0))
 
Theoremsqr1 4771 The square root of 1 is 1.
(√ ‘1) = 1
 
Theoremsqr4 4772 The square root of 4 is 2.
(√ ‘4) = 2
 
Theoremsqr9 4773 The square root of 9 is 3.
(√ ‘9) = 3
 
Theoremsqrsqe 4774 Square root of square.
A ∈ ℝ    ⇒   (0 ≤ A → (√ ‘(A↑2)) = A)
 
Theoremsqsqr 4775 Square of square root.
A ∈ ℝ    ⇒   (0 ≤ A → ((√ ‘A)↑2) = A)
 
Theoremsqsqrt 4776 Square of square root.
((A ∈ ℝ ∧ 0 ≤ A) → ((√ ‘A)↑2) = A)
 
Theoremsqr2irrlem1 4777 Lemma for irrationality of square root of 2. Technical lemma used to simplify the main induction step.
A ∈ ℕ    &   B ∈ ℕ    ⇒   ((A↑2) = (2 · (B↑2)) → ((B < A ∧ (A / 2) ∈ ℕ) ∧ (B↑2) = (2 · ((A / 2)↑2))))
 
Theoremsqr2irrlem2 4778 Lemma for irrationality of square root of 2. Eliminates hypotheses with weak deduction theorem.
((A ∈ ℕ ∧ B ∈ ℕ) → ((A↑2) = (2 · (B↑2)) → ((B < A ∧ (A / 2) ∈ ℕ) ∧ (B↑2) = (2 · ((A / 2)↑2)))))
 
Theoremsqr2irrlem3 4779 Main theorem for irrationality of square root of 2. There are no natural numbers such that the square of one is twice the square of the other. Uses strong induction.
¬ ∃x ∈ ℕ ∃y ∈ ℕ (x↑2) = (2 · (y↑2))
 
Theoremsqr2irrlem4 4780 Lemma for irrationality of square root of 2.
A ∈ ℕ    &   B ∈ ℕ    ⇒   ((√ ‘2) = (A / B) ↔ (A↑2) = (2 · (B↑2)))
 
Theoremsqr2irrlem5 4781 Lemma for irrationality of square root of 2. Eliminates hypotheses with weak deduction theorem.
((A ∈ ℕ ∧ B ∈ ℕ) → ((√ ‘2) = (A / B) ↔ (A↑2) = (2 · (B↑2))))
 
Theoremsqr2irr 4782 The square root of 2 is irrational.
(√ ‘2) ∉ ℚ
 
Theoremsqr2re 4783 The square root of 2 exists and is a real number.
(√ ‘2) ∈ ℝ
 
Theoremnthruc 4784 The sequence ℕ, ℤ, ℚ, ℝ, and ℂ forms a chain of proper subsets. In each case the proper subset relationship is shown by demonstrating a number that belongs to one set but not the other. We show that zero belongs to ℤ but not ℕ, one-half belongs to ℚ but not ℤ, the square root of 2 belongs to ℝ but not ℚ, and finally that the imaginary number i belongs to ℂ but not ℝ. See nthruz 4785 for a further refinement.
((ℕ ⊂ ℤ ∧ ℤ ⊂ ℚ) ∧ (ℚ ⊂ ℝ ∧ ℝ ⊂ ℂ))
 
Theoremnthruz 4785 The sequence ℕ, ℕ0, and ℤ forms a chain of proper subsets. In each case the proper subset relationship is shown by demonstrating a number that belongs to one set but not the other. We show that zero belongs to ℕ0 but not ℕ and minus one belongs to ℤ but not ℕ0. This theorem refines the chain of proper subsets nthruc 4784.
(ℕ ⊂ ℕ0 ∧ ℕ0 ⊂ ℤ)
 
Syntaxcre 4786 Extend class notation to include real part of a complex number.
class
 
Syntaxcim 4787 Extend class notation to include imaginary part of a complex number.
class
 
Syntaxccj 4788 Extend class notation to include complex conjugate function.
class
 
Syntaxcabs 4789 Extend class notation to include a function for the absolute value (modulus) of a complex number.
class abs
 
Definitiondf-re 4790 Define a function whose value is the real part of a complex number. See revalt 4794 for its value, recl 4802 for its closure, and replimt 4798 for its use in decomposing a complex number.
ℜ = {⟨x, y⟩∣(x ∈ ℂ ∧ y = {z ∈ ℝ∣∃w ∈ ℝ x = (z + (w · i))})}
 
Definitiondf-im 4791 Define a function whose value is the imaginary part of a complex number. See imvalt 4795 for its value, imcl 4803 for its closure, and replimt 4798 for its use in decomposing a complex number.
ℑ = {⟨x, y⟩∣(x ∈ ℂ ∧ y = {w ∈ ℝ∣∃z ∈ ℝ x = (z + (w · i))})}
 
Definitiondf-cj 4792 Define the complex conjugate function. See cjcl 4804 for its closure and cjvalt 4799 for its value.
∗ = {⟨x, y⟩∣(x ∈ ℂ ∧ y = ((ℜ ‘x) − ((ℑ ‘x) · i)))}
 
Definitiondf-abs 4793 Define the function for the absolute value (modulus) of a complex number. See abscl 4840 for its closure and absvalt 4801 or absval2 4836 for its value.
abs = {⟨x, y⟩∣(x ∈ ℂ ∧ y = (√ ‘(x · (∗ ‘x))))}
 
Theoremrevalt 4794 The value of the real part of a complex number.
(A ∈ ℂ → (ℜ ‘A) = {x ∈ ℝ∣∃y ∈ ℝ A = (x + (y · i))})
 
Theoremimvalt 4795 The value of the imaginary part of a complex number.
(A ∈ ℂ → (ℑ ‘A) = {y ∈ ℝ∣∃x ∈ ℝ A = (x + (y · i))})
 
Theoremreclt 4796 The real part of a complex number is real.
(A ∈ ℂ → (ℜ ‘A) ∈ ℝ)
 
Theoremimclt 4797 The imaginary part of a complex number is real.
(A ∈ ℂ → (ℑ ‘A) ∈ ℝ)
 
Theoremreplimt 4798 Construct a complex number from its real and imaginary parts.
(A ∈ ℂ → A = ((ℜ ‘A) + ((ℑ ‘A) · i)))
 
Theoremcjvalt 4799 Value of the conjugate of a complex number. The value is the real part minus i times the imaginary part. Definition 10-3.2 of [Gleason] p. 132.
(A ∈ ℂ → (∗ ‘A) = ((ℜ ‘A) − ((ℑ ‘A) · i)))
 
Theoremcjclt 4800 The conjugate of a complex number is a complex number (closure law).
(A ∈ ℂ → (∗ ‘A) ∈ ℂ)

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